Answer:
The four primary functions of managers are planning, organizing, leading, and controlling. By using the four functions, managers work to increase the efficiency and effectiveness of their employees, processes, projects, and organizations as a whole.
what happens to the boiling point of hydrocarbon compounds when the number of carbon atom increases
A. Decreases
B. Increases
C. Remains the same
D. None of these
I NEED YOUR ANSWER RN GUYSS PLEASEE
What volume of 15.6M NH4OH is needed to make 500.0 mL of 3.00M solution? a) 0.962 L b) 0.00962 L c) 0.026 L d) 0.0962 L
Answer:
d) 0.0962 L
Explanation:
The problem describes a dilution process, meaning that we can solve it by using the following equation:
C₁V₁=C₂V₂Where subscript 1 stands for the volume and concentration of the concentrated solution, and 2 for those of the diluted solution. That means that in this case:
C₁ = 15.6 MV₁ = ?C₂ = 3.00 MV₂ = 500 mLWe input the data:
15.6 M * V₁ = 3.00 M * 500 mLAnd solve for V₁:
V₁ = 96.2 mLFinally we convert 96.2 mL to L:
96.2 mL / 1000 = 0.0962 LThe answer is thus option d).
Propanoic acid fromula
Answer:
C₃H₆O₂
Explanation:
Propionic acid is a colorless liquid with a sharp rancid odor. Produces irritating vapor. (USCG, 1999)
hydrogen cyanide is produced industrially from the reaction of gaseous ammonia, oxygen, and methane: if 5.00 103 kg each of nh3, o2, and ch4 are reacted, what mass of hcn and of h2o will be produced, assuming 100% yield?
Mass of H2O = number of moles of H2O × molar mass of H2O By substituting the calculated values, we can determine the mass of HCN and H2O produced.
To determine the mass of hydrogen cyanide (HCN) and water (H2O) produced from the given reaction of gaseous ammonia (NH3), oxygen (O2), and methane (CH4), we need to consider the stoichiometry of the reaction.
The balanced chemical equation for the reaction is as follows:
2 NH3 + 3 O2 + 2 CH4 → 2 HCN + 6 H2O
From the balanced equation, we can see that 2 moles of ammonia (NH3) react with 3 moles of oxygen (O2) and 2 moles of methane (CH4) to produce 2 moles of hydrogen cyanide (HCN) and 6 moles of water (H2O).
To calculate the mass of HCN and H2O produced, we need to convert the given masses of NH3, O2, and CH4 to moles using their respective molar masses:
Molar mass of NH3 = 17.03 g/mol
Molar mass of O2 = 32.00 g/mol
Molar mass of CH4 = 16.04 g/mol
Number of moles of NH3 = mass of NH3 / molar mass of NH3
Number of moles of O2 = mass of O2 / molar mass of O2
Number of moles of CH4 = mass of CH4 / molar mass of CH4
Once we have the number of moles of each reactant, we can use the stoichiometric coefficients from the balanced equation to determine the number of moles of HCN and H2O produced.
Number of moles of HCN = 2 × min(number of moles of NH3, number of moles of O2, number of moles of CH4)
Number of moles of H2O = 6 × min(number of moles of NH3, number of moles of O2, number of moles of CH4)
Finally, we calculate the mass of HCN and H2O produced using their respective molar masses:
Mass of HCN = number of moles of HCN × molar mass of HCN
Mass of H2O = number of moles of H2O × molar mass of H2O
By substituting the calculated values, we can determine the mass of HCN and H2O produced.
It is worth noting that the 100% yield assumption is ideal, but in reality, reactions may have lower yields due to various factors such as side reactions or incomplete conversions.
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What is the definition for floating
Answer:
"1. buoyant or suspended in water or air.
2.not settled in a definite place; fluctuating or variable."
Explanation:
Hope this helps! :)
FILL IN THE BLANK.natural gas is primarily composed of ________. group of answer choices methane nitrogen sulfur dioxide oxygen nitrite
Natural gas is primarily composed of methane (CH₄), which is a hydrocarbon gas consisting of one carbon atom bonded to four hydrogen atoms.
Methane is the main component of natural gas and typically accounts for the largest percentage of its composition. However, natural gas may also contain small amounts of other hydrocarbons such as ethane, propane, and butane, as well as traces of non-hydrocarbon gases like nitrogen, carbon dioxide, and hydrogen sulfide.
The exact composition of natural gas can vary depending on its source and processing methods. Methane is a clean-burning fuel that is commonly used for heating, cooking, and electricity generation due to its high energy content and lower greenhouse gas emissions compared to other fossil fuels.
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an endothermic animal is warm blooded. This means it can do what
Answer:
Endothermic animals are those that must generate their own heat to maintain an optimal body temperature.
Explanation:
Answer:
There
Explanation:
Endothermic animals are those that must generate their own heat to maintain an optimal body temperature. In ordinary language, these animals are commonly referred to as "warm-blooded." The term endotherm comes from the Greek endon, meaning within, and thermos, which means heat
How many grams of sodium hydroxide are required to prepare a 200 ml solution of a 10% (weight per volume) solution? (Atomic weights: Na = 23; 0 = 16; H = 1)
Given that we want to prepare a 10% solution of sodium hydroxide in 200 mL, we need to calculate the mass of sodium hydroxide required to make this solution.
We can use the following formula to calculate the mass of solute required to make a given volume and concentration of solution:
mass of solute = volume of solution x concentration of solution x density of soluteFirst, let's calculate the density of sodium hydroxide.The density of solid NaOH is 2.13 g/mL. So, the density of sodium hydroxide solution is:
Density = 2.13 g/mLNow, let's substitute the given values into the formula to calculate the mass of sodium hydroxide required:mass of solute = 200 mL x 0.10 x 2.13 g/mL= 4.26 gTherefore, 4.26 grams of sodium hydroxide are required to prepare a 200 mL solution of a 10% (weight per volume) solution.About Sodium hydroxideSodium hydroxide, also known as lye and caustic soda or caustic soda, is an inorganic compound with the chemical formula NaOH. This compound is an ionic compound in the form of a white solid composed of the sodium cation Na⁺ and the hydroxide anion OH⁻. Sodium hydroxide is a building block that can also be found in detergents and oil stain removers. We use it to make products clean better by influencing the formula molecules, so they work better together.
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calculate the mass of lead oxide that decomposes to produce 1.2 dm³ of oxygen measured at room temperature
Explanation:
Please here it is I guess this will help
A balloon is filled with 26L of helium in the morning when the temperature is
17°C. By noon the temperature has risen to 32°C. What is the new volume of
the balloon?
Answer:
V1T1=V2T2
Explanation:
V2=V1T1/T2
The final volume of the gas can be determines using the Charles's law of volume and temperature. The volume of helium when temperature increased to 32 °C increases to 48.9 L.
What is Charles's law ?Charles's law states that, at constant pressure, the volume and temperature of a gas are in direct proportionality. Thus, as the temperature increases, volume of the gas increases.
Hence, V/T = constant
Let V1 and T1 be the initial volume and temperature and V2 and T2 be the final quantities. Then, the relation can be stated as ;
V1/ T1 = V2/ T2
Given that initial quantities:
V1 = 26 L
T1 = 17 °C
Final temperature T2 =32 °C
Then, final volume V2 = V1 T2/T1
V2 = (26 L × 32°C)/ 17 °C = 48.9 L
Therefore, the volume of helium gas increases to 48.9 liters.
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chemistry help please!!
Answer:
no so boring........................
Pls Help ASAP! 2 grams of potassium (K) reacts with 5 grams of Oxygen (O). According to the Law of Conservation of Mass, how many grams of potassium oxide (K2O) will be produced?
O 10 grams
O 7 grams
O 2 grams
O 5 grams
Taking into account the reaction stoichiometry, 2.4041 grams of K₂O can be produced from 2 grams of K and 5 grams of O₂.
Reaction stoichiometryIn first place, the balanced reaction is:
4 K + O₂ → 2 K₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
K: 4 molesO₂: 1 mole K₂O: 2 molesThe molar mass of the compounds is:
K: 39.1 g/moleO₂: 32 g/moleK₂O: 94.2 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
K: 4 moles ×39.1 g/mole= 156.4 gramsO₂: 1 mole ×32 g/mole= 32 gramsK₂O: 2 moles ×94.2 g/mole= 188.4 gramsLimiting reagentThe limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
Limiting reagent in this caseTo determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 32 grams of O₂ reacts with 156.4 grams of K, 5 grams of O₂ reacts with how much mass of K?
mass of K= (156.4 grams of K× 5 grams of O₂)÷ 32 grams of O₂
mass of K= 24.4375 grams
But 24.4375 grams of K are not available, 2 grams are available. Since you have less mass than you need to react with 5 grams of O₂, K will be the limiting reagent.
Mass of K₂O formedConsidering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 156.4 grams of K form 188 grams of K₂O, 2 grams of K form how much mass of K₂O?
mass of K₂O= (2 grams of K× 188 grams of K₂O)÷ 156.4 grams of K
mass of K₂O= 2.4041 grams
Then, 2.4041 grams of K₂O can be produced from 2 grams of K and 5 grams of O₂.
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Answer:
(Question) What does the Law of Conservation of Mass state?
(Answer) The total mass of all of the reactants prior to a chemical reaction must equal the total mass of all the products after the reaction.
(Question) If the mass of elements before a chemical reaction is 30 grams, after the chemical reaction, the mass will be __.
(Answer) 30 grams
(Question) 78 g of potassium (K) react with 71 g of chlorine (Cl) to produce potassium chloride. According to the Law of Conservation of Mass, what is the mass of the product (2KCl)?
(Answer) 149 g
(Question) 2 grams of potassium (K) reacts with 5 grams of Oxygen (O). According to the Law of Conservation of Mass, how many grams of potassium oxide (K2O) will be produced?
(Answer) 7
(Question) Which of the following equations demonstrates the Law of Conservation of Mass?
(Answer) CH4+O2→C+2H2O
Explanation:
just finished the quick check. hope this helps UwU
What molecule is butane
Butane is a gaseous molecule which is part of the organic compounds called hydrocarbon,
What kind of molecule is butane?Butane is a gaseous molecule which is generally called a hydrocarbon.
Hydrocarbons are composed of only carbon and hydrogen. They are of organic origin.
Butane is a low molecular weight hydrocarbon which is used as a fuel.
In conclusion, butane is a gaseous hydrocarbon,
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If you are correct you get a brainless
(07.01 MC)
As a part of the life cycle of plants, the plant must begin with an embryo. What statement best describes where the embryo can be found in flowering and non-flowering plants? (2 points)
12. Which one of the following is not true about the reaction of: CH3-
CH3+C12...CH3CH2CI+HCI?
a it is elimination reaction
b it is photochemical reaction
c it is chlorination reaction
d it is substitution reaction
Explanation:
CH₃CH₃ + Cl₂ → CH₃CH₂Cl + HCl
This reaction take place in the presence of light/UV rays. (i.e, photochemical reaction)It's a Chlorination reaction because here there's addition of chlorine.It's a substitution reaction because Cl substituted H from place and attach there.Option which is NOT correct is
Option A (It's not an elimination reaction)
Therefore,
Option A is correct✔
Why is heterogeneous nucleation favored over homogeneous nucleation?
I found this, hope it helps
Heterogeneous nucleation is favored over homogeneous nucleation because it requires a lower energy barrier for the nucleation process. Heterogeneous nucleation involves the formation of a new phase on the surface of an existing foreign material, while homogeneous nucleation occurs spontaneously within a uniform medium.
Heterogeneous nucleation is favored over homogeneous nucleation because it occurs on surfaces or interfaces that are different from the bulk material, providing a lower energy barrier for nucleation to occur.
In contrast, homogeneous nucleation occurs within the bulk material, where there is a higher energy barrier due to the lack of nucleation sites.
As a result, heterogeneous nucleation is more likely to occur and is typically associated with faster and more efficient crystallization processes.
Homogeneous nucleation, on the other hand, can lead to the formation of unwanted impurities and defects in the material due to the high energy required for nucleation.
The presence of the foreign surface in heterogeneous nucleation reduces the overall energy required, making it more likely to occur compared to homogeneous nucleation.
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When jayden applies the hydrogen peroxide to Chloes dark hair, the melanin pigments in her hair will be
Answer: her hair will be oxidized
Explanation: they hydrogen peroxide works as an oxidizing agent, releasing oxygen into the melanin pigment in the hair.
A 0.589 mol sample of nitrogen gas, N2, has a volume of 1.68L at a pressure of 0.975 atm. Calculate the temperature of the nitrogen gas
The temperature of the nitrogen gas is 33.92 Kelvin
How to solve:
To get the temperature of the nitrogen gas, we will use the ideal gas equation:
PV = nRT
where:
P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. First, let's change the equation to account for temperature:
T = PV/(nR)
Presently, we can connect the given qualities:
The ideal gas constant, R, is 0.0821 L-atm/(mol-K), with P = 0.975 atm and V = 1.68 L and n = 0.589 mol.
Adding the following values to the equation:
T = (0.975 atm * 1.68 L) / (0.589 mol * 0.0821 L atm/(mol K)) T = 1.6332 atm L / (0.04813 L atm/(Kmol))
The nitrogen gas's temperature is 33.92 Kelvin because;
T = 1.6332 / 0.04813 K
T = 33.92 K.
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(100 POINTS) When thermal energy (heat) is added to a reaction, it happens _________ (faster or slower)
When thermal energy (heat) is removed from a reaction, it happens _________ (faster or slower)
Answer:
1) faster
2) slower
Explanation:
Answer:
faster
Explanation:
A compound contains 46% Sodium, 12% Carbon and 42% Oxygen. The molecular mass of the compound is 106 u. Draft a table with these data and find the Empirical formula and Molecular formula of this compound. Given that atomic masses are Na=23 u, C=12u and O=16u.
Answer:
Empirical formula is Na₂CO₃
Molecular formula is Na₂CO₃
Explanation:
Percentage compositions of the elements;
Sodium = 46%
Carbon = 12 %
Oxygen = 42%
To determine empirical formula, we calculate the mole ratio first.
mole ratio = % mass/atomic mass; where the atomic masses of the elements are : Na = 23 u, C = 12 u and O = 16 u.
mole ratio: Na = 46/23; C = 12/12; O = 42/16
mole ratio (Na : C : O) = 2 : 1 : 2.6
approximate mole ratio = 2 : 1 :3
Therefore, empirical formula of compound is Na₂CO₃
To determine the molecular formula;
molecular formula or mass = n(empirical formula or mass)
n = molecular mass/empirical mass
molecular mass = 106 u,
empirical mass = 23*2 + 12 + 16*3 = 106 u
then, n = 106/106 = 1
therefore, molecular formula = 1 * (Na₂CO₃) = Na₂CO₃
In a particular experiment, a 4. 00 g sample of CaO is reacted with excess water and 2. 14 g of Ca(OH)2 is recovered. What is the percent yield in this experiment
\textbf{Question:}
In a particular experiment, a 4.00 g sample of CaO is reacted with excess water, and 2.14 g of Ca(OH)2 is recovered. What is the percent yield in this experiment?
\textbf{Answer:}
The Percent yield in this experiment is 40.5%.
What is the percent yield?
In chemistry, the percentage yield is used to compare a reaction's actual outcome to the maximum anticipated outcome.
The actual yield and the theoretical yield must be compared in order to calculate the percent yield.
Given: \ce{CaO}mass equals 4.00 g
\ce{Ca(OH)2}
recovered mass (actual yield): 2.14 g
The reaction's chemical equation is balanced as follows:
\ce{Ca(OH)2(s)} is created when \ce{CaO(s)} and water combine.
The stoichiometric ratio of \ce{CaO}to \ce{Ca(OH)2} is 1:1, as can be shown from the equation. It follows that 1 mole of \ce{CaO} interacts to become 1 mole of \ce{Ca(OH)2}.
We first compute the amount of moles of \ce{CaO} to be used in the theoretical yield calculation:
Moles of \ce{CaO} = \(\frac{{\text{{Mass of \ce{CaO}}}}}{{\text{{Molar mass of \ce{CaO}}}}}\)
\ce{CaO}'s molecular weight is 40.08 \, \text{g/mol}.
Moles of CaO = \(\frac{{4.00 \, \text{{g}}}}{{40.08 \, \text{{g/mol}}}}\)
Next, we determine the theoretical yield of \ce{Ca(OH)2} in grams:
Theoretical yield = Moles of CaO \times \text{{Molar mass of \ce{Ca(OH)2}}}
The molar mass of \ce{Ca(OH)2} is 74.09 \, \text{g/mol}.
Theoretical yield = Moles of CaO \times 74.09 \, \text{{g/mol}}
Finally, we can calculate the percent yield:
Percent yield = \(\frac{{\text{{Actual yield}}}}{{\text{{Theoretical yield}}}} \times 100\%\)
Percent yield = \(\frac{{2.14 \, \text{{g}}}}{{(\text{{Moles of CaO}}) \times 74.09 \, \text{{g/mol}}}}\) \times 100\%
Hence, the percent yield in this experiment is approximately 40.46\%.
---
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In the Bohr model of the hydrogen atom, the electron moves in a circular orbit of radius 5.3 times 10^-11 m with a speed of 2.2 times 10^6 m/s.
a. If we are viewing the atom in such a way that the electron's orbit is in the plane of the paper with the electron moving clockwise, find the magnitude of the electric field that the electron produces the location of the nucleus (treated as a point).
b. Find the direction of the electric field that the electron produces at the location of the nucleus (treated as a point) from the electron toward the electron
c. Find the magnitude of the magnetic field that the electron produces at the location of the nucleus (treated as a point).
a. The magnitude of electric field is found to be E = 5.14 x 10¹¹ N/C ,
b. The direction of the electric field that the electron produces at the location of the nucleus is radial
c. the magnitude of the magnetic field is 2.63 x 10⁻⁷ T
a. To find the magnitude of the electric field that the electron produces at the location of the nucleus, we can use Coulomb's law, which states that the electric force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. In this case, the electron has a charge of -1.6 x 10⁻¹⁹ C, and the nucleus has a charge of +1.6 x 10⁻¹⁹ C (since the hydrogen atom is neutral, the nucleus must have a positive charge). The distance between the electron and the nucleus is the radius of the electron's orbit, which is 5.3 x 10⁻¹¹ m.
Therefore, the magnitude of the electric field is:
E = (k * q₁ * q₂) / r²
E = (9 x 10⁹ N m²/C²) * (1.6 x 10⁻¹⁹ C) * (-1.6 x 10⁻¹⁹C) / (5.3 x 10⁻¹¹ m)²
E = 5.14 x 10¹¹ N/C
where k is Coulomb's constant.
b. The direction of the electric field that the electron produces at the location of the nucleus is radial, pointing directly from the electron toward the nucleus. This is because the electric force between two point charges always points along the line connecting them, and in this case, the electron and the nucleus are both point charges. Therefore, the electric field points inward, toward the nucleus.
c. The magnetic field produced by the electron is given by the formula:
B = (μ0/4π) * (q * v * sinθ) / r²
where μ0 is the permeability of free space (4π x 10⁻⁷ T m/A), q is the charge of the electron, v is its speed, θ is the angle between the velocity vector and the line connecting the electron and the nucleus, and r is the distance between them. Since the electron is moving in a circular orbit, its velocity vector is perpendicular to the line connecting it to the nucleus, so θ is 90 degrees and sinθ is 1. Therefore, the magnitude of the magnetic field is:
B = (μ0/4π) * (q * v) / r²
B = (4π x 10⁻⁷ T m/A) * (-1.6 x 10⁻¹⁹ C) * (2.2 x 10⁶ m/s) / (5.3 x 10⁻¹¹ m)²
B = 2.63 x 10⁻⁷ T
where T is the unit of magnetic field called the Tesla.
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Question 2
5 pts
The air inside a beach ball is at a temperature of 25°C a pressure of 1.0 atm. The ball
contains 0.85 mol of air, what is its volume?
21 L
27 L
0 171
06.11
< Previous
Nest
Answer: The volume of given ball is 21 L.
Explanation:
Given : Pressure = 1.0 atm, no. of moles = 0.85 mol
Temperature = \(25^{o}C = (25 + 273) K = 298 K\)
According to the ideal gas equation, formula used is as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
\(PV = nRT\\1.0 atm \times V = 0.85 mol \times 0.0821 Latm/mol K \times 298 K\\V = 21 L\)
Thus, we can conclude that the volume is 21 L.
If a plant cell is placed in a solution and the cell shrivels up, what type of solution was it placed in? How do you know?
Answer:
The cell is in a Hypotonic solution. When a cell is in a Hypotonic solution the lower osmotic pressure causing water to move across the pressure gradient into the solution causing the cell to shrivel.
Which group in the Periodic Table contains elements that are all gases?
1. 11
2. 17
3. 12
4. 18
Answer:
d
Explanation:
the group's name is called noble gases. hence they are all gases.
Air is cooling at night. The frost point (temperature at which RH with respect to ice reaches 100%) is reached at T = -10 degree Celsius. a) What is the RH (normal RH with respect to liquid water) at this point? b) Upon further cooling the air reaches a temperature of T =-11 degree Celsius Kaolinite particles of 200 nm diameter are present. Do you expect ice particles to form? If yes, do they form via deposition nucleation or condensation of droplets followed by freezing? Briefly explain your answer. c) Upon even further cooling the air reaches a temperature of T = -12 degree Celsius. Same question as before: Do you expect ice particles to form now? If yes, do they form via deposition nucleation or condensation of droplets followed by freezing? Briefly explain your answer. Equilibrium vapor pressures may be calculated or taken from the table below. t/°C 0 -1 -2 -3 -4 -5 -6 -7 -8 -9 - 10 -11 -12 -13 T/ Keow /Pa 273.15 611.2 272.15 568.2 271.15 527.9 270.15 490.2 269.15 454.8 268.15 421.8 267.15 390.9 266.15 362.1 265.15 335.1 264.15 310.0 263.15 286.5 262.15 264.7 261.15 244.3 260.15 225.4 259.15 207.8 258.15 191.4 e oi/Pa 611.2 562.7 517.7 476.1 437.5 401.8 368.7 338.2 310.0 283.9 259.9 237.7 217.3 198.5 181.2 165.3 - 14 - 15 Equilibrium vapor pressures with respect to water (eow) and with respect to ice (coi).
The equilibrium vapor pressure with respect to water (eow) is 259.9 Pa. assume that saturation vapor pressure is same as equilibrium vapor pressure.
Therefore, the RH at the frost point is
RH = (eow / saturation vapor pressure) × 100
= (259.9 Pa / 259.9 Pa) × 100
= 100%
b) At T = -11 °C, we need to compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi) to determine if ice particles will form. From the given table, at T = -11 °C, the equilibrium vapor pressure with respect to water (eow) is 237.7 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 165.3 Pa.
The air is supersaturated with respect to ice, and the presence of Kaolinite particles can provide surfaces for water droplets to condense onto, leading to the formation of ice particles.
c) At T = -12 °C, we compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi). From the given table, at T = -12 °C, the equilibrium vapor pressure with respect to water (eow) is 217.3 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 181.2 Pa.
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What is the best description of radiation
Radiation is the emission and propagation of energy in the form of waves, rays, or particles. There are three main types of radiation Non-ionizing radiation , Ionizing radiation, and Neutrons.
Non-ionizing radiation is the release of energy from the lower-energy region of the electromagnetic spectrum. Ionizing radiation is radiation with sufficient energy to remove an electron from an atomic orbital, forming an ion. Neutrons are particles found in the atomic nucleus.
Radiation includes the emanation of any portion of the electromagnetic spectrum, plus it includes the release of particles. An example is a burning candle that emits radiation in the form of heat and light. Radiation is the release of energy, whether it takes the form of waves or particles. Radioactivity refers to the decay or splitting of an atomic nucleus. A radioactive material releases radiation when it decays.
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When patients are admitted to a hospital they will have their blood pressure and oxygen saturation measured. The probability of a person having problems with blood pressure is 0.4482, the probability of a person having low oxygen saturation is 0.2194, and the probability of a person having them both is 0.0916. What is the probability of a person's measures are normal for blood pressure and oxygen saturation? Round your answer to four decimal places.
The probability of a person's measures are normal for blood pressure and oxygen saturation is 0.4303.
Given that the probability of a person having problems with blood pressure is 0.4482,
the probability of a person having low oxygen saturation is 0.2194, and the probability of a person having them both is 0.0916.
We need to calculate the probability of a person's measures are normal for blood pressure and oxygen saturation.
The probability of a person's measures being normal for blood pressure and oxygen saturation is given as(normal for blood pressure) = 1 - P(problems with blood pressure)
= 1 - 0.4482
=0.5518P(normal for oxygen saturation)
= 1 - P(low oxygen saturation) = 1 - 0.2194
= 0.7806
Using the formula(normal for blood pressure and normal for oxygen saturation)
= P(normal for blood pressure) x P(normal for oxygen saturation)
Multiplying the probabilities, we get(normal for blood pressure and normal for oxygen saturation)
= 0.5518 × 0.7806
= 0.4303
Rounded off to four decimal places, the probability of a person's measures are normal for blood pressure and oxygen saturation is 0.4303.
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calculate the amount of parent isotope that remaining after 1, 2, 3, and 4 half-lives. include 4 decimal places in your answers. parent present: 1.0000 unit (i.e., all of the parent isotope is still present) after 1 half-life: 0.5000 units
For each half-life, the total amount of the isotope is divided by 2.
Therefore, the amount of parent isotope that remains after:
1 half-life is ½= 0.5
2 half-lives= 2/4= 0.5
3 half-lives= 3/6= 0.5
What is an isotope?
Isotopes are two or more atoms sharing the same atomic number and chemical element but have distinct nucleon numbers (mass numbers) as a result of having a different number of neutrons in their nuclei. The word "isotope" is derived from the Greek words "isos" and "topos," both of which imply "the same location." As a result, the name refers to the fact that various isotopes of a given element occupy the same spot on the periodic table. Scottish physician and author Margaret Todd first used it in a recommendation in 1913.To know more about isotopes, click the link given below:
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Which organisms are common pioneer species?