Answer:
I think its true
Step-by-step explanation:
hope it helps and you have a greate Day
(i know the answer) ·ω· so i will tell you if you are right so ever gets it right gets brainliest
(question is what is the gcf (greatest common factor) of 24 and 16)
·ω·
→←
Answer:
Step-by-step explanation:
8,2,4
Question 5
A recent conference had 900 people in attendance. In one exhibit room of 80 people, there were 65 teachers and 15 principals. What prediction can you make about the number of principals in attendance at the conference?
There were about 820 principals in attendance.
There were about 731 principals in attendance.
There were about 208 principals in attendance.
There were about 169 principals in attendance.
Question 6
A teacher was interested in the subject that students preferred in a particular school. He gathered data from a random sample of 100 students in the school and wanted to create an appropriate graphical representation for the data.
Which graphical representation would be best for his data?
Stem-and-leaf plot
Histogram
Circle graph
Box plot
Question 7
A random sample of 100 middle schoolers were asked about their favorite sport. The following data was collected from the students.
Sport Basketball Baseball Soccer Tennis
Number of Students 17 12 27 44
Which of the following graphs correctly displays the data?
histogram with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled basketball going to a value of 17, the second bar labeled baseball going to a value of 12, the third bar labeled soccer going to a value of 27, and the fourth bar labeled tennis going to a value of 44
histogram with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled baseball going to a value of 17, the second bar labeled basketball going to a value of 12, the third bar labeled tennis going to a value of 27, and the fourth bar labeled soccer going to a value of 44
bar graph with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled basketball going to a value of 17, the second bar labeled baseball going to a value of 12, the third bar labeled soccer going to a value of 27, and the fourth bar labeled tennis going to a value of 44
bar graph with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled baseball going to a value of 17, the second bar labeled basketball going to a value of 12, the third bar labeled tennis going to a value of 27, and the fourth bar labeled soccer going to a value of 44
Question 8
A New York City hotel surveyed its visitors to determine which type of transportation they used to get around the city. The hotel created a table of the data it gathered.
Type of Transportation Number of Visitors
Walk 120
Bicycle 24
Car Service 45
Bus 30
Subway 81
Which of the following circle graphs correctly represents the data in the table?
circle graph titled New York City visitor's transportation, with five sections labeled walk 80 percent, bus 16 percent, car service 30 percent, bicycle 20 percent, and subway 54 percent
circle graph titled New York City visitor's transportation, with five sections labeled walk 40 percent, bicycle 8 percent, car service 15 percent, bus 10 percent, and subway 27 percent
circle graph titled New York City visitor's transportation, with five sections labeled subway 40 percent, bus 8 percent, car service 15 percent, bicycle 10 percent, and walk 27 percent
circle graph titled New York City visitor's transportation, with five sections labeled subway 80 percent, bicycle 20 percent, car service 30 percent, bus 16 percent, and walk 54 percent
Question 9
A college cafeteria is looking for a new dessert to offer its 4,000 students. The table shows the preference of 225 students.
Ice Cream Candy Cake Pie Cookies
81 9 72 36 27
Which statement is the best prediction about the scoops of ice cream the college will need?
The college will have about 480 students who prefer ice cream.
The college will have about 640 students who prefer ice cream.
The college will have about 1,280 students who prefer ice cream.
The college will have about 1,440 students who prefer ice cream.
Question 10
The box plots display measures from data collected when 20 people were asked about their wait time at a drive-thru restaurant window.
A horizontal line starting at 0, with tick marks every one-half unit up to 32. The line is labeled Wait Time In Minutes. The box extends from 8.5 to 15.5 on the number line. A line in the box is at 12. The lines outside the box end at 3 and 27. The graph is titled Super Fast Food.
A horizontal line starting at 0, with tick marks every one-half unit up to 32. The line is labeled Wait Time In Minutes. The box extends from 9.5 to 24 on the number line. A line in the box is at 15.5. The lines outside the box end at 2 and 30. The graph is titled Burger Quick.
Which drive-thru typically has more wait time, and why?
Burger Quick, because it has a larger median
Burger Quick, because it has a larger mean
Super Fast Food, because it has a larger median
Super Fast Food, because it has a larger mean
Answer:
B
B
A
B
D
C
Step-by-step explanation:
5. B
65 = teachers
15 = principal
65/80 = 81.25
If there's is a total of 900 people, find 81.25 (number of teachers)
=731.25
=731
6. B
The best graphical representation for the teacher's data would be a histogram. A histogram is a graph that displays the distribution of continuous data, such as the number of students who prefer a particular subject. It shows the frequency of each interval, or bin, of values.
A stem-and-leaf plot is typically used for small datasets and displays each data point. A circle graph, also known as a pie chart, is used to show how different parts make up a whole and is not appropriate for showing the distribution of preferences among the students. A box plot, also known as a box-and-whisker plot, is used to display the distribution of data, but it may not be as useful for showing the specific frequencies of each preference as a histogram would be.
7) A
There's an image for it I attached
8) B
The correct circle graph that represents the data in the table is option B) circle graph titled New York City visitor's transportation, with five sections labeled walk 40 percent, bicycle 8 percent, car service 15 percent, bus 10 percent, and subway 27 percent.
In the given table, the number of visitors for each type of transportation is given. To create a circle graph, we need to convert the given numbers to percentages. Then, we can use these percentages to determine the angle of each section in the circle graph.
Using the given numbers, we can calculate the percentage of visitors for each transportation type as follows:
Walk: (120/300) x 100 = 40%
Bicycle: (24/300) x 100 = 8%
Car Service: (45/300) x 100 = 15%
Bus: (30/300) x 100 = 10%
Subway: (81/300) x 100 = 27%
Option B) correctly represents these percentages in a circle graph.
9) D
The best prediction about the scoops of ice cream the college will need is option D) The college will have about 1,440 students who prefer ice cream.
To make this prediction, we need to use the information given in the table and assume that the entire student body has the same preferences as the sample of 225 students.
According to the table, 81 out of 225 students prefer ice cream.
To estimate the number of students who prefer ice cream in the entire student body of 4,000 students, we can use proportions.
81/225 = x/4000
Multiplying both sides by 4000, we get:x = 81/225 x 4000 = 1,440
Therefore, the college will have about 1,440 students who prefer ice cream, and they will need to prepare that many scoops.
10) C
The drive-thru that typically has more wait time is option C) Super Fast Food, because it has a larger median.
The median is the middle value when a set of data is arranged in order. In this case, the median wait time for Super Fast Food is 12 minutes, and the median wait time for Burger Quick is 15.5 minutes.
This means that half of the customers at Super Fast Food waited less than 12 minutes, while half of the customers at Burger Quick waited less than 15.5 minutes.
Therefore, the wait time at Super Fast Food is typically shorter than at Burger Quick.
The mean, on the other hand, is influenced by outliers or extreme values, and it is not as robust a measure of central tendency as the median. Therefore, we cannot determine which drive-thru typically has more wait time based on the mean alone.
The diameter of a circle is 13 cm. What is the radius of the circle?
Answer:
The Radius is 6.5 cm.
Step-by-step explanation:
We know that the diameter of a circle is a line that begins on one point of a circle and ends on the opposite side. We also know that the radius is a point on the circle that starts from that point and ends at the center. Therefore, the radius would be half the diameter.
\(13/2 = 6.5\)
Hope this helped :D!
Given the following segment lengths, find the length of segment AB.
AC : 10
EC : 16
ED :4
Show all your work
2.5 is the length of segment AB.
What is line segment ?
A line segment in geometry has two unique points on the line that define its boundaries. Or, a line segment is a section of the line that links two points, as another alternative.
In contrast to a line, which has no endpoints and can go on forever, a line segment has two distinct endpoints that are fixed or identifiable.
BD ║ AE
Δ CBD ≈ ΔCAE by AA similarity corresponding sides are proportional .
CB/CA = CD/DE ⇒ CB/10 = EC - ED/16
CB/10 = 16 - 4/16 ⇒ CB/10 = 12/16
CB = 12 * 10/16 = 7.5
AB= AC - CB = 10 - 7.5
AB = 2.5
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problem 1.)
question. there is a function h(t) that will give a ball's height in terms of the time t since it was launched. Soecifially, if t is in secinds and h(t) is in feet, then h(t) = -16t^2 + 160t + 176
Question 1
What is the initial height of the ball?
Question 2
b. ) How long does it take the ball to reach the maximum height?
Question 3
Using the EQUATION, find the exact maximum height.
Question 4
What is the height of the rocket at 3 seconds
______________________
Problem 2
y = x^2 - 4x + 7
Opens;
Vertex;
Min. or Max.:
Axis of Symm:
y-intercept:
Roots:
Domain:
Range:
______________________
problem 3
y = - 2x^2 - 20x - 51
Opens:
Vertex:
Min. or Max.:
Axis of Symm:
y-intercept:
Zeros:
Domain:
Range:
______________________
problem 4
y = x^2 - 7
Opens:
Vertex:
Min. or Max.:
Axis of Symm:
y-intercept:
Solutions:
Domain:
Range:
______________________
problem 5
y = - x^2 + 6x
Opens:
Vertex:
Min. or Max.:
Axis of Symm:
y-intercept:
x-intercepts:
Domain:
Range:
For the given quadratic function:
1) The initial height is 176 ft.
2) The time is 5 seconds.
3) The maximum height is 576 ft
4) The heigth is 512 ft
How to find the initial height of the ball?Here we have the quadratic equation:
h(t) =-16t² + 160t + 176
That models the height.
The initial height is what we get when we evaluate in t = 0, we will geT:
initial height = 16*0² + 160*0 + 176 = 176
2) The maximum height is at the vertex, it is at:
t = -160/(2*-16) = 5
So it takes 5 seconds
3) Evaluating in t = 5 we will get:
h(5) = -16*5² + 160*5 + 176 = 576 ft
So the maximum height is 576 ft.
4) The height at t = 3 seconds is:
h(3) = -16*3² + 160*3 + 176 = 512 ft
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Please help my test is this week ;/
The perimeters of a square and a rectangle are equal. One side of the rectangle is 11 cm and the area of the square is 4 cm2
more than the area of the rectangle. Find the side of the square.
The answer is X= 9 cm or X= 13 cm
Step-by-step explanation:
Let x=one side of the square; y=one side of the rectangle:
The perimeters are equal, so 4x=2y+22, or y=2x-11. The areas are given by x^2, and 11(2x-11). Since the square is 4 cm^2 larger than the rectangle, we get:
x^2-4=11(2x-11)
x^2-4=22x-121
x^2-22x+117=0
(x-13)(x-9)=0
x=13, or 9
Plugging 13 into our original equation, we get a square 13X13 or 169cm^2, and a rectangle (26-11)X 11, or 165cm^2, which satisfies our requirements!!!!!!
Find the area of a hexagon with an apothem of 15in(the height)
The area of the regular polygon with an apothem of 15 inches will be 2338.27 square inches.
What is the area of the regular polygon?Let 'a' be the apothem and 'b' be the regular side length.
Then the area of the regular polygon will be
A = 3 × a × b
We know that each angle of the regular hexagon is 60°.
Then the base length is given as,
b = 2a tan θ
b = 2 x 15 x tan 60°
b = 51.96 in
Then the area of the regular hexagon is given as,
A = 3 × a × b
A = 3 × 15 × 51.96
A = 2338.27 square inches
The area of the regular polygon with an apothem of 15 inches will be 2338.27 square inches.
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3(3x + 2) - 2x = 7x + 6
whats x?
Answer:
Step-by-step explanation:
3(3x + 2) - 2x = 7x + 6
distribute
6x+6=7x+6
get all of your x's on the same side
6x+6=7x+6
-6x -6x
6=x+6
Subtract 6 from both sides
6=x+6
-6 -6
0=x
The function f : Z x Z → Z x Z defined by the formula f(m,n) = (5m+4n, 4m+3n) is bijective. Find its inverse.
The function f : Z x Z → Z x Z defined by \(f(m,n) = (5m+4n, 4m+3n)\) is bijective, with its inverse given by \(f^{-1}(m,n) = (-3m + 4n, 4m - 5n)\). This means that for every pair of integers (m,n), the function f maps them uniquely to another pair of integers, and the inverse function \(f^{-1}\) maps the resulting pair back to the original pair.
The inverse of the function f(m,n) = (5m+4n, 4m+3n) is \(f^{-1}(m,n) = (-3m + 4n, 4m - 5n)\).
To show that the function f is bijective, we need to prove both injectivity (one-to-one) and surjectivity (onto).
Injectivity:
Assume f(m1, n1) = f(m2, n2), where (m1, n1) and (m2, n2) are distinct elements of Z x Z.
Then, (5m1 + 4n1, 4m1 + 3n1) = (5m2 + 4n2, 4m2 + 3n2).
This implies 5m1 + 4n1 = 5m2 + 4n2 and 4m1 + 3n1 = 4m2 + 3n2.
By solving these equations, we find m1 = m2 and n1 = n2, proving injectivity.
Surjectivity:
Let (a, b) be any element of Z x Z. We need to find (m, n) such that f(m, n) = (a, b).
By solving the equations 5m + 4n = a and 4m + 3n = b, we find m = -3a + 4b and n = 4a - 5b.
Thus, f(-3a + 4b, 4a - 5b) = (5(-3a + 4b) + 4(4a - 5b), 4(-3a + 4b) + 3(4a - 5b)) = (a, b), proving surjectivity.
Since the function f is both injective and surjective, it is bijective. The inverse function \(f^{-1}(m, n) = (-3m + 4n, 4m - 5n)\) is obtained by interchanging the roles of m and n in the original function f.
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sppose you have the following information about a regression s(e) = 2.16 for the slope estimate (b1), what is the 95
For the given regression parameters, the 95% confidence interval is (-0.35, 1.25). Therefore, the correct option is A.
To calculate the 95% confidence interval for the slope estimate (b1), we will use the standard error (s(e)), the slope (b1), the standard deviation of x (s(x)), and the sample size (n).
1. First, we need to find the t-value for a 95% confidence interval with 8 degrees of freedom (n-1 = 9-1 = 8). You can find this value using a t-distribution table or an online calculator, which gives a t-value of approximately 2.306.
2. Next, we calculate the margin of error by multiplying the t-value by the standard error of the slope estimate. Margin of error = t-value * s(e) = 2.306 * 2.16 ≈ 4.98096.
3. Now, we can calculate the confidence interval by adding and subtracting the margin of error from the slope estimate (b1):
Lower bound = b1 - margin of error = 0.45 - 4.98096 ≈ -0.35
Upper bound = b1 + margin of error = 0.45 + 4.98096 ≈ 1.25
Thus, the 95% confidence interval for the slope estimate (b1) is (-0.35, 1.25), which corresponds to option A.
Note: The question is incomplete. The complete question probably is: Suppose you have the following information about a regression. s(e) = 2.16 b1 = 0.45 s(x) = 2.25 n = 9 For the slope estimate (b1), what is the 95% confidence interval? a. (-0.35, 1.25) b. (-2.61, 3.51) c.(0.36, 0.54) d. (0.11, 0.79).
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Evaluate the triple integral E xyzdV, where T is the solid tetrahedron with vertices (0, 0, 0), (1, 0, 0), (1, 1, 0), and (1, 0, 1)
To evaluate the triple integral, E xyzdV, we must integrate with respect to each of the three variables: x, y, and z. Let's begin by finding the limits of integration for each of these three variables.
For the x variable, we will integrate from 0 to 1 since all of the x-values of the vertices of the tetrahedron lie within that range. For the y variable, we will integrate from 0 to 1 since the y-values of the vertices of the tetrahedron lie within that range. For the z variable, we will integrate from 0 to 1 since the z-values of the vertices of the tetrahedron lie within that range.The integral can now be written as:
E xyzd
V = ∫₀¹ ∫₀¹ ∫₀¹ xyz dzdydx
By evaluating the integral, we get:
E xyzdV = 1/6.
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A basketball team scored 50 points in a game last week. This week, they scored 55 points. What was the percent increase in points scored from last week to this week?
Sketch the following and then find the sum of the vertex
angles.
a. A hexagon
b. An octagon
c. A dodecagon.
To find the sum of the vertex angles in various polygons, we need to sketch the polygons and then calculate the sum. For a hexagon, octagon, and dodecagon, the sums of the vertex angles are 720°, 1,080°, and 1,800°, respectively.
a. Hexagon: A hexagon is a polygon with six sides. To find the sum of the vertex angles, we can divide the hexagon into triangles. Since each triangle has an interior angle sum of 180°, the hexagon can be divided into four triangles. Therefore, the sum of the vertex angles in a hexagon is 4 * 180° = 720°.
b. Octagon: An octagon is a polygon with eight sides. Similar to the hexagon, we can divide the octagon into triangles. Dividing it into six triangles, each with an interior angle sum of 180°, the sum of the vertex angles in an octagon is 6 * 180° = 1,080°.
c. Dodecagon: A dodecagon is a polygon with twelve sides. Dividing it into ten triangles, each with an interior angle sum of 180°, the sum of the vertex angles in a dodecagon is 10 * 180° = 1,800°.
Therefore, the sum of the vertex angles in a hexagon is 720°, in an octagon is 1,080°, and in a dodecagon is 1,800°.
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Find the sum of the vertex angles of the following polygons---
a. A hexagon
b. An octagon
c. A dodecagon.
How many workers will be needed to complete a task in 6 days, given that it takes 8 days for 3 workers to complete the same task?
Answer:
4
Step-by-step explanation:
8*3 = 24
24/6 = 4
help help help helpppppp
The maximum of a - b, given the values of a and b, would be 78.785.
How to find the maximum difference ?The maximum difference between a and b can be found by looking for the difference between the largest possible value for a and the smallest possible value for b.
Maximum value of a because it was rounded off would be:
80. 0 + 0. 05 = 80. 05
Smallest possible value of b would then be:
1. 27 - 0. 005 = 1. 265
The maximum difference between a and b is:
= 80. 05 - 1. 265 = 78. 785
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Given that £1 = $1.58
a) How much is £920 in $?
b) How much is $553 in £?
Answer:
a) $1453.60
b) £350
Step-by-step explanation:
A:
\(\frac{1}{1.58} = \frac{920}{x}\) 1.58 × 9201453.60B:
\(\frac{1}{x} = \frac{1.58}{553}\) 553 ÷ 1.58 = 350350 × 1 = £350A man gave 35% of his money to his elder on and 40% of the remainder to the younger son.Now, he is left with 11700 rupees.How much money had he?
A number, d, is increased by 73% to give
4152.
Work out the original value of d.
Answer:
2400
Step-by-step explanation:4152 is just 173% of d.
We create an equation d = 4152/1.73
after solving you get 2400.
Bernie can eat 20 oreos in 5 minutes. If Joe can eat oreos at 3/4
of Bernie’s pace, how many oreos can they eat together in half an hour?
a.200
b. 210
c. 220
d. 230
Answer:
b
Step-by-step explanation:
PLSSSS HELP ASAP!!!!!
It's 360 feet (The person above)
Answer:
360 ft squared
Step-by-step explanation:
you have 3 (2 shapes but one is done twice)
2 rectangles and a larger rectangle
the 2 rectangles
3 is the width, and 15 is the length
15*3 = 45 * 2 (for the other one)
and you get 90ft squared
then you have the larger rectangle. it is 15 feet wide and 18 in length (15+3)
15*18 = 270
270 ft squared + 90 ft squared = 360 ft squared
Bilquis wants to ride her bicycle 47.6 miles this week. She has already ridden 8 miles. If she rides for 6 more days, what is the average number of miles she would have to ride each day to meet her goal?
If she rides for 6 more days, what is the average number of miles she would have to ride each day to meet her goal is 4.7
We have given that,
Bilquis wants to ride her bicycle 47.6 miles this week. She has already ridden 8 miles.
We have to determine that If she rides for 6 more days, what is the average number of miles she would have to ride each day to meet her goal.
Based on the given conditions, formulate: 8+4x=26
Rearrange unknown terms to the left side of the equation:4x=26-8
Calculate the sum or difference:4x=18
Divide both sides of the equation by the coefficient of the variable:4x/4=18/4
Calculate the product or quotient:x=18/4
We get the result:4.7
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Answer: The answer is 6.6
Step-by-step explanation:
I need help plzzzz percent equations blank% of $30 =3
Answer:
10%
Step-by-step explanation:
Hello I can help you with this question. Lets start.
The question is asking what percent of $30 is 3
so i think u actually meant $3 right but anyways
30 is 10 times 3
then clearly it would be 10%
gogo that's the answer!
What is the domain and range of d(x)=|x|-4
Answer:
Domain = (-∞,∞) { x|x∈R}
Range = { -4 , ∞} , { y|y≥-4}
Step-by-step explanation:
can someone answer not just use my points
Answer:
35
Step-by-step explanation:
Well if m<YVW = (12x-1) and x=3 then just plug in x
So,
m<YVW = (12(3)-1)
m<YVW = 36-1
m<YVW = 35
In 2011, the moose population in a park was measured to be 5,800. By 2017, the population was measured again to be 8,000. If the population continues to change exponentially, find an equation for the moose population, P, as a function of t, the years since 2011.What does your model from above predict the moose population to be in 2022?
This problem asks to:
a) Find a model to predict the population P as a function of t (years since 2011).
b) Predict the population in 2022.
To find this information, follow the steps below.
Step 1: Write a general equation for populational growth.
The population growth can be represented as:
\(P=P_0\cdot e^{r\cdot t}\)Where:
P is the population in time t;
Po is the initial population;
r is the rate of growth;
t is the time.
Step 2: Write the equation that represents the moose population.
Since the problems aks to evaluate the population from 2011. Use the population in 2011 as the initial population.
Then, P0 = 5,800.
\(P=5,800\cdot e^{r\cdot t}\)Now, to find r, use the information for 2017.
In 2017,
P = 8,000
t = 6 (2017 - 2011)
Then,
\(\begin{gathered} 8,000=5,800\cdot e^{r\cdot6} \\ \end{gathered}\)To isolate r, first divide both sides by 5,800:
\(\begin{gathered} \frac{8,000}{5,800}=e^{r\cdot t} \\ \frac{80}{58}=e^{r\cdot t} \\ \end{gathered}\)Take the ln from both sides.
\(\begin{gathered} \ln (\frac{40}{29})=\ln e^{6r} \\ \text{ Using the properties of ln:} \\ \ln (\frac{40}{29})=6r\cdot\ln e \\ \ln (\frac{40}{29})=6r\cdot1 \\ \ln (\frac{40}{29})=6r \end{gathered}\)Divide both sides by 6:
\(\begin{gathered} \frac{6r}{6}=\frac{\ln (\frac{40}{29})}{6} \\ r=\frac{\ln(\frac{40}{29})}{6} \\ or \\ r=\frac{0.3216}{6}=0.0536 \end{gathered}\)So,
(a) The equation that represents the moose population over the years is:
\(P=5,800\cdot e^{0.0536\cdot t}\)Step 3: Predict the population in 2022.
In 2022,
t = 11 (2022 - 2011).
Then,
\(\begin{gathered} P=5,800\cdot e^{0.0536\cdot t} \\ P=5,800\cdot e^{0.0536\cdot11} \\ P=5,800\cdot e^{0.5895} \\ P=5,800\cdot1.8032 \\ P=10,458.6 \\ P=10,459 \end{gathered}\)(b) The moose population in 2022 will be 10,459.
Answer:
(a)
\(P=5,800\cdot e^{0.0536\cdot t}\)(b) 10,459.
In a control chart application, we have found that the grand average over all the past samples of 6 units is X-Double Bar = 25 and R-Bar = 5.
a) Set up X-bar and R Control charts.
A2= 483 D3=0 D4=2.004
.483*5=2.415+25=27.415=UCL
.485*5=25-2.415=22.585=LCL
LCL(R bar)=0
UCL=10.020
b) The following measurements are taken from a new sample: 33, 37, 25, 35, 34 and 32. Is the process still in control?
Based on the given data, the process is out of control.
To determine if the process is still in control, we need to compare the new sample measurements to the control limits established in the X-bar and R control charts.
For the X-bar chart:
The UCL (Upper Control Limit) is calculated as the grand average (X-Double Bar) plus A2 times R-Bar:
UCL = 25 + (0.483 * 5) = 27.415
The LCL (Lower Control Limit) is calculated as the grand average (X-Double Bar) minus A2 times R-Bar:
LCL = 25 - (0.483 * 5) = 22.585
For the R chart:
The UCL (Upper Control Limit) for the R chart is calculated as D4 times R-Bar:
UCL = 2.004 * 5 = 10.020
The LCL (Lower Control Limit) for the R chart is 0.
Given the new sample measurements: 33, 37, 25, 35, 34, and 32, we can determine if any of the measurements fall outside the control limits. If any data point falls outside the control limits, it indicates that the process is out of control.
Upon comparing the new sample measurements to the control limits, we find that the measurement 37 exceeds the UCL of the X-bar chart. Therefore, the process is considered out of control.
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HELP HELP HELP plsssdss
Answer:
the lines are perpindicular
Step-by-step explanation:
Write 2 equation of the given line that pae through the point one hould be parallel an the other hould be perpindicular to the givin line
The equation of the line parallel to 3x-2y is:
2y-3x=0
Given in the question:
Equation of the line parallel is: 3x-2y=0
Property: We know through the property of the slopes, that the slope of two parallel line are equal.
m1=m2
Let the slope of the given line be denoted as m1.
Then, from the equation:
3x-2y=0
3x=2y
y=3/2x+0
comparing it to the standard equation of a straight line: y=mx+c
we get,
m1=3/2
then from the property
m1=m2
Then, m2=3/2
Let the point be P(4,6)
The the equation of the straight line parallel to the line 3x-2y is:
y=mx+c
y-y1=m(x-x1)
y-6=3/2(x-4)
cross multiplying
2(y-6)=3(x-4)
2y-12=3x-12
2y-3x=12-12
2y-3x=0
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Major league baseball game durations are normally distributed with a mean of 180 minutes and a standard deviation of 45 minutes. What is the probability of a game duration of fewer than 210 minutes
The probability of a game duration of fewer than 210 minutes is 0.7486, or 74.86%.
To find the probability of a game duration of fewer than 210 minutes, we need to calculate the z-score and then use the standard normal distribution table.
First, we calculate the z-score using the formula: z = (x - mean) / standard deviation.
In this case, x = 210 minutes, mean = 180 minutes, and standard deviation = 45 minutes.
z = (210 - 180) / 45
z = 30 / 45
z = 0.67
Next, we look up the z-score of 0.67 in the standard normal distribution table. The table gives us the probability corresponding to the z-score.
From the table, we find that the probability corresponding to a z-score of 0.67 is 0.7486.
Therefore, the probability of a game duration of fewer than 210 minutes is 0.7486, or 74.86%..
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The probability of a major league baseball game lasting fewer than 210 minutes is approximately 74.86%.
The duration of major league baseball games is normally distributed with a mean of 180 minutes and a standard deviation of 45 minutes. To find the probability of a game lasting fewer than 210 minutes, we need to calculate the z-score and use the standard normal distribution table.
First, we calculate the z-score using the formula:
z = (x - mean) / standard deviation
Here, x represents the desired game duration, which is 210 minutes in this case. Plugging in the values, we get:
z = (210 - 180) / 45
z = 30 / 45
z = 0.67
Next, we look up the corresponding probability for the z-score of 0.67 in the standard normal distribution table. The table tells us that the probability associated with this z-score is 0.7486.
Therefore, the probability of a game duration of fewer than 210 minutes is 0.7486 or 74.86%.
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solve the system of equations algebraically -5x+2y=4 2x+3y=6
Step-by-step explanation:
-5x+2y= 4 <==== Multiply entire equation by -3 to get:
15x-6y = -12
2x+3y= 6 <==== Multiply entire equation by 2 to get :
4x+6y = 12 Add the two underlined equations to eliminate 'y'
19x = 0 so x = 0
sub in x = 0 into any of the equations to find: y = 2
(0,2)