Answer: 3
Explanation:
Calculate the pH and the equilibrium concentration of S²- in a 6.89x10-2 M hydrosulfuric acid solution, H₂S (aq). For H₂S, Ka1 = 1.0x10-7 and Ka_2 = 1.0×10-1⁹ pH = [S²] = M
Therefore, the pH and the equilibrium concentration of S²⁻ in a 6.89x10⁻² M hydrosulfuric acid solution are pH = 7.78 and [S²⁻] = 2.31x10⁻¹¹ M.
Hydrosulfuric acid (H₂S) is a weak acid that dissociates in water to produce hydrogen ions (H⁺) and bisulfide ions (HS⁻). H₂S(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HS⁻(aq)
The bisulfide ions (HS⁻) in turn reacts with water to produce hydronium ions (H₃O⁺) and sulfide ions (S²⁻).
HS⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + S²⁻(aq) Ka1
= 1.0x10⁻⁷,
Ka2 = 1.0x10⁻¹⁹
To calculate the pH and the equilibrium concentration of S²⁻ in a 6.89x10⁻² M H₂S(aq) solution, we must first determine if H₂S(aq) is a strong or weak acid.
It has Ka1 = 1.0x10⁻⁷, which is a very small value; thus, we can conclude that H₂S(aq) is a weak acid.
To calculate the equilibrium concentration of S²⁻ in a 6.89x10⁻² M H₂S(aq) solution, we need to use the Ka2 value (Ka2 = 1.0x10⁻¹⁹) and a chemical equilibrium table.
[H₂S] = 6.89x10⁻² M[H₃O⁺] [HS⁻] [S²⁻]
Initial 0 0 0Change -x +x +x
Equilibrium (6.89x10⁻² - x) x xKa2 = [H₃O⁺][S²⁻]/[HS⁻]1.0x10⁻¹⁹
= x² / (6.89x10⁻² - x)
Simplifying: 1.0x10⁻¹⁹ = x² / (6.89x10⁻²)
Thus: x = √[(1.0x10⁻¹⁹)(6.89x10⁻²)]
x = 2.31x10⁻¹¹ M
Thus, [S²⁻] = 2.31x10⁻¹¹ M
To calculate the pH of the solution, we can use the Ka1 value and the following chemical equilibrium table.
[H₂S] = 6.89x10⁻² M[H₃O⁺] [HS⁻] [S²⁻]
Initial 0 0 0
Change -x +x +x
Equilibrium (6.89x10⁻² - x) x x
Ka1 = [H₃O⁺][HS⁻]/[H₂S]1.0x10⁻⁷
= x(6.89x10⁻² - x) / (6.89x10⁻²)
Simplifying: 1.0x10⁻⁷ = x(6.89x10⁻² - x) / (6.89x10⁻²)
Thus: x = 1.66x10⁻⁸ M[H₃O⁺]
= 1.66x10⁻⁸ M
Then, pH = -log[H₃O⁺]
= -log(1.66x10⁻⁸)
= 7.78 (rounded to two decimal places)
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It is a mixture that consists of a liquid solvent and dissolved solute.
Answer:
A solution is a homogeneous mixture consisting of a solute dissolved into a solvent . ... The solute is the substance that is being dissolved, while the solvent is the dissolving medium. Solutions can be formed with many different types and forms of solutes and solvents.
Answer:
A solution is a homogeneous mixture consisting of a solute dissolved into a solvent .
Explanation:
En condiciones normales 1g de aire ocupa un volumen de 773 mL ¿ qué volumen ocupará la misma masa de aire a 0 ºC y la presión a 93,3 KPa *
Answer:
El volumen que ocupará la misma masa de aire es 839.49 mL.
Explanation:
Las condiciones normales de presión y temperatura (abreviado CNPT) o presión y temperatura normales (abreviado PTN o TPN), son términos que implican que la temperatura referenciada es de 0ºC (273,15 K) y la presión de 1 atm (definida como 101.325 Pa).
La ley de Boyle dice que “El volumen ocupado por una determinada masa gaseosa a temperatura constante, es inversamente proporcional a la presión” y se matemáticamente como
Presión*Volumen=constante
o P*V=k
La ley de Charles es una ley que dice que cuando la cantidad de gas y de presión se mantienen constantes, el cociente que existe entre el volumen y la temperatura siempre tendrán el mismo valor:
\(\frac{V}{T} =k\)
La ley de Gay-Lussac establece que la presión de un volumen fijo de un gas, es directamente proporcional a su temperatura. Se expresa matemáticamente como:
\(\frac{P}{T} =k\)
Combinando estas tres leyes se obtiene:
\(\frac{P*V}{T} =k\)
Siendo un estado inicial 1 y un estado final 2, la expresión anterior queda determinada como:
\(\frac{P1*V1}{T1} =\frac{P2*V2}{T2}\)
En este caso:
P1= 101325 PaV1= 773 mLT1= 273.15 KP2= 93,3 kPa= 93300 PaV2= ?T2= 0°C= 273.15 KReemplazando:
\(\frac{101325 Pa*773 mL}{273,15 K} =\frac{93300 Pa*V2}{273.15 K}\)
y resolviendo obtenes:
\(V2=\frac{273.15 K}{93300 Pa} *\frac{101325 Pa*773 mL}{273,15 K}\)
V2= 839,49 mL
El volumen que ocupará la misma masa de aire es 839.49 mL.
Contact Forces
Definition:
List of contact forces:
1........
2.......
3..
4.
5......
6.
7.....
13. Which are the simplest pure substances that cannot be broken down into any other substances?
Answer:
Elements
Explanation:
Each kind of atom is an element. Elements are pure substances that cannot be broken down into simpler substances by ordinary chemical means.
Answer:
Elements
Explanation:
Elements such as those on the periodic table are unable to be broken down into simpler forms.
Mixtures (both homogenous and heterogenous) are made of multiple elements making it able to be physically broken down back to its original elements.
Compounds are also made up of multiple elements, however it must go through a chemical separation process in order for it to be broken down into its original elements.
Matter is a broad term of any substance. So it could both be a combination or a single element making it incorrect for this question.
The mass In grams of fluorine in a sample of MgF 2 that contains 20.1 grams of magnesium is:A)10.6 grams B)6.4 grams C)42.4 grams D)16.5 grams
1. In order to answer this one and the next one, we will use mass percentage as our guide, since every compound has a mass percentage for each element, and this is found by checking the total mass and the separate masses of each element, for example, MgF2, the mass percentage is 39% for Mg and 61% for F2, this is due to their molar mass, 24g for Mg and 38g for F2
We have 27.1 g of Mg, and this will always correspond for 39% of the total mass of the compound, so we can do the following math:
100% = x
39% = 27.1g
x = 69.5 grams is the total mass of MgF2, now we only have to subtract the value of Mg and then we will have F2
69.5 - 27.1 = 42.4 grams, this is the mass of Fluorine
2. The same step by step from the previous question, 36% of the total mass is Al and 64% is S, but this question has a little difference, now we have the mass of the compound, but the process is very similar
100% = 50.2 grams
64% = x grams
x = 32.1 grams, which can be considered as letter A
How many moles of potassium are contained in 449 g of
potassium?
pls help im so lost
Answer:
449 (g K) / 39.1 (g/mol K) = 11.5 mol K
Explanation:
Potassium has atomic number 39.1
amount of K in 449g sample = 449/39.1 = 11.5 mol
Answer:
\(\boxed {\boxed {\sf 11.5 \ mol \ K}}\)
Explanation:
We are asked to find how many moles of potassium are in 449 grams of potassium.
We will convert grams to moles using the molar mass. This is the mass of 1 mole of a substance. These values are found on the Periodic Table because they are the same as the atomic masses, but the units are grams per mole (g/mol) instead of atomic mass units (amu).
Look up potassium's molar mass.
K: 39.0983 g/molWe will convert using dimensional analysis, so we set up a ratio using the molar mass.
\(\frac { 39.0983 \ g \ K }{ 1 \ mol \ K}\)
We are converting 449 grams of potassium to moles, so we multiply by this value.
\(449 \ g \ K *\frac { 39.0983 \ g \ K }{ 1 \ mol \ K}\)
Flip the ratio. It is still the same value, but the units of grams of potassium cancel.
\(449 \ g \ K *\frac {1 \ mol \ K}{ 39.0983 \ g \ K }\)
\(449 *\frac {1 \ mol \ K}{ 39.0983}\)
\(\frac {449}{ 39.0983} \ mol \ K\)
\(11.48387526 \ mol \ K\)
The original measurement of grams (449) has 3 significant figures, so our answer must have the same. For the number we found, that is the tenths place. The 8 in the hundredth place tells us to round the 4 in the tenths place up to a 5.
\(11.5 \ mol \ K\)
449 grams of potassium contains approximately 11.5 moles of potassium
Does flammability increase the size of the molecule
Answer:
Yes, the size of the mass increases which increases size.
Explanation:
Hope this helps! Have a great day! :)
PLS HELP ME ON MY FINAL MULTIPLE CHOICE
Answer:
The force would decrease
The oxygen in water behaves as though it’s , and the hydrogens behave as though they’re
The oxygen in water behaves as though it’s electronegative, and the hydrogens behave as though they’re electropositive. This is due to the difference in electronegativity between oxygen and hydrogen.
Oxygen is more electronegative than hydrogen, which means that it has a stronger attraction for electrons. As a result, the electrons in a water molecule spend more time around the oxygen atom than they do around the hydrogen atoms.
The oxygen in water is said to be electronegative, while the hydrogens behave as if they're electropositive. This is due to the disparity in electronegativity between the two atoms. Oxygen is more electronegative than hydrogen, implying that it has a stronger attraction for electrons.
Electronegativity is a measure of an atom's ability to attract electrons. It helps to explain why the electrons in a water molecule spend more time around the oxygen atom than they do around the hydrogen atoms.
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using your melting point data, what evidence allows you to conclude that your product is trans-9-(2-phenylethenyl)anthracene?
The evidence that allows you to conclude that your product is trans-9-(2-phenylethenyl) anthracene using melting point data is that it matches the reported melting point range.
Melting point is the temperature at which a solid changes into a liquid. The melting point of a substance is used to characterize it as a physical property. It's critical to the determination of a substance's identity. When heated, a sample is observed to turn into a clear liquid, which is a clear indicator of the melting point. Tips for analyzing melting point data. The melting point is determined by carefully heating the sample in a capillary tube and observing the temperature at which it turns into a clear liquid. When dealing with melting point data, the following guidelines should be followed: Observe the physical state of the sample. Observe the heating rate. Observe the apparatus calibration. Check for impurities in the sample, if any. Apply the range of melting point. Observe the color of the sample in the liquid and solid phases. Observe the time of melting point. Data for melting point.
The range of melting point for trans-9-(2-phenylethenyl) anthracene is from 196 to 199 °C. If the melting point range of your product matches with the reported melting point range, it is safe to assume that your product is trans-9-(2-phenylethenyl)anthracene.
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NOTE: The question given on the portal is incomplete, here's the complete question.
QUESTION: Using your melting point data and thin layer chromatogram, what evidence allows you to conclude that your product is Trans-9-(2-phenylethenyl) anthracene.
We did not do the TLC in lab, but still need to answer the question, but I cant find any info on this compound specifically, please help
when 0.224 g of sodium metal is added to an excess of hydrochloric acid, 2330 j of heat are produced. what is the enthalpy of the reaction as written? 2na(s) 2hcl(aq)⟶2nacl(aq) h2(g)
The enthalpy of the reaction as written is approximately 239,306 J/mol.
To calculate the enthalpy of the reaction, we need to use the heat released (2330 J) and the amount of sodium reacted (0.224 g) to determine the heat released per mole of sodium reacted.
The molar mass of sodium (Na) is 22.99 g/mol.
First, we need to calculate the number of moles of sodium reacted:
Number of moles of Na = Mass of Na / Molar mass of Na
Number of moles of Na = 0.224 g / 22.99 g/mol ≈ 0.00974 mol
Next, we can calculate the enthalpy change (ΔH) per mole of sodium reacted:
ΔH = Heat released / Number of moles of Na
ΔH = 2330 J / 0.00974 mol ≈ 239306 J/mol
Enthalpy (H) is a thermodynamic property that represents the total heat content of a system at constant pressure. It includes the internal energy of the system plus the product of pressure and volume. Enthalpy is often used to describe heat changes in chemical reactions, where the difference in enthalpy between the reactants and products determines whether a reaction is exothermic (releases heat) or endothermic (absorbs heat). Enthalpy is typically measured in joules (J) or kilojoules (kJ).
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The density of aluminum is 2.7 g/ml. What is the volume of 8.1 g?
Answer:
volume= 3
Explanation:
D=m/v
2.7=8.1/v
2.7v=8.1
8.1/2.7= 3
8.1/3= 2.7 which is the density!
Answer:
3 mL
Explanation:
\(V = \frac{8.1 g}{3 mL} = 2.7 g/mL\)
what will be the result of the reaction
(CH3COO)2+redP +Cl2
Answer:
(CH3COO)2 + redP + Cl2 → ClCH2COOH + HCl
Explanation:
This is an example of halogenation of carboxylic acids at alpha carbon atom. In this reaction, red phosphorus and chlorine are treated with carboxylic acids having alpha hydrogen atom followed by hydrolysis to form alpha chloro carboxylic acid.
question shown in picture tysm!!!
Answer:
the answer is the second one.
This chemical equation represents one of the reactions that form acid rain.
Which two options list the bonds that break in the reaction?,
A. The bonds between H and O in H20
B. The bonds between N and O in NO2
C. The bonds between N and O and between Hand O in HNO2
D. The bonds between N and O and between Hand O in HNO3
When sulfur dioxide (SO2) and nitrogen oxides (NOX) are released into the atmosphere and carried by wind and air currents, acid rain is the volcanoes.
Thus, Nitric and sulfuric acids are created when the SO2 and NOX react with water, oxygen, and other substances. Then, before hitting the ground, they combine with water and other substances.
The majority of the SO2 and NOX that contribute to acid rain originates from burning fossil fuels, however a tiny amount comes from natural sources like volcanoes.
Thus, When sulfur dioxide (SO2) and nitrogen oxides (NOX) are released into the atmosphere and carried by wind and air currents, acid rain is the volcanoes.
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Which has the longest bond length for the Cl-O bond?
1. ClO4-
2. ClO3-
3. ClO2-
4. ClO-
Answer:
4 ClO-
Explanation:
Bond length ∝ 1/ Bond order
Bond order of ClO − =1,
Bond order of ClO 2− =1.5,
Bond order of ClO 3− =1.66 ,
Bond order of ClO 4− =1.75.
Thus the order of bond length is
ClO 4− <ClO3− <ClO2−
<ClO −
3. Consider the following equilibrium: When a 0.500 moles of SO₂ and 0.400 moles of O₂ are placed into a 2.00 liter container and allowed to reach equilibrium, the equilibrium [SO,] is to be 0.250M. Calculate the Keq value. 2SO₂ + O₂ = 2SO3 the equals is arrows going left and right
The following equation can be used to determine the equilibrium constant (Keq) for this reaction: Keq is equal to [SO3]2/[SO2][O2].
Since the concentration of SO3 in this situation is 0.250M at equilibrium, the Keq value is calculated as 0.2502 / (0.500 x 0.400) = 0.4.
Given that the Keq value is more than 1, this indicates that the reaction is marginally biassed in favour of the products.
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help! science what usually has the greasiest density 1. plasma 2. liquid 3. gas 4. solid
Answer:soild
Explanation:
Answer:
I think that it is a solid that has the greatest density
Ammonia is produced using the Haber process. A. Write a balanced symbol equation for the reaction and calculate the atom economy for each product. B. Calculate the theoretical yield of ammonia if 27. 3 g of nitrogen was used in the reaction. C. Calculate the percentage yield of the reaction. The actual yield was 29. 9 g. D. Calculate the percentage conversion of hydrogen if you started with 10. 4 g and 2. 8 g could be recovered from the reaction. I need the answer for part b please
The balanced symbol equation for the Haber process, which is the industrial method for producing ammonia, is N2 + 3H2 → 2NH3
A. The Haber process is the industrial method for producing ammonia, and the balanced equation for the reaction is:
N2 + 3H2 → 2NH3
The atom economy for a product is the percentage of the total mass of reactants that becomes the desired product. For ammonia, the atom economy can be calculated as follows:
Molar mass of NH3 = 14.01 + 3(1.01) = 17.04 g/mol
Atom economy of NH3 = (2 mol NH3 x 17.04 g/mol) / [(1 mol N2 x 28.02 g/mol) + (3 mol H2 x 2.02 g/mol)] x 100% = 34.0%
B. To calculate the theoretical yield of ammonia, we need to use the given mass of nitrogen and the stoichiometry of the balanced equation. The molar mass of nitrogen is 28.02 g/mol, so 27.3 g of nitrogen is equal to:
27.3 g / 28.02 g/mol = 0.974 mol N2
According to the balanced equation, 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3. Therefore, the theoretical yield of ammonia is:
Theoretical yield of NH3 = (0.974 mol N2) x (2 mol NH3 / 1 mol N2) x (17.04 g/mol NH3) = 33.1 g NH3
C. The percentage yield of the reaction can be calculated by dividing the actual yield of ammonia by the theoretical yield, and then multiplying by 100%. The actual yield of ammonia is given as 29.9 g:
Percentage yield of NH3 = (29.9 g NH3 / 33.1 g NH3) x 100% = 90.4%
D. The percentage conversion of hydrogen can be calculated by dividing the mass of hydrogen used in the reaction by the mass of hydrogen that would have been used if all of it had been consumed in the reaction. The mass of hydrogen used is 10.4 g, and the mass of hydrogen that would have been used if all of it had been consumed in the reaction is:
1( mol H2 x 2.02 g/mol) x (0.974 mol N2 / 1 mol N2) = 1.98 g H2
Therefore, the percentage conversion of hydrogen is:
Percentage conversion of H2 = (10.4 g H2 / 1.98 g H2) x 100% = 525% (This result is not possible, as the percentage conversion cannot be greater than 100%. It is likely that there was an error in the calculation or in the data provided.)
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giving brainly if correct!
complete the chart above
Answer:
I hate chemistry good luck alice
iallowinn noints are noncoplanar with points \( B, C, F \) and \( G \) ? Select all that apply.
Points A, D, and H are noncoplanar with points B, C, and F.
To determine which points are noncoplanar with points B, C, F, and G, we can follow these steps:
Identify the plane formed by points B, C, and F using the equation of a plane.
Substitute the coordinates of point G into the equation of the plane.
If the equation is satisfied, then point G is coplanar with points B, C, and F.
Otherwise, it is noncoplanar.
Repeat steps 2 and 3 for each of the other points (A, D, E, and H) to determine their coplanarity with B, C, and F.
Points A, D, E, and H that do not satisfy the equation of the plane are noncoplanar with points B, C, and F.
Based on the given options, points A, D, and H are noncoplanar with points B, C, and F.
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Students were asked to select methods to increase the rate of dissolving a solid. Which methods would increase the rate? Select all that may apply.
Select 3 correct answer(s)
1. Increasing the pressure so that a solid dissolves in the solution.
2. Shaking/stirring the mixture causing an increase in the rate of dissolution.
3. Grinding the solute to increase the surface area.
4. Decreasing the pressure so that a solid dissolves in the solution.
5. Increasing the temperature in order to increase molecule collisions.
5. Increasing the temperature to increase molecule collisions.
What factor increases the solubility of a solid in a solution?An increase in the temperature of the solution can increase the solubility of a solid solute. For example, a greater amount of sugar will dissolve in warm water as compared to in cold water. The size of solute particles, stirring of the solution and increasing temperature of the solution are the three factors that can affect the solubility of a solid in a solvent. Increasing the surface area of the solute will also increase the rate of dissolving in a solution as well as increase the temperature of the solvent. Stirring will increase the speed which also increases the rate of dissolving a solid solute in a solution which helps in attaining higher solubility.
So we can conclude that temperature is the factor that increases the solubility of a solid into a solution.
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Answer:
Increase temp
Shaking/ stirring
Grinding
Explanation:
Chatgpt hehehehe
Characteristics of an acid and a base
pH scale: What is it? How is it helpful? Where can you find acids and bases on it?
Indicators: Identify two and tell how to use them and what acids and bases look like in them.
Include TWO examples of an acid and a base.
Explain what neutralization is.
Give an example of a neutral substance.
Answer:
Acids and bases are two types of chemical substances with different characteristics. An acid is a substance that can donate a hydrogen ion, while a base is a substance that can accept a hydrogen ion.
The pH scale is a measurement of how acidic or basic a substance is. It ranges from 0 to 14, with 7 being neutral. Acids have a pH lower than 7, while bases have a pH greater than 7. The pH scale is helpful in identifying the acidity or basicity of a substance, and it can be found in science textbooks or online.
Indicators are substances that change color in the presence of an acid or a base. Two common indicators are litmus paper and phenolphthalein. Litmus paper turns red in the presence of an acid and blue in the presence of a base, while phenolphthalein turns pink in the presence of a base and remains colorless in the presence of an acid.
Examples of acids include lemon juice (citric acid) and vinegar (acetic acid). Examples of bases include baking soda (sodium bicarbonate) and ammonia (NH3).
Neutralization is a chemical reaction between an acid and a base that results in the formation of a neutral substance, such as water and a salt. During neutralization, the acidic and basic properties of the substances cancel each other out, resulting in a neutral solution.
An example of a neutral substance is pure water. When an acid, such as hydrochloric acid (HCl), and a base, such as sodium hydroxide (NaOH), are mixed together in equal amounts, they undergo neutralization to form water and sodium chloride (NaCl).
which of the following buffers has the largest capacity if made in 1.0 l solutions? a) 0.300 mol hcn and 0.200 mol nacn b) 0.100 mol hcn and 0.500 mol nacn c) 0.0200 mol hcn and 0.0200 mol nacn d) 0.500 mol hcn and 0.100 mol nacn
The buffer solution that has the largest capacity if made in 1.0 l is 0.300 mol hcn and 0.200 mol nacn.
So option A is correct.
What is a buffer solution?A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa.
A buffer solution has it's pH changes very little when a small amount of strong acid or base is added to it.
We can conclude that 0.300 mol hcn and 0.200 mol nacn is the buffer solution that has the largest capacity because it has the highest number of moles of both weak and conjugate base.
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PLEASE HELP ME 40 POINTS RIGHT ANSWERS ONLY!!!!! :)
Consider the solubility curve at right. which solid material is a solid solute?
Substance C is a solid solute according to the solubility curve. So option B is correct.
Solubility is the maximum solubility that a solute can have in a 100 g solvent at a specific temperature. Solubility curves are plots of the temperature and the solubility value of a specific solute.
The curve of solubility is a curved line on a graph that indicates the relationship between temperature and solubility for a given substance at different temperatures. The graph of the relationship of solubility to temperature is called the Solubility curve. Most solubility curves are sigmoidal, meaning that the peak solubility occurs at the inflection point.
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4. Manik saw his father watering his garden plants in hot weather. He noticed that
water doesn’t stick to the plant leaves and leaves become dry but looked fresh. He asked
following questions to his teacher
a. Which tissue forms the outer covering of a plant and does it have a protective role
to play?How ?
b. Why does water not stick to the leaves?
Water does not stick to the leaves of the plant owing to the fact that the leaves has a waterproof cuticle.
What tissues protects the leaves?We know that the leaves are the parts of the plant that are involved in photosynthesis. Photosynthesis is the process by which green plants produce their own food in the presence of sunlight and chlorophyll. We know that the leave has an outer protective covering.
The tissue that plays this outer covering of a plant for is the epidermis and its waxy cuticle. It prevents damage to the plant.
Water does not stick to the leaves of the plant owing to the fact that the leaves has a waterproof cuticle.
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You have 2.9 x 10^24 atoms of calcium How many grams do you have?
Answer:
a mole of calcium is 6.02 ×10²³, therefore 2.9 ×10²⁴ will be ~4.82moles,
And since a mole of calcium is 40.1g
4.82 moles will be 4.82 × 40.1
that's =193.28g
A substance has a mass of 10 grams and a volume of 5mL. What is its density?
Answer:
The answer is
2.0 g/mLExplanation:
The density of a substance can be found by using the formula
\(density = \frac{mass}{volume} \)From the question
mass = 10 g
volume = 5 mL
The density of the substance is
\(density = \frac{10}{5} \)
We have the final answer as
2.0 g/mLHope this helps you
A compound is 2. 00% H by mass, 32. 7% S by mass, and 65. 3% O by mass. What is its empirical formula? The final step is to use the mole ratios of the elements to write the empirical formula. The mole ratios of the elements are: mole ratio of H:S:O = 2:1:4 The mole ratios show the ratios of the elements in the compound. Use these ratios to identify the subscripts on each element in the empirical formula. Remember that the subscript 1 is not shown. What is the correct empirical formula for this compound? HSO H2S1O4 H2SO4.
The empirical formula of this compound is \(H_2SO_4\)
Given the following data:
Percentage of H = 2.00%Percentage of S = 32.7%Percentage of O = 65.3%Scientific data:
Molar mass of hydrogen (H) = 1.0 g/mol.Molar mass of sulfur (S) = 32 g/mol.Molar mass of oxygen (O) = 16 g/mol.To determine the empirical formula of this compound:
Note: We would assume that the mass of the compound is 100 grams.
Hence, the mass of its constituent elements are:
Mass of hydrogen (H) = 2.00 gramsMass of sulfur (S) = 32.7 gramsMass of oxygen (O) = 65.3 gramsNext, we would determine the number of moles of each element by using this formula:
\(Number\;of\;moles = \frac{mass}{molar\;mass}\)
For hydrogen (H):
\(Number\;of\;moles = \frac{2.00}{1}\)
Number of moles = 2.0 moles
For sulfur (S):
\(Number\;of\;moles = \frac{32.7}{32}\)
Number of moles = 1.0 moles
For oxygen (O):
\(Number\;of\;moles = \frac{65.3}{16}\)
Number of moles = 4.0 moles
Empirical formula = \(H_2SO_4\)
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