Two parallel, metal plates with separation distance d = 1.00 cm carry charges of equal magnitude but opposite sign. The plates are oriented horizontally. Assume the electric field between the plates is uniform, and it has a magnitude of 1,920 N/C. A charged particle with mass 2.00 â 10^â16 kg and charge 1.02 â 10%â6 C is projected from the center of the bottom negative plate with an initial speed of 1.07 â 10%5 m/s at an angle of 37.0° above the horizontal. Assume the plates are square with side length = 20.0 cm.

Required:
a. Describe the trajectory of the particle.
b. Which plate does it strike?
c. Where does it strike, relative to its starting point?
d. What is the minimum initial speed (in m/s) the particle must have in order to change the answer to part (b)?

Answers

Answer 1

We have that  the trajectory of the particle,The plate the particle strikes,Where it strikes, relative to its starting point and the minimum initial speed (in m/s) the particle must have in order to change the answer to part (b) are as follows

Parabola Negative plate\(a=9.792x10^{12}m/s^2\)\(V_m=570452.106m/s\)

From the question we have that

Distance \(d=1.00cm=0.01m\)

Magnitude  \(M=1,920 N/C\)

Mass \(m=2.00x10^{-16} kg\)

Charge \(q=1.02x10^{-6} C\)

initial speed \(V_0= 1.07x10^5 m/s\)

Angle \(\theta= 37\)

Length \(l= 20.0 cm.\)

a)

The Particle follow a Parabola trajectory through its travel as a Parabola Creates a Curved Plane and has its initial half side same as the final side.with the particle is a \(\theta= 37\) angle create on its elevation and depression

Parabola

b)

It strikes the Negative plate at a specific distance to be discovered in the C part of the Question

c)

We are tasked to determine where the particle strikes the plate.

Generally the equation for strike distance S  is mathematically given as

\(s=\frac{v_0^2 sin(2\theta)}{a}\)

Where

\(a=\frac{qM}{m}\)

\(a=\frac{1.02x10^{-6}x1920}{2.00x10^{-16} }\)

\(a=9.792x10^{12}m/s^2\)

Therefore

\(s=\frac{v_0^2 sin(2\theta)}{a}\)

\(\frac{(1.07x10^5)^2 xsin(2*37)}{9.792x10^{12}}\)

\(s=0.0011239m\)

d)

Generally the equation for  the minimum Velocity  is mathematically given as

\(V_m=\sqrt{\frac{2ah}{sin(\theta)}}\)

\(V_m=\sqrt{\frac{2x9.792*10^{12}*0.01}{sin(37)}}\)

\(V_m=570452.106m/s\)

In conclusion

The trajectory of the particle,The plate the particle strikes,Where it strikes, relative to its starting point and the minimum initial speed (in m/s) the particle must have in order to change the answer to part (b) are as follows

Parabola Negative plate\(a=9.792x10^{12}m/s^2\)\(V_m=570452.106m/s\)

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Related Questions

Please help me with this
10 points
all i have rn :/
thanks <3

Please help me with this10 points all i have rn :/thanks &lt;3

Answers

Answer: c the last one

Explanation:

C because the Sun is a star which always stays in place unlike earth it’s a planet so it’s consistent move


a What is meant by zero error?
b Give an example of when you would have to allow
for it.

Answers

a) It is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.

b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge.

a) Zero error refers to the deviation or discrepancy in the measurement instrument, where the indication or reading on the instrument is not zero when the quantity being measured is zero. In other words, it is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.

Zero error can occur due to various reasons such as manufacturing defects, wear and tear, misalignment, or improper calibration of the instrument. It can be positive or negative, depending on whether the instrument reads higher or lower than the actual value.

b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge. These instruments are commonly used to measure the dimensions of objects with high precision.

In a vernier caliper, for instance, zero error can occur when the jaws do not close perfectly when there is no object being measured. If the caliper shows a reading other than zero when the jaws are closed, it indicates the presence of zero error.

To obtain accurate measurements, the zero error needs to be accounted for and compensated. This can be done by adjusting the position of the zero on the scale or by subtracting the zero error value from the measured readings.

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3. Observe: An organelle is a cell structure that performs a specific function. Observe the samples below under the highest magnification. Click the Show labels checkbox to label the organelles. List the organelles and approximate size of the cells in each sample.

Answers

Organelles are specialized structures within cells that perform specific functions, such as energy production, protein synthesis, and waste removal.

Some examples of organelles include mitochondria, which produce energy for the cell, and ribosomes, which are involved in protein synthesis.

The size of cells can vary widely depending on the organism and the type of cell. For example, human cells can range from 10 to 30 micrometers in diameter, while bacterial cells are typically much smaller, ranging from 1 to 5 micrometers in diameter.

In summary, organelles are specialized structures within cells that perform specific functions, and the size of cells can vary widely depending on the organism and the type of cell.

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(20) A rocket is launched vertically. At time t = 0 seconds, the rocket’s engine shuts down. At the time, the rocket has reached an altitude of 500m and is rising at a velocity of 125 m/s. Gravity then takes over. The height of the rocket as a function of time is h(t)=-9.8/2 t^2+125t+500,t>0. Using your function file from HW2A: Generate a plot of height (vertical axis) vs. time (horizontal axis) from 0 to 30 seconds. Include proper axis labels. Find the maximum height and the time at which it occurs: Analytically, showing your steps and equations. This part should be done entirely in the write-up: no coding Using the data cursor on the plot. Using the MAX function on your data from part (a) Using FMINSEARCH on your m file Comment on the differences between the methods. How closely does each method match the "true" (analytical) value? Find the time when the rocket hits the ground: Analytically, showing your equations. This part should be done entirely in the write-up: no coding Using the data cursor on the plot. Using FZERO on your m file Comment on the differences between the methods in each of part (B) and (C). How closely does each method match the "true" (analytical) value? Use a quantitative comparison to make your argument.

Answers

Answer:

Explanation:

Given that,

h(t) = -9.8t² / 2 + 125t + 500

for t > 0.

At t = 0, the rocket is at height h = 500m, at a velocity of Vo = 125m/s.

We want to find the maximum height reached by rocket

Using mathematics maxima and minima

let find the turning point when dh/dt = 0

dh/dt = -9.8t + 125

dh / dt = 0 = -9.8t + 125

9.8t = 125

t = 125 / 9.8

t = 12.76s

Let find the turning point to know if this time t = 12.76 is maximum or minimum point

Let find d²h / dt²

d²h / dt² = -9.8

Since, d²h/dt² < 0, then, at t = 12.76s is the maximum points.

Then, the maximum height reached is

h =  -9.8t² / 2 + 125t + 500

h =  -9.8(12.76)² / 2 + 125(12.76) + 500

h = -797.80 + 1595 + 500

h = 1297.2 m

The maximum height reached is 1297.2 m

From the attachment, the maximum height is 1297.2m at t = 12.76sec.

Comment, the result are the same for both the analysis aspect and the graphical aspect.

(20) A rocket is launched vertically. At time t = 0 seconds, the rockets engine shuts down. At the time,

22 Humans see different colors of
the visible light spectrum because
A. the wavelength of light is
reflected by what it is hitting and
directed back into the eye.
B. the wavelength of light is
refracted by what it is hitting and
directed back into the eye.
C. the wavelength of light is
diffracted by what it is hitting
and directed back into the eye.
D. the wavelength of light is
absorbed by what it is hitting and
directed back into the eye.

Answers

Answer:

A. the wavelength of light is reflected by what it is hitting and directed back into the eye.

Explanation:

A rock falls to the ground with a force of 300N and air resistance pushes back up on the rock with a
force of 45N. Which is true of the rock?

Answers

Answer:

what are the choices

Explanation:

don't worry i'll edit it

A train approaching a crossing changes speed from 25 m/s to 10 m/s in 240 s. How can the train’s acceleration be described?
A. The train’s acceleration is positive.
B. The train is not accelerating.
C. The train will come to rest in 6 minutes.
D. The train’s acceleration is negative.

Answers

The acceleration of the train can be described as: The train’s acceleration is negative (Option D)

How do I know the nature of the acceleration?

To describe the acceleration of the train, we shall determine the acceleration of the train. Details below:

From the question given above, the following were obtained:

Initial velocity (u) = 25 m/sFinal velocity (v) = 10 m/sTime (t) = 240 sAcceleration (a) =?

a = (v - u) / t

a = (10 - 25) / 240

a = -15 / 240

a = -0.0625 m/s²

From the above calculation, we can see that the acceleration is -0.0625 m/s²

Thus, the correct answer to the question is: The train’s acceleration is negative (Option D)

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Brianna has difficulty focusing in school and has struggled to learn to read. How would this disorder be classified in the DSM-5? (2 points)
a
Personality Disorder

b
Sleep-Wake Disorder
c
Schizophrenia Spectrum Disorder

d
Neurodevelopmental Disorder

Answers

D
Neurodevelopmental Disorder

I need help with magnitudes of net force

I need help with magnitudes of net force

Answers

since both forces are equal and are in opposite directions, Fnet would be 0

At time t = 0 s, a puck is sliding on a horizontal table with a velocity 3.60 m/s, 35.0° above the +x axis. As the puck slides, a constant acceleration acts on it that has the following components: a = - 2 0.360 m/s and da, = -0.980 m/s. What is the velocity of the puck at time t = 1.50 s? 2 0​

Answers

The velocity of the punk at time t = 1.5 s is equal to 2.47 m/s.

What are the components of velocity?

The object will have two velocities during the projectile motion, one is horizontal velocity and the other is vertical velocity. The horizontal velocity of the object is constant throughout the projectile motion but the vertical velocity is changed in the projectile motion.

Given that the velocity vector is making an angle θ with a horizontal table, θ = 35°

The vertical component of the velocity of the puck can be determined as:\(u_x = u Sin 35^o = 3.60 \times 0.573 =2.06 m/s\)

The horizontal component of the velocity of the puck can be determined as:

\(u_y = u cos 35^o = 3.60 \times 0.82=2.95 m/s\)

Given the acceleration aₓ = -0.360 m/s² and a y = -0.980 m/s²

The final vertical components of the velocity of the punk are:

\(v_x = u_x + a_xt\)

\(v_x = 2.95 - (0.360) (1.5)\\v_x = 2.41 m/s\)

and, the horizontal velocity of the punk is:

\(v_y = u_y +a_yt\\v_y = 2.06 - (0.980) (1.5)\\v_y = 0.59 m/s\)

The velocity of the punk can be determined as:

\(v = \sqrt{v_x^2 + v_y ^2}\\ v =\sqrt{(5.80)^2 + (0.35)^2}\\ v = 2.47 m/s\)

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Force varies directly with pressure. A force of 22,000 newtons acts on an object, causing 110 N/m² of pressure. The
force decreases to 18,000 newtons. What is the new amount of pressure caused by the force?
○ 45 N/m²
90 N/m²
O 75 N/m²
60 N/m²

Answers

The final amount of pressure caused by the force is 90 N/m².

Initial amount of force, F₁ = 22 x 10³ N

Initial amount of pressure produced, P₁ = 110 N/m²

Final amount of force exerted, F₂ = 18 x 10³ N

Pressure is defined as the amount of force acting on an object per unit area of the object.

So, we can say that the force and pressure are directly proportional.

F ∝ P

So, F₁/P₁ = F₂/P₂

Therefore, the final amount of pressure caused by the force is,

P₂ = F₂P₁/F₁

P₂ = 18 x 10³x 110/22 x 10³

P₂ = 18/0.2

P₂ = 90 N/m²

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The train slows down at the railroad crossing. Is that acceleration, velocity, speed, of none of the above?​

Answers

Answer:

none of the above

Explanation:

im pretty positive this is the answer tell me if i am wrong please

10. The table below shows the melting point and the boiling point of four substances.
Which substance is a liquid at room temperature of 20°C?
Substance
A
B
m.
-101
-39
30
327
bir
-35
357
2100
1750
C
D
Page 3
Set by: Mohamed Sabca​

Answers

B would be the answer

a car of mass 500 kg is moving with an instantaneous speed of 80.0 km/h. what is its kinetic energy

Answers

Answer:7.5. 10^4 J

Explanation:

Answer:

The Kinetic Energy of the car at that instant will be 123,210 Joules.

Explanation:

Given:

Mass=500 Kg

\(Speed= 80 km/h=\frac{80*1000}{3600}\ m/s =22.2 m/s\)

Required:

Kinetic energy (K.E)=?

Formula:

\(K.E=\frac{1}{2}mv^{2}\)

Where:

m is the mass.

v is the speed.

Solution:

\(K.E=\frac{1}{2}mv^{2}\\K.E=\frac{1}{2} *500* (22.2)^{2} \\K.E=123,210 J\)

The Kinetic Energy of the car at that instant will be 123,210 Joules.

A 16.0 g bullet is moving to the right with speed 250 m/s when it hits a target and travels an additional 22.6 cm into the target. What are the magnitude (in N) and direction of the stopping force acting on the bullet

Answers

Answer:

The magnitude will be "2212 N".

Explanation:

The given values are:

Initial speed, u = 250 m/s

Final speed, v = 0

Mass, m = 16.0 = 0.016 kg

Distance, d = 22.6 cm

On converting cm into m, we get

d = 0.226 m

As we know,

⇒  \(v^2-u^2=-2ad\)

⇒  \(a=\frac{v^2-u^2}{-2d}\)

On putting the estimated values, we get

⇒    \(=\frac{(0)^2-(250)^2}{-2\times 0.226}\)

⇒    \(=\frac{0-62500}{-0.452}\)

⇒    \(=13,8276 \ m/s^2\)

Now,

Force, \(F=ma\)

On putting values, we get

⇒            \(=0.016\times 138276\)

⇒            \(=2212 \ N\) (magnitude)

The magnitude of the stopping force on the bullet is 2,212.4 N in opposite direction to the bullet.

The given parameters;

mass of the bullet, m = 16 gspeed of the bullet, u = 250 m/sdistance traveled by the bullet and the target, d = 22.6 cm = 0.226 m

The acceleration of the bullet is calculated as follows;

v² = u² - 2ad

where;

v is the final velocity when the bullet stops = 0

0 = 250² - a(2 x 0.226)

0.452a = 62500

\(a = \frac{62500}{0.452} \\\\a = 138,274.34 \ m/s^2\\\\\)

The magnitude of the stopping force on the bullet is calculated as follows;

F = ma

F = 0.016 x 138,274.34

F = 2,212.4 N

Thus, the magnitude of the stopping force on the bullet is 2,212.4 N in opposite direction to the bullet.

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the international space station orbits the earth at a speed of 7660m/s.If it has a kinetic energy of 1.24 x 1013J, what is its mass

Answers

Answer:

4.2 x 10⁵kg

Explanation:

Given parameters:

Speed of orbit  = 7660m/s

Kinetic energy  = 1.24 x 10¹³J

Unknown:

Mass  = ?

Solution:

Kinetic energy is the energy due to the motion of a body. It is mathematically expressed as;

       K.E  = \(\frac{1}{2}\)mv²

m is the mass

v is speed

Now insert the parameters and find the mass;

   1.24 x 10¹³   =  \(\frac{1}{2}\) x m x 7660²  

   1.24 x 10¹³  = 2.93 x 10⁷m

  m  = \(\frac{1.24 x 10^{13} }{2.93 x 10^{7} }\)   = 0.42 x 10⁶kg = 4.2 x 10⁵kg

When the applied force is 150 N and the friction is 94 N, what is the motion? A. Accelerated motion b. Decelerated motion c. No motion D. Uniform motion

Answers

Answer:

the answer to this question is Accelerated motion

Which type of muscle cell can have multiple nuclei

Answers

Answer:

Skeletal muscle cells

Explanation:

Skeletal muscle cells are long, cylindrical, and striated. They are multi-nucleated meaning that they have more than one nucleus. This is because they are formed from the fusion of embryonic myoblasts.

pls mark me the brainliest

Answers for these 2 please

Answers for these 2 please

Answers

i think the answer for question 1 is 4.
Question 1 is acceleration = 1 m/s^2

Describe the setup of the electromagnet. Why does the wire need to be a conductive material?

Answers

An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.

An electromagnet is a type of magnet that is created by running an electrical current through a wire. The setup of an electromagnet involves a few basic components. First, there must be a wire that is conductive, meaning that it can conduct electricity. This wire is usually wrapped around a core, which is often made of iron, steel, or another magnetic material. When an electrical current is run through the wire, it creates a magnetic field around the wire. This magnetic field then magnetizes the core, creating an even stronger magnetic field. The strength of the electromagnet can be controlled by adjusting the amount of current that is run through the wire. The wire must be a conductive material because it needs to be able to carry the electrical current that creates the magnetic field. If the wire were not conductive, then the electrical current would not be able to flow through it, and the magnetic field would not be created. In summary, the setup of an electromagnet involves a conductive wire wrapped around a magnetic core, which is magnetized by the electrical current running through the wire. The wire must be conductive to carry the electrical current and create the magnetic field.

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what did rutherford discover in his experiment

Answers

In his famous gold foil experiment, Ernest Rutherford discovered that the atom was mostly composed of empty space, and that a small, dense nucleus containing the majority of the atom's mass was located at its center.

What is Rutherford?
First Baron Rutherford of Nelson Ernest Rutherford, OM, FRS, HonFRSE The father of nuclear physics is, a New Zealander who lived from 30 August 1871 to 19 October 1937. He is regarded as the greatest experimenter since Michael Faraday by Encyclopaedia Britannica (1791–1867). He worked outside of his home country for a significant portion of his career, both in Canada and in the Kingdom. Early research by Rutherford led to the discovery of the radioactive element radon, the idea of radioactive half-life, and the classification and naming of alpha and beta radiation. At McGill University in Quebec, Canada, this work was completed. It served as the foundation for his 1908 Nobel Prize in Chemistry, which was given in recognition of his studies into to the disintegration of a elements.

He also found that a small percentage of alpha particles, which are positively charged particles, were deflected rather than passing straight through the gold foil. This led to the conclusion that the atom was composed of a positively charged nucleus surrounded by negatively charged electrons.

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Two loudsspeakers emit identical sound waves along the x axis. THe osund at a point on the axis has maximum intensity when the speakers are 40 cm apart. The sound intensity decreases as the distance between the speakers is increased, reaching zero at a separation of 50 cm. If the distance between the speakers continuse to increase, at what separation will the sound intensity again be a maximum?

Answers

Answer: 30 cm.

Solving

The situation described is that of two sources of sound waves that are separated by some distance. The two waves interfere with each other constructively at some points and destructively at others. When they interfere constructively, the amplitude (and intensity) of the sound wave is greater than when they interfere destructively.

When the speakers are 40 cm apart, the waves that they produce are in phase at some points on the axis, leading to constructive interference and a maximum in the intensity of the sound. As the distance between the speakers is increased beyond 40 cm, the points of constructive interference move farther apart, and the intensity of the sound decreases. When the speakers are 50 cm apart, the waves that they produce are exactly out of phase at some points on the axis, leading to complete destructive interference and a minimum in the intensity of the sound.

If the separation between the speakers continues to increase, the points of constructive interference will move closer together again, and the intensity of the sound will increase. The separation between the speakers at which the intensity of the sound will again be a maximum can be found using the following equation:

d = λ/2 + nλ

where d is the separation between the speakers, λ is the wavelength of the sound wave, and n is an integer that represents the number of half-wavelengths between the speakers.

At the maximum, the separation is an even multiple of half the wavelength, so we can use the formula above with n = 1. The wavelength can be found from the distance between the speakers at the minimum, which is 50 cm, and the distance at the maximum, which is 40 cm:

λ = 2(d_max - d_min) = 20 cm

Substituting λ and n into the formula gives:

d = λ/2 + nλ = 10 cm + 20 cm = 30 cm

Therefore, the sound intensity will be a maximum again when the separation between the speakers is 30 cm.

____ is based on the acceptance of rules and laws.

Multiple Choice

1. Rational-legal authority
2. Traditional authority
3. Legal power
4. Political power​

Answers

3 is the answer hdhshhshshs

andrew returns to the top of the hill and starts again
his mass is 67kg.
calculate his momentum when his velocity is 31 m/s

Answers

As a result, when Andrew is moving at a speed of 31 m/s, his momentum is 2077 kg*m/s.

What is the kinetic energy equation?

Kinetic energy has the following formula: K.E. = 1/2 m v2, where m is the object's mass and v is its square velocity. The kinetic energy is measured in kilogrammes-meters squared per second squared if the mass is measured in kilogrammes and the velocity is measured in metres per second.

An object's mass (m) and velocity (v) can be multiplied to find its momentum (p), which is written as:

p = m * v

Given that Andrew's mass is 67 kg and his velocity is 31 m/s, his momentum can be calculated as:

p = 67 kg * 31 m/s

p = 2077 kg*m/s

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Question:

Andrew is riding his bike up a hill. At some point, he stops and rests at the top of the hill. He then turns around and starts riding down the hill. When he reaches a velocity of 31 m/s, calculate his momentum. Andrew's mass is 67 kg.

An object whose mass is 3 kg is fired from an artillery cannon, giving it a forward momentum of 1050 kg•m/s . What is its velocity?

Answers

Given :-

Mass of the object is 3kg .Its momentum is 1500kg m/s

To Find :-

Its velocity .

Solution :-

As we know that , the amount of motion contained in a body is called momentum . Mathematically ,

\(\sf\twoheadrightarrow Momentum = mass * velocity\\\\\)

\(\sf\twoheadrightarrow 1500kg\ m/s = 3kg * v\\\\ \)

\(\sf\twoheadrightarrow v =\dfrac{1500kg\ m/s}{3kg}\\\\\)

\(\sf\twoheadrightarrow \underline{\underline{\blue{ velocity = 500m/s}}}\)

VELOCITY

Problem:

» An object whose mass is 3 kg is fired from an artillery cannon, giving it a forward momentum of 1050 kg•m/s . What is its velocity?

Answer:\( \color{hotpink} \bold{500 \: m/s} \\ \)

— — — — — — — — — —

— To calculate the velocity of a momentum, use formula:

\( \underline{ \boxed{ \tt v= \frac{p}{m} }} \\ \)

where,

v is the velocity measured in meters per second (m/s)p is the momentum in kg•m/sm is the mass measured in kilograms (kg)

Solution:

Since the givens are 3 kg mass, and 1050 kg•m/s momentum, then...

Using the formula/equation above, we get

\( \tt \: v = \frac{p}{m}\\\)

\( \tt \: v = \frac{1500 \: kg \cdot m/s}{3 \: kg} \\\)

\( \tt v = \underline{ \boxed{ \blue{ \tt 500 \: m/s}}}\\\)

\( \therefore \sf Its \: velocity \: is \: \: \bold{500 \: m/s}\)

_______________∞_______________

The frequency of microwaves in a microwave oven is 2450 MHz . What is the mode number for electromagnetic standing waves in a 42.9- cm -wide microwave oven?

Answers

The mode number for the electromagnetic standing waves in a 42.9-cm-wide microwave oven with a frequency of 2450 MHz is 7.

The mode number of  standing waves in a microwave oven can be found using  formula:

n = 2L/λ

λ = c/f

where c is the speed of light in vacuum and f is  frequency of the microwaves.

We are given  frequency of  microwaves as 2450 MHz. Converting this to SI units, we get:

\(f = 2.45 * 10^9 Hz\)

The speed of light in vacuum is approximately \(3.00 *10^8 m/s\).

Now we can calculate  wavelength:

\(\lambda = c/f \\\lambda = (3.00 * 10^8 m/s) / (2.45 * 10^9 Hz) \\\lambda = 0.1225 m\)

We are also given the width of the microwave oven as 42.9 cm, which we convert to meters:

L = 0.429 m

Now we can calculate the mode number:

\(n = 2L/\lambda \\n = 2(0.429 m) / 0.1225 m \\n = 7\)

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A student performs an experiment in which a 4kg object travels across a horizontal surface with an initial speed velocity of 6m/s and a 2kg object travels across a horizontal surface with an initial speed velocity of −3m/s. The objects travel toward each other and collide. Data collected from the experiment were used to create the velocity versus time graph shown that contains information about both objects before and after the collision. The positive direction is considered to be to the right. Which of the following statements are true regarding the data from the experiment?

A- Both objects always travel in the positive direction during the experiment.

B- Kinetic energy is conserved during the experiment.

C- The position of the center of mass of the system remains constant during the experiment.

D- The velocity of the center of mass of the two-object system remains constant during the experiment.

Answers

The position of the center of mass of the system remains constant during the experiment.

Conservation of linear momentum

The principle of conservation of linear momentum states that the total momentum of the system before after collision is always conserved for both elastic and inelastic collision.

\(m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2\ \ (elastic)\\\\m_1 u_1 + m_2 u_2 = v(m_1 + m_2 ) \ (inelastic)\)

Conservation of kinetic energy

The total kinetic energy of the system is conserved for perfectly elastic collision BUT not conserved for inelastic collision.

The center mass of the system

The center mass of the system is always constant.

Thus, the position of the center of mass of the system remains constant during the experiment.

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A liquid has a volume and a shape.

Answers

Answer:

A liquid has no definite shape since its molecules are loosely held onto each other. But it does have a volume

Answer:

a liquid has a fixed volume and a variable shape.

Explanation:

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Most people can throw a baseball farther than a bowling ball, and most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball. Explain these two situations in terms of
Newton’s First Law of Motion
Newton’s Second Law of Motion

Answers

Based on Newton's first  and second law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.

What is Newton's first law of motion?

Newton's first law of motion first law of motion states that a body at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force.

Newton's first law of motion is also called law of inertia because it depends on mass of the object.

An object with a greater mass will require greater force to be stopped or get moving.

Based on Newton's first law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.

Also according to Newton's second law of motion, the force applied to an object is proportional to the product of mass and acceleration of the object. Thus, a baseball with smaller mass will require smaller force to be stopped.

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round around the sun. earth. satellite is a satellite that cebits the equator with the same angalar velocity a Part Two: Match the items ander column "B" with the items under column "A" as related A B 9. Friction charges 10. Loss electrons 11. Like charges A Repel forces B. Positive charges C. Charging by rubbing D. Attracting forces E 12. Unlike charges 13. Neutral charges E. Charging by induction Part Three: Choose the correct answer from the given alternatives. 14. If Charge Ql attracts Q2 and charges Q2 repels charge Q3. Which of the following is correct their signs? A. D.- 13. The electric field strength at a point is defined by the force of A. Source charges B. Test charge C. An electron D. Proton C B 6. Orbital velocity of a satellite does not depend on: A. Mass of earth B. Mass of satellite C Radius of earth D. Acceleration due to gravity 7. When a planet moves around the sun: A the angular moment remains conserved. B. The angular speed remains constant. C. The linear momentum remains constant. D. The linear velocity remains constant. - Kepler's law of area is consequence of A. conservation energy. B. conservation of mass. C. conservation of linear momentum. D. conservation of angular momentunt. A current of 4A flows through 2011 resistors. How much power is lost in the resistor? A. 320w B. 80w C. 24w D. 60 A boy observed that a pen rubbed on his dry hair attracted a nearby neutral piece of paper cause of the attraction? A. Magnetic forces B. Nucleus forces C. Gravitational forces D. Electrostatic forces What will happen to the electric potential at a point in the field if the distance from the c Decrease by half B. Increase two times C. Increase four times D. Decrease to he distance between plates of a parallels plate capacitor is 1cm. If the electric field st at is the potential difference between the plates of the capacitor? B. 0.13/c Die C. 10J/c D. 0.013/c​

Answers

The matchup are given below

9. Friction charges: Charging by rubbing (C)

10. Loss electrons: Positive charges (B)

11. Like charges: Repel forces (A)

12. Unlike charges: Attracting forces (D)

13. Neutral charges: Charging by induction (E)

14. If Charge Q1 attracts Q2 and charges Q2 repels charge Q3, the correct sign of their charges is: Unlike charges (D)

15.The electric field strength at a point is defined by the force of: Test charge (B)

16. Orbital velocity of a satellite does not depend on: Mass of earth (A)

17. When a planet moves around the sun: The angular moment remains conserved (A)

18. Kepler's law of area is a consequence of: conservation of angular moment (D)

18. If a current of 4A flows through a 2011 ohm resistor, the power lost in the resistor is: 80W (B)

20. If a boy observed that a pen rubbed on his dry hair attracted a nearby neutral piece of paper, the cause of the attraction is: Electrostatic forces (D)

21. If the distance from a point in the electric field is decreased by half, the electric potential at that point will: Increase four times (C)

22. The potential difference between the plates of a parallel plate capacitor with a distance of 1cm between plates and electric field strength of 10J/c is: 0.13V/c (B)

What are the statements about?

The term "Friction charges" refers to the process of charging an object by rubbing it against another material. When two materials are rubbed together, electrons can be transferred from one material to the other, creating a static electric charge. The resulting charge on the object is referred to as "friction charges."

Therefore, in terms of Loss electrons: The term "Loss electrons" refers to a situation in which an object loses electrons and becomes positively charged. This can occur when electrons are transferred from the object to another material through a process such as friction charging or electrical discharge. When an object loses electrons, it has a surplus of positively charged particles and is said to have a positive charge.

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