The graph shows the decay of two different radioactive nuclei, Source A and Source B.
How long does it take Source B to complete two half-lives?

a. 10 s
b. 5 s
c. 40 s
d. 20 s

The Graph Shows The Decay Of Two Different Radioactive Nuclei, Source A And Source B.How Long Does It

Answers

Answer 1

It takes source B 40 s to complete two half lives.

What is the half life?

The half-life of a chemical is the amount of time it takes for half of the atoms in a sample to decay. This concept is widely used to describe how quickly a substance decays radioactively in nuclear physics and radiochemistry. Each radioactive substance has a unique half-life due to the properties of each atomic nucleus.

Looking at the graph, we can see that the half life of the source B is 20s .

Hence the time taken to complete two half lives = 2(20 s) =  40 s.

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Related Questions

On the Moon’s surface, lunar astronauts placed a corner reflector, off which a laser beam is periodically reflected. The distance to the Moon is calculated from the round-trip time. What percent correction is needed to account for the delay in time due to the slowing of light in Earth’s atmosphere? Assume the distance to the Moon is precisely 3.84×108 m , and Earth’s atmosphere (which varies in density with altitude) is equivalent to a layer 30.0 km thick with a constant index of refraction n = 1.000293.

Answers

Answer:

\(T_d=2.8*10^-^6\%\)

Explanation:

From the question we are told that

Distance b/w Earth and the moon \(d_e=3.84×10^8 m\)

Thickness of Earth's atmosphere\(d_t=30km\)

Constant index of refraction \(n = 1.000293.\)

Generally the equation for percentage of time delay \(T_d\) is mathematically given as

\(T_d=\frac{d(n-1)}{rm}*100\%\)

\(T_d=\frac{(35*10^3)(1.000293-1)()100)}{3.674*10^8} *\%\)

\(T_d=2.8*10^-^6 \%\)

Therefore the general percentage correction needed because of tym deley is given as

\(T_d=2.8*10^-^6\%\)

Ms. Paul is standing at the top of a cliff that is 100 m tall. She kicks a rock and it gets a horizontal velocity of 15.0 m/s. Determine the range of the
projectile.

Answers

vertical motion

h=1/2 gt²

100 = 1/2 x 10 x t²

t² = 100/5 = 20

t = 2√5 s

horizontal motion

x = v.t

x = 15 x 2√5

x = 30√5 m

if a space rover has a mass of 3900 kg, then what is its weight on earth

Answers

Answer:

38 220

Explanation:

Weight =Mg

W=Mg

W = (3900)(9.8)

W = 38 220

Match the technology that uses radio waves to the field in which it is used.
research
communication
broadcasting
medicine
navigation
Correct!
AM and FM stations
CB radios
magnetic resonance imaging
global positioning system
radio telescopes

Answers

A group of students are playing tether ball and measure centripetal force on a 0.2 kg ball swung in a horizontal circle of radius 0.5 m. When the tension in the scale is 1.6 N, what is the velocity of the ball?

Answers

When the tension in the scale is 1.6 N, the velocity  of the ball is  2 meter/second.

What is centripetal force?

Centripetal force is a force that acts on a body travelling in a circle and is aimed at the center of the body's motion.

Given that mass of the ball: m = 0.2 kg.

Radius of horizontal circle : r = 0.5 m.

the tension in the scale is: F = 1.6 N.

This tension is due to centripetal force acting on the ball during rotation. Let the magnitude of velocity at that moment is v. The centripetal force on the ball is = mv²/r.

Hence, F =  mv²/r

⇒ v = √(Fr/m)

put the values and get:

v = 2 meter/second.

Hence, velocity  of the ball is  2 meter/second.

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When a 480 Hz. tuning fork and a piano key are struck together, four beats per second are heard. When a 470 Hz. tuning fork and a piano key are struck together, four beats per second are heard. What is the frequency of the piano key? unknown piano key = _____Hz 476 478 477 475

Answers

the frequency of the piano key is 476 Hz.

What is frequency?

Frequency describes the number of waves that pass a fixed place in a given amount of time. In physics, frequency is the number of waves that pass a fixed point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time.

Given, When a 480 Hz. tuning fork and a piano key being struck together, four beats per second are heard.

The frequency of the tuning fork, Nf = 480 Hz

Beats heard at this frequency, x = 4 beats/second

When a 470 Hz. tuning fork and a piano key being struck together, four beats per second are heard.

The equation for the Frequency of the piano,

Np = Nf - x

Np = 480 - 4

Np = 476 Hz

When tension has increased the frequency also increased. As the number of beats decreased, the frequency of the string must be less than 480 Hz.

Therefore, the frequency of the piano key is 476 Hz.

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Determine whether the inertia of an object changes as the object's
velocity changes.

Answers

Answer:

The inertia of an object does not change as the objects velocity changes because the inertia will remain the same as long as the mass is the same.

:

Help with homework not graded I learn best by watching you do problem

Help with homework not graded I learn best by watching you do problem

Answers

When a soccer ball is kicked with a velocity 'v' at an angle of (theta), The vertical component of the ball right it before hits the ground is

\(v_y=v\sin \theta\)

Hence, the correct answer is (C)

A single wire in the shape of a circle of radius 15 cm is carrying a current of 2.7 amps. The wire lies in the xy plane. If the wire is located within a uniform magnetic field of magnitude 0.12 Tesla, what is the net torque on the loop if the magnetic field is oriented parallel to the +x axis Torque = Nm the magnetic field is oriented to the +z axis Torque = Nm the magnetic field is oriented in the xy plane at an angle of 75 degrees from the +x axis. Torque = Nm

Answers

The magnetic field is oriented in the xy plane at an angle of 75 degrees from the +x axis, the angle between the magnetic field and the normal to the loop is 75 degrees, so the net torque on the loop is 0.203 Nm.

The net torque on a current-carrying loop in a magnetic field is given by the equation: Torque = (B × I × A × sin(theta))

where torque is the net torque on the loop, B is the magnitude of the magnetic field, I is the current in the wire, A is the area of the loop, and theta is the angle between the magnetic field and the normal to the loop.

In this case, the radius of the loop is 15 cm = 0.15 m, so the area of the loop is A = pi × r² = pi × (0.15 m)² = 0.07 m²

The current in the wire is 2.7 amps, and the magnitude of the magnetic field is 0.12 Tesla.

If the magnetic field is oriented parallel to the +x axis, the angle between the magnetic field and the normal to the loop is 0 degrees, so the net torque on the loop is: Torque = (0.12 Tesla × 2.7 amps × 0.07 m² × sin(0)) = 0 Nm

If the magnetic field is oriented to the +z axis, the angle between the magnetic field and the normal to the loop is 90 degrees, so the net torque on the loop is: Torque = (0.12 Tesla × 2.7 amps × 0.07 m² × sin(90)) = 0.252 Nm

If the magnetic field is oriented in the xy plane at an angle of 75 degrees from the +x axis, the angle between the magnetic field and the normal to the loop is 75 degrees, so the net torque on the loop is: Torque = (0.12 Tesla × 2.7 amps × 0.07 m² × sin(75)) = 0.203 Nm

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You stay up all night to study for a test but feel fairly energized in the morning.
Why?

Answers

The excitement and stress of the test release adrenaline, temporarily boosting energy levels despite the lack of sleep.

Staying up all night to study for a test and still feeling fairly energized in the morning can be attributed to several factors. Firstly, the human body has a natural circadian rhythm, a biological process that regulates sleep-wake cycles over a 24-hour period. While staying up all night disrupts this rhythm, the body can still adapt and find temporary energy reserves to keep you awake and alert.

Secondly, the excitement or stress associated with an impending test can release adrenaline and other stress hormones, which can temporarily boost energy levels and promote wakefulness. These hormones activate the body's "fight-or-flight" response, increasing heart rate and alertness.

Additionally, individual differences in sleep needs and sleep quality can play a role. Some people naturally require less sleep than others and can function relatively well on limited rest. If you happen to be one of these individuals, you may feel more energized despite the lack of sleep.

It's important to note, however, that even if you feel energized initially, sleep deprivation can have negative effects on cognitive function, memory retention, and overall performance. While you may feel fine in the morning, the consequences of sleep deprivation can catch up with you later in the day.

In summary, feeling fairly energized after staying up all night to study for a test can be attributed to the body's temporary adaptations, the release of stress hormones, individual differences in sleep needs, and the initial excitement surrounding the upcoming event. However, it is crucial to prioritize regular and sufficient sleep for optimal cognitive functioning and overall well-being.

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How does the law of conservation of mass apply to chemical reactions?

Answers

Answer: mass is neither created nor destroyed

Explanation: For example, the carbon atom in coal becomes carbon dioxide when it is burned. The carbon atom changes from a solid structure to a gas but its mass does not change.

a crane lifts a 75 kg mass at a height of 8m . calculate the gravitational potential energy gained by the mass (g= 10N)

Answers

Advice: Search up your questions in the Brainly search bar before asking your questions.

PLEASE HELP I WROTE THIS LIKE 200 TIMES

Plate boundaries represent parts of the Earth where plates come in contact with one another. There are different ways in which these plates can move and interact. In this assignment, you will identify each type of plate movement and create an illustration to represent this.

PLEASE HELP I WROTE THIS LIKE 200 TIMESPlate boundaries represent parts of the Earth where plates come

Answers

Plate boundaries represent the parts of the Earth's crust where plates come in contact with one another. There are three types of plate boundaries based on the movement and interaction of the plates involved. These are: Divergent Plate Boundaries, Convergent Plate Boundaries, and Transform Plate Boundaries.



Divergent Plate Boundaries
At divergent plate boundaries, two plates move away from each other as magma rises to the surface and creates new crustal material. Examples of divergent plate boundaries include the Mid-Atlantic Ridge, the East Pacific Rise, and the African Rift Valley.

Convergent Plate Boundaries
At convergent plate boundaries, two plates move toward each other and eventually collide. Depending on the type of plate involved, different types of interactions can occur. The three types of convergent plate boundaries are oceanic-continental, oceanic-oceanic, and continental-continental. An example of oceanic-continental convergence is the Pacific Northwest region of the United States. An example of oceanic-oceanic convergence is the Japanese Islands, and an example of continental-continental convergence is the Himalayas.

Transform Plate Boundaries
At transform plate boundaries, two plates move past each other in a horizontal direction. These boundaries are characterized by faults and earthquakes, such as the San Andreas Fault in California.

To create an illustration that represents each type of plate movement, you can draw a diagram that shows the direction of plate movement, the type of boundary, and any notable geological features associated with that type of boundary.

For example, a divergent plate boundary illustration could include a depiction of magma rising to the surface and creating new crustal material, while a transform plate boundary illustration could include a fault line and a depiction of the earthquakes that occur along that boundary.

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a train is traveling at 50km/h average .what is the displacement of the train per second?​

Answers

0.013888888888889
I believe this is the answer

In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression, x = 8.00 cos 5t + π 8 where x is in centimeters and t is in seconds. (a) At t = 0, find the position of the piston. cm (b) At t = 0, find velocity of the piston. cm/s (c) At t = 0, find acceleration of the piston. cm/s2 (d) Find the period and amplitude of the motion. period s amplitude cm

Answers

Question:

In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression, x = 8.00 cos (5t + π / 8) where x is in centimeters and t is in seconds. (a) At t = 0, find the position of the piston. cm (b) At t = 0, find velocity of the piston. cm/s (c) At t = 0, find acceleration of the piston. cm/s2 (d) Find the period and amplitude of the motion. period s amplitude cm

Answer:

(a) 7.392cm

(b) -15.32 cm/s

(c) -184cm/s²

(d) 0.4πs and 8.00cm

Explanation:

The general equation of a simple harmonic motion (SHM) is given by;

x(t) = A cos (wt + Φ)        --------------(i)

Where;

x(t) = position of the body at a given time t

A =  amplitude or maximum displacement during oscillation

w = angular velocity

t = time

Φ = phase constant.

Given from question:

x(t) = 8.00 cos (5t + π / 8)         ---------------(ii)

(a) At time t = 0;

The position, x(t), of the body (piston) is given by substituting the value of t = 0 into equation (ii) as follows;

x(0) = 8.00 cos (5(0) + π / 8)

x(0) = 8.00 cos (π /8)

x(0) = 8.00 x 0.924

x(0) = 7.392 cm

Therefore, the position of the piston at time t = 0 is 7.392cm

(b) To get the velocity, v(t), of the piston at t = 0, first differentiate equation (ii) with respect to t as follows;

v(t) = \(\frac{dx(t)}{dt}\)

v(t) = \(\frac{d(8.00cos(5t + \pi / 8 ))}{dt}\)

v(t) = 8 (-5 sin (5t + π / 8))

v(t) = -40sin(5t + π / 8)     --------------------(iii)

Now, substitute t=0 into the equation as follows;

v(0) = -40 sin(5(0) + π / 8)

v(0) = -40 sin(π / 8)

v(0) = -40 x 0.383

v(0) = -15.32 cm/s

Therefore, the velocity of the piston at time t = 0 is -15.32 cm/s

(c) To find the acceleration a(t) of the piston at t = 0, first differentiate equation (iii), which is the velocity equation, with respect to t as follows;

a(t) = \(\frac{dv(t)}{dt}\)

a(t) = \(\frac{d(-40sin (5t + \pi /8))}{dt}\)

a(t) = -200 cos (5t + π / 8)

Now, substitute t = 0 into the equation as follows;

a(0) = -200 cos (5(0) + π / 8)

a(0) = -200 cos (π / 8)

a(0) = -200 x 0.924

a(0) = -184.8 cm/s²

Therefore, the acceleration of the piston at time t = 0 is -184cm/s²

(d) To find the period, T, first, let's compare equations (i) and (ii) as follows;

x(t) = A cos (wt + Φ)                   --------------(i)

x(t) = 8.00 cos (5t + π / 8)         ---------------(ii)

From these equations it can be deduced that;

Amplitude, A = 8.00cm

Angular velocity, w = 5 rads/s

But;

w = \(\frac{2\pi }{T}\)           [Where T = period of oscillation]

=> T = \(\frac{2\pi }{w}\)

=> T = \(\frac{2\pi }{5}\)

=> T = 0.4π s

Therefore, the period and amplitude of the piston's motion are respectively 0.4πs and 8.00cm

10. Refraction occurs...
A. only with light waves
B. at any, unpredictable time
C. when a wave changes speed
D. only at a wave front
E. All of the above

Answers

The answer is C! Good luck!

1. A Ograph A Ograph B Ograph c Which graph represents what happens to the pressure in a tire as air is added to the tire, assuming the temperature is constant? ​

1. A Ograph A Ograph B Ograph c Which graph represents what happens to the pressure in a tire as air

Answers

Answer:

Explanation:

It's graph A because the pressure in the tire is increasing as the amount of air going into it increases. B says the pressure drops exponentially as air goes in, and C says that the pressure stays the same as air goes in. Pressure in a tire increases proportionally to the amount of air in it.

describe the relation among density, temperature, and volume when the pressure is constant, and explain the blackbody radiation curve

Answers

Answer:

in all cases with increasing temperature the density should decrease.

Black body radiation is a construction that maintains a constant temperature and a hole is opened, this hole is called a black body,

Explanation:

Let's start for ya dream gas

        PV = nRT

Since it indicates that the pressure is constant, we see that the volume is directly proportional to the temperature.

The density of is defined by

        ρ = m / V

As we saw that volume increases with temperature, this is also true for solid materials, using linear expansion. Therefore in all cases with increasing temperature the density should decrease.

Black body radiation is a construction that maintains a constant temperature and a hole is opened, this hole is called a black body, since all the radiation that falls on it is absorbed or emitted.

This type of construction has a characteristic curve where the maximum of the curve is dependent on the tempera, but independent of the material with which it is built, to explain the behavior of this curve Planck proposed that the diaconate in the cavity was not continuous but discrete whose energy is given by the relationship

             E = h f

which ways more a quarter pound hamburger on jupiter or a 12 ounce steak on venus

Answers

Answer: 12 ounce steak on venus

Explanation: venus = closer to the sun. The sun = more potential gravity, which would make it heavier than a quarter pound hamburger on jupiter.

(a)Find the force (in N) of electrical attraction between a proton and an electron that are 7.4 ✕ 10−11 m apart.
(b)Compare this to the gravitational force between these particles. (Enter the gravitational force, in N.

Answers

The electrostatic force of attraction between the proton and electron is 4.2 x 10⁻⁸N.

The gravitational force between the proton and electron is 1.9 x 10⁻⁴⁷N.

a) Charge on proton = charge on electron = q = 1.6 x 10⁻¹⁹C

Distance between the proton and electron, r = 7.4 x 10⁻¹¹m

The electrostatic force of attraction between the proton and electron is given by,

F = 1/4πε₀(q²/r²)

F = 9 x 10⁹ x (1.6 x 10⁻¹⁹)²/(7.4 x 10⁻¹¹)²

F = 9 x 10⁹ x 2.56 x 10⁻³⁸/54.76 x 10⁻²²

F = 4.2 x 10⁻⁸N

b) Mass of the electron, m₁ = 9.1 x 10⁻³¹kg

Mass of the proton, m₂ = 1.67 x 10⁻²⁷kg

Distance between the proton and electron, r = 7.4 x 10⁻¹¹m

The gravitational force between the proton and electron is given by,

F = Gm₁m₂/r²

F = 6.67 x 10⁻¹¹x 9.1 x 10⁻³¹x 1.67 x 10⁻²⁷/(7.4 x 10⁻¹¹)²

F = 1.9 x 10⁻⁴⁷N

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The displacement (in meters) of a particle moving in a straight line is given by the equation of motion:

s = 4/t^2, where t is measured in seconds.

Required:
Find the velocity of the particle at times t = a, t = 1, t = 2, and t = 3.

Answers

Answer:

At \(t = 1\; \rm s\), the particle should have a velocity of \(-8\; \rm m \cdot s^{-1}\).At \(t = 2\; \rm s\), the particle should have a velocity of \(-1\; \rm m \cdot s^{-1}\).At \(t = 3\; \rm s\), the particle should have a velocity of \(\displaystyle -\frac{8}{27}\; \rm m \cdot s^{-1}\).

For \(a > 0\), at \(t = a \; \text{second}\), the particle should have a velocity of \(\displaystyle -\frac{8}{a^3}\; \rm m \cdot s^{-1}\).

Explanation:

Differentiate the displacement of an object (with respect to time) to find the object's velocity.

Note that the in this question, the expression for displacement is undefined (and not differentiable) when \(t\) is equal to zero. For \(t > 0\):

\(\begin{aligned}v &= \frac{\rm d}{{\rm d}t}\, [s] = \frac{\rm d}{{\rm d}t}\, \left[\frac{4}{t^2}\right] \\ &= \frac{\rm d}{{\rm d}t}\, \left[4\, t^{-2}\right] = 4\, \left((-2)\, t^{-3}\right) = -8\, t^{-3} =-\frac{8}{t^3}\end{aligned}\).

This expression can then be evaluated at \(t = 1\), \(t = 2\), and \(t = 3\) to obtain the required results.

A wheel has a radius of r = 2.0 m and it rolls down a smooth incline. The height of the incline is h = 8.0 m . What is the angular velocity ω of the wheel at the bottom of the incline?
Express your answer in radians per second.

Answers

The angular velocity of the wheel at the bottom of the incline is 4.429 rad/sec

The angular velocity (ω) of an object is the rate at which the object's angle position is changing in relation to time.

For a wheel attached to an incline angle, the angular velocity can be computed by considering the conservation of energy theorem.

As such the total kinetic energy (K.E) and rotational kinetic energy (R.K.E) at a point is equal to the total potential energy (P.E) at the other point.

i.e.

P.E = K.E + R.K.E

\(\mathbf{mgh = \dfrac{1}{2}m(r \times \omega)^2 + \dfrac{1}{2}\times I \times \omega^2}\)

\(\mathbf{gh = \dfrac{1}{2}(r \times \omega)^2 + \dfrac{1}{2}\times r^2 \times \omega^2}\)

\(\mathbf{2 \times \dfrac{gh}{r^2} =\omega^2 + \omega^2}\)

\(\mathbf{2 \omega^2=2 \times \dfrac{9.81 \times 8 m }{2.0 ^2} }\)

\(\mathbf{\omega^2=\dfrac{39.24 }{2}}\)

\(\mathbf{\omega=\sqrt{19.62 } \ rad/sec}\)

\(\mathbf{\omega=4.429 \ rad/sec}\)

Therefore, we can conclude that the angular velocity of the wheel at the bottom of the incline is 4.429 rad/sec

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The angular velocity of the wheel depends on the mass, radius and the

mode of rotation of the wheel (with or without slipping).

The angle velocity at the bottom of the incline, ω ≈ 4.43 rad/sec

Reasons:

The given parameters are;

Radius of the wheel, r = 2.0 m

Height of the incline, h = 8.0 m

Required:

Angular velocity of the wheel at the bottom of the incline.

Solution:

The potential energy of the wheel at the top of the hill, P.E. = m·g·h

\(Sum \ of \ the \ kinetic \ energy \ of \ the \ wheel, \ K.E. = \mathbf{\displaystyle \frac{1}{2} \cdot m \cdot v^2 + \frac{1}{2} \cdot I \cdot \omega ^2}\)

Where;

v = The translational velocity of the wheel = ω·r

I = The moment of inertia of the wheel = m·r²

Therefore'

\(Sum \ of \ K.E. = \displaystyle \frac{1}{2} \cdot m \cdot (\omega \cdot r)^2 + \frac{1}{2} \cdot m \cdot r^2 \cdot \omega ^2 = \mathbf{m \cdot r^2 \cdot \omega^2}\)

At the bottom of the hill, the potential energy is converted to kinetic energy

Therefore;

P.E. = Sum of K.E.

m·g·h = m·r²·ω²

g·h = r²·ω²

\(\displaystyle \omega = \sqrt{ \frac{g \cdot h}{r^2} } = \mathbf{ \frac{\sqrt{g \cdot h} }{r}}\)

Where;

g = Acceleration due to gravity ≈ 9.81 m/s²

Therefore;

\(\displaystyle \omega = \frac{\sqrt{9.81 \times 8} }{2} \approx \mathbf{ 4.43}\)

The angular velocity of the of the wheel at the bottom of the incline, ω ≈ 4.43 rad/sec

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A wheel has a radius of r = 2.0 m and it rolls down a smooth incline. The height of the incline is h

The diagram shows a charge moving into an electric field. Two horizontal parallel plates have equally spaced vectors going from the bottom plate to the top plate. A negatively charged sphere labeled Z in traveling horizontally in between the plates. A vector is pointing right. The top plate is labeled W. There is an X at the far end of the top plate and a Y at the far end of the bottom plate. The charge will most likely leave the electric field near which letter? W X Y Z

Answers

The negatively charged sphere Z is most likely to leave the electric field near the center of plates, which is closest to letter Y.

What is an electric field?

Physical field that surrounds electrically charged particles and exerts force on all the other charged particles in the field is called an electric field.

Negatively charged sphere labeled Z will experience a force due to  electric field created by parallel plates. Since the vector is pointing right, we can assume that electric field is also pointing right.

Electric field lines are perpendicular to plates and are equally spaced. Therefore, electric field is uniform in magnitude and direction between the plates.

As the negatively charged sphere Z travels horizontally between plates, it will experience force in the direction opposite to electric field due to its negative charge. This force will cause sphere to slow down and  stop.

Since the electric field lines are equally spaced between the plates, electric field will be strongest at the edges of plates and weakest in the center. Therefore, negatively charged sphere Z is most likely to leave the electric field near the center of plates, which is closest to letter Y.

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The gravitational force between two objects is 100n if the mass of each object is doubled what is the gravitational force between the objects at the same distance

Answers

Answer:

The force of gravity between the objects at the same distance is 400N (400N = 100 N x 2 x 2). This problem can be solved using the force of gravity formula which is described as Force = G x Mxm/r^2. In this formula, Force is the force of gravity, G is the constant gravity, M is the mass of the object, m is the mass of another object, and r is the distance between them.

ASAP HELPPPPPP POP PLEASE​

ASAP HELPPPPPP POP PLEASE

Answers

Answer:

The answer is in the attachment

Explanation:

!!PLEASE PLEASE PLEASE PLEASE PLEASE MARK ME THE BRAINLIEST!!

ASAP HELPPPPPP POP PLEASE

What is the Russell-Vogt theorem? Why is it important? How does it shed
light on the existence of the Main Sequence?

Answers

According to the Vogt-Russell theorem, the structure of a star in hydrostatic and thermal equilibrium with all energy produced from nuclear processes is uniquely defined by its mass and chemical element distribution throughout its interior.

Despite being called a theorem, the Vogt-Russell theorem has never been officially proven. The theorem is named for the astronomers Heinrich Vogt and Henry Norris Russell, who separately devised it.

What is the relevance of the Vogt-Russell theorem?

The Russell-Vogt Theorem, which states that the nature of a star is essentially entirely governed by its mass, age, and starting composition, explains why stars have such a well-defined brightness and temperature range while they are burning hydrogen in their interiors.

This trend is especially noticeable because the initial composition has little influence in comparison to the other two. The upper luminosity limit is caused by stars more massive than about 100 times the mass of the sun blowing themselves apart, while the lower luminosity limit is caused by objects less massive than about 0.08 times the mass of the sun failing to develop satisfactory pressure and temperature in their cores to burn hydrogen.

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Velocity and Acceleration Problem

Velocity and Acceleration Problem

Answers

Answer:

velocity is a hell of a drug treatment classes in the position you are offering to help you with your medical needs and your needs and your needs and your needs and your needs for the future and to be getting your son in a better place for the better of the richest of his family and his life in the world.

Explanation:

no exceptions

The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?

Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.

Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!

Answers

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

Learn more about earthquakes from the given link.

https://brainly.com/question/25843505

The student has a mass of 50.0 kg. What is her momentum at 2 s (in kgm/s)?

Answers

Answer:

50kgm/2

Explanation:

Extreme-sports enthusiasts have been known to jump off the top of El Capitan, a sheer granite cliff of height 910 min Yosemite National Park. Assume a jumper runs horizontally off the top of El Capitan with speed 4.0 m/sand enjoys a free fall until she is h = 150 m above the valley floor, at which time she opens her parachute.(Figure 1) A) Ignoring air resistance how long is the jumper in freefall? Please show units B) How far from the cliff is the jumper when she opens her chute? Please show units

Answers

(A) The jumper is in freefall for approximately 5.43 seconds. (B) The jumper is about 21.7 meters away from the cliff when she opens her chute.

(A) Ignoring air resistance, we can use the equations of motion to find how long the jumper is in freefall. We know that the initial vertical velocity is zero, the acceleration due to gravity is -9.81 m/s² (downward), and the displacement is h = 150 m.

The following is the motion equation for vertical displacement:

\(h = (1/2)gt^2\)

Solving for time:-

\(t = \sqrt{(2h/g)}\)

\(t = \sqrt{(2*150/9.81)}\)

t ≈ 5.43 s

Therefore, the jumper is in freefall for approximately 5.43 seconds.

(B) To find how far from the cliff the jumper is when she opens her chute, we can use the equation of motion for horizontal displacement:

d = vt

here,

d is horizontal displacement,

v is horizontal velocity (which is constant at 4.0 m/s), and

t is time in freefall (which we just found to be approximately 5.43 s).

So,

d = vt

d = (4.0 m/s)(5.43 s)

d ≈ 21.7 m

Therefore, the jumper is about 21.7 meters away from the cliff when she opens her chute.

To know more about freefall please refer: https://brainly.com/question/17067422

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