A massive object can distort the light of more distant objects behind it through the phenomenon that we call GRAVITATIONAL LENSING.
GRAVITATIONAL LENSING, WIMPS, ROTATION CURVES, ORDINARY (OR BARYONIC), LARGE-SCALE STRUCTURE , EXOTIC (OR NONBARYONIC)
A massive object can distort the light of more distant objects behind it through the phenomenon that we call GRAVITATIONAL LENSING.
WIMPS are defined as subatomic particles that have more mass than neutrinos but do not interact with light.
The ROTATION CURVES of spiral galaxies provide strong evidence for the existence of dark matter.
Matter made from atoms, with nuclei consisting of protons and neutrons, represents what we call ORDINARY (OR BARYONIC) matter.
Models show that the LARGE-SCALE STRUCTURE of the universe is better-explained when we include the effects of dark matter along with the effects of luminous matter.
Matter consisting of particles that differ from those found in atoms is generally referred to as EXOTIC (OR NONBARYONIC) matter.
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9.two ropes tied to a tree branch hold up a child swing as shown in figure 7 . the tension in each rope is 2.28N.what is the combined force (magnitude and direction) of the two ropes one the swing?
(please answer fast important)
The combined force of the two ropes on the swing is : 4.56 ∠ 77° above X -axis
Given data :
Tension in the ropes ( T ) = 2.28 N
Angle made by ropes = 13° vertical
Determine the combined force of the two ropesF ( combined force ) = T + T
= 2.28 + 2.28 = 4.56 N
from the question 13° vertical is approximately equal to 77° above the positive X-axis.
Therefore the combined force of the two ropes on the swing is : 4.56 ∠ 77° above the X-axis of the swing.
Hence can conclude that The combined force of the two ropes on the swing is : 4.56 ∠ 77° above X -axis
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Answer:
Explanation:
The combined force of the two ropes on the swing is : 4.56 ∠ 77° above X -axis
Given data :
Tension in the ropes ( T ) = 2.28 N
Angle made by ropes = 13° vertical
Determine the combined force of the two ropes
F ( combined force ) = T + T
= 2.28 + 2.28 = 4.56 N
from the question 13° vertical is approximately equal to 77° above the positive X-axis.
Therefore the combined force of the two ropes on the swing is : 4.56 ∠ 77° above the X-axis of the swing.
Hence can conclude that The combined force of the two ropes on the swing is : 4.56 ∠ 77° above X -axis
An object, initially traveling at a velocity of 52 m/s, experiences an acceleration of -9.8 m/s². How much time will it take it to come to rest? *
Answer:
5.3 s
Explanation:
Given:
v₀ = 52 m/s
v = 0 m/s
a = -9.8 m/s²
Find: t
v = at + v₀
0 m/s = (-9.8 m/s²) t + 52 m/s
t = 5.3 s
A 19.7 kg sled is pulled with a 42.0 N force at a 43.0° angle, across ground where μ₁ = 0.130.
What is the normal force on the sled?
The following information is provided in the problem: A sled with a weight of 19.7 kg is pulled with a force of 42.0 N at an angle of 43.0° across ground where μ₁ = 0.130. We need to find out the normal force that is exerted on the sled.
Let us examine each of the forces acting on the sled.The weight of the sled is equal to its mass multiplied by the acceleration due to gravity. Therefore, the weight of the sled is:mg = 19.7 kg x 9.8 m/s² = 193.06 N.The force exerted on the sled can be divided into two components: one that is parallel to the ground and one that is perpendicular to the ground.The force parallel to the ground is:F₁ = 42.0 N x cos(43.0°) = 30.56 N.The force perpendicular to the ground is:F₂ = 42.0 N x sin(43.0°) = 28.30 N.The frictional force is equal to the coefficient of friction multiplied by the normal force. Therefore, we need to find the normal force on the sled in order to calculate the frictional force. Since the sled is not accelerating vertically, the normal force is equal to the weight of the sled plus the force perpendicular to the ground. Therefore, N = mg + F₂N = 193.06 N + 28.30 N = 221.36 N.The frictional force is:Fr = μ₁ x NFr = 0.130 x 221.36 N = 28.77 N.Thus, the normal force exerted on the sled is 221.36 N.For such more question on perpendicular
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4
A box full of 35 matches has a mass of 6.77 g. The box itself has a mass of 3.37 9.
What is the mass of one match in grams?
a
Answer:
Rounded down to 2 digits, 0.10 grams.
Explanation:
6.77 - 3.37 = 3.4
3.4 / 35 = 0.09714285
The mass of one match in grams will be 0.097 g
What is unitary method ?The unitary method is a technique for solving a problem by first finding the value of a single unit and then finding the necessary value by multiplying the single unit value,
mass of 35 matches = mass of box full of matches - mass of box itself
mass of 35 matches = 6.77 g - 3.37 g
= 3.4 g
using unitary method , we can write
if 35 matches can have a mass of = 3.4 g
1 match can have a mass of = 3.4/35 g
= 0.097 g
The mass of one match in grams will be 0.097 g
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Express 48 m/s in terms of
1.km/h
2.m/min
3.km/s
4.km/minutes
48 m/s in terms of km/h is 720.8 km/h. In terms of m/min is 2880 m/min, in terms of km/s is 0.048 km/s and in terms of km/min is 2.88 km/min.
To solve this question, we need to understand some terms. The unit of velocity is measured in m/s. It can be expressed in different units of velocity.
1 km (kilometer) = 1000 meter
1 h (hour) = 3600 seconds
1 minutes = 60 seconds
To convert m/s into km/h,
48 m/s * 3600/1000 = 172.8 km/h
To convert m/s into m/min,
48 m/s * 60 = 2880 m/min
To convert m/s into km/s,
48 m/s ÷ 1000 = 0.048 km/s
To convert m/s into km/minutes,
48 m/s * 60 / 1000 = 2.88 km/min
Therefore, the 48 m/s expressed is 172.8 km/h, 2880 m/min, 0.048 km/s and 2.88 km/min.
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48 m/s is equivalent to 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.
To express 48 m/s in different units of velocity:
km/h (kilometers per hour):
To convert m/s to km/h, we can use the conversion factor of 3.6 since 1 m/s is equal to 3.6 km/h.
48 m/s * (3.6 km/h / 1 m/s) = 172.8 km/h
Therefore, 48 m/s is equivalent to 172.8 km/h.
m/min (meters per minute):
To convert m/s to m/min, we can use the conversion factor of 60 since there are 60 seconds in a minute.
48 m/s * (60 m/min / 1 s) = 2880 m/min
Therefore, 48 m/s is equivalent to 2880 m/min.
km/s (kilometers per second):
Since 1 kilometer is equal to 1000 meters, to convert m/s to km/s, we divide the value by 1000.
48 m/s / 1000 = 0.048 km/s
Therefore, 48 m/s is equivalent to 0.048 km/s.
km/minute (kilometers per minute):
To convert m/s to km/minute, we first need to convert m/s to km/s (as calculated in the previous step) and then multiply by 60 to convert seconds to minutes.
0.048 km/s * 60 = 2.88 km/minute
So, 48 m/s is equivalent to 2.88 km/minute.
Hence, 48 m/s is equivalent to approximately 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.
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A radioactive nucleus contains 128 nucleons. It emits a B-particle.
How many nucleons are now in the nucleus?
A
124
B 127
C 128
-D 129
please help!!
Kara is setting up a tee-shirt cannon for a community event. The angle of the cannon can be adjusted, but all projectiles leave the cannon at 25 meters per second. If Kara sets the angle of the cannon to be 20 degrees above horizontal, what will be the range of the projectiles?
The range of the shots(projectiles) will be around 131.65 meters when the point of the cannon is set to 20 degrees above level.
To decide the run of the shots, we have to calculate the horizontal distance that the shots will travel.
Ready to utilize the taking after kinematic condition to fathom for the run:
\(R = (v^2/g) * sin(2θ)\)
Where:
R = run
v = starting speed (25 m/s)
g = increasing speed due to gravity (9.81 m/s²)
θ = point of the cannon (20 degrees)
Substituting the given values into the condition, we get:
\(R = (25^2/9.81) * sin(2*20)\)
R = 131.65 meters
In this manner, the run of the shots will be around 131.65 meters.
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A pot of water is heated on a gas-flame stove and begins to boil. Which two
transfers of thermal energy involved in this system are examples of radiation?
O A. From the burner to air that is not touching it
B. In the surrounding air as air currents develop
C. From the burner to a nearby spoon
O D. From the water to the air
Examples of radiation are from the burner to air that is not touching it. In the surrounding air as air currents develop. The correct options are A and B.
What is radiation?Radiation is the emission or transmission of energy through a material medium or across space in the form of waves or particles. Radiation is the heat transfer method in which the heat is transferred without any direct contact between the two objects.
Given that a pot of water is heated on a gas-flame stove and begins to boil. Which two transfers of thermal energy are involved?
Here the heat is transferred through the radiation in which no direct contact is there between the two objects. The two thermal heat transfer energies are from the burner to air that is not touching it and In the surrounding air as air, currents develop.
Therefore, examples of radiation are from the burner to air that is not touching it. In the surrounding air as air currents develop. The correct options are A and B.
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which of the following containing same amount of boiling hot water is likely to cool first and why? a. a breaker whose surface is covered with aluminum foil b. a breaker whose surface is painted black
The force of the ruler on the ball is called an applied force. The force of the barrier on the ball is called a
normal force. Both of these forces are exerted by surfaces, and the direction of force is at a right angle to
the surface. The difference is that an applied force is exerted by a moving object and a normal force is
exerted by a stationary object. Draw two arrows to represent the applied force and the normal force on
the ball,
For
ments
ET
We 2 pt
barrier
ruler
The given statement states that The force of the ruler on the ball is called an applied force. The force of the barrier on the ball is called a normal force. Both of these forces are exerted by surfaces, and the direction of force is at a right angle to the surface.
The difference is that an applied force is exerted by a moving object and a normal force is exerted by a stationary object.The two arrows that represent the applied force and the normal force on the ball are as follows:Arrow 1: Applied Force - It is the force applied by the ruler on the ball. It acts in the direction of the force applied and is perpendicular to the surface of the ball.
It is represented by the arrow as shown in the figure below.Arrow 2: Normal Force - It is the force exerted by the barrier on the ball. It is perpendicular to the surface of the ball and acts in the opposite direction of the applied force. It is represented by the arrow as shown in the figure below. Main Answer:Arrow 1 - Applied ForceArrow 2 - Normal ForceTwo arrows that represent the applied force and the normal force on the ball are shown in the figure above. The direction of force is at a right angle to the surface. Both of these forces are exerted by surfaces. An applied force is exerted by a moving object, whereas a normal force is exerted by a stationary object.
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Study the ray diagram given below and select the correct option.
(a) Parallel to the incident ray
(b) Pass through F
(c) Appear to diverge from F
(d) Appear to diverge from C
Answer:
(a) Parallel to the incedent ray
An opaque object, like a piece of wood...
Select one:
a. reflects and absorbs light but does not transmit it.
b. reflects light but does not absorb it.
c. reflects, absorbs, and transmits light.
d. transmits light.
Answer:
A. reflects and absorbs light but does not transmit it
Explanation:
I'm pretty sure it's the first one
A light beam with a 70° angle of incidence travels through a medium with an index of refraction of 1.8. The light enters a second medium and has an angle of refraction of 37°. What is the index of refraction of the second medium?
Answer:
Explanation:
For refraction , the formula is
sin i / sin r = μ₂ / μ₁
where light is travelling from medium 1 to 2 having refractive index of μ₁ and μ₂ . Angle of incidence in medium 1 is i and angle of refraction in medium 2 is r .
Here i = 70°, r = 37°
μ₁ = 1.8 ,μ₂ = ?
sin70 / sin 37 = μ₂ / 1.8
.939 / .602 = μ₂ / 1.8
1.56 = μ₂ / 1.8
μ₂ = 2.81 .
The value of refraction index for the second medium will be \(\mu_2=2.16\)
What will be the refractive index?Every material has a different refractive index. The refracted index of any material shows that the light is refracted by how much angle.
So like for water its value will be different also for glass its value will be different.
Now it is given in the question that
Angle of incidence \(i=70^o\)
Refractive index of the first medium \(\mu_1=1.8\)
Angle of refraction \(r=37^o\)
Now from snells law
\(\dfrac{Sin \ i}{Sin \ r} = \dfrac{\mu_2}{\mu_1}\)
\(\dfrac{Sin70}{Sin37} = \dfrac{\mu_2}{1.8}\)
\(\mu_2= \dfrac{Sin70\times1.8}{Sin37}\)
\(\mu_2=2.16\)
Thus the value of the refraction index for the second medium will be \(\mu_2=2.16\)
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The boiling point of water is 1000 C at sea level. The boiling point of butane is -1.50C… If we leave liquid butane in a bowl on a table in a room where the temperature is 240C, butane will
A. evaporate.
B. condense.
C. freeze.
D. melt.
Answer: If we leave liquid butane in a bowl on a table in a room where the temperature is \(24^{o}C\), butane will evaporate.
Explanation:
A temperature at which the the liquid and gaseous phase of a substance of a substance are present in equilibrium with each other is called boiling point.
For example, the boiling point of butane is -1.5 degree Celsius.
This means that at a temperature above -1.5 degree Celsius, butane will exist is gaseous state. That is, at a temperature of 24 degree Celsius butane will evaporate.
Thus, we can conclude that if we leave liquid butane in a bowl on a table in a room where the temperature is \(24^{o}C\), butane will evaporate.
Mrs. Cadillac's class pulls with a force of 50.4 N. Mrs. Barr's class pulls with a force of 48.8 N. What is the net force?
The net force on the rope will be equal to 1.6 N.
What is the net force?The net force can be defined as the vector sum of forces acting on a body. The net force can be described as a single force providing same the effect as the original forces on the body's motion.
The net force acting on an object becomes the resultant force. The net force has the same effect on the motion as all actual forces taken together by the object.
Given, the applied force by Mrs. Cadillac's class = 50.4 N
The applied force by Mrs. Barr's class = 48.8 N
The net force = 50.4 N + (-48.8N) = 1.6 N
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assume an ideal-offset model with for both diodes. if , , and , find the current through the diode, and the voltage across the diode, .
In an ideal-offset model for diodes, we assume that the diodes have an infinite resistance in the reverse direction and zero resistance in the forward direction. Using this model, we can calculate the current through and voltage across the diode. If we have and in the forward direction, we can assume that the voltage across the diode is zero. This means that the current through the diode will be determined solely by the resistor value. Therefore, the current through the diode will be .
In the reverse direction, the voltage across the diode will be equal to the voltage across the resistor, which is . Since the diode has an infinite resistance in the reverse direction, no current will flow through it, and the current through the resistor will be zero.To summarize, the current through the diode in the forward direction is , and the voltage across the diode is zero. In the reverse direction, the voltage across the diode is , and no current flows through it.
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4. Jerry has approached you with a series circuit problem. He's trying to figure out the electricity for a new circuit in his house. He needs to find the total resistance. Which equation should Jerry use? A.R=R₁ + R₂ + R₂ B. R=1/R₁+1/R₂ + 1/R C. R=1/R₁ R₂ R D. R=R₁ R₂ R₂
The equation Jerry should use for the total resistance in a series circuit is R = R₁ + R₂ + R₃.
option A.
What is a series circuit?In a series circuit, all components are connected end-to-end, forming a single path for current flow.
A series circuit can contain any combination of resistors, capacitors, and inductors.
In a series circuit, the current flowing in each circuit component is the same and the voltage drop in each circuit component is different.
Based on this, the total formula for the total resistance in a series circuit is given as;
R = R₁ + R₂ + R₃
where;
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A crate slides down a ramp that makes a 20∘ angle with the ground. To keep the crate from sliding too fast, Paige pushes back on it with a 69 N horizontal force.
A) How much work does Paige do on the crate as it slides 3.3 m down the ramp?
,Paige does 182.9 J of work on the crate as it slides 3.3 m down the ramp.
To determine the work done by Paige on the crate as it slides down the ramp, we need to calculate the component of Paige's force that is parallel to the direction of motion of the crate. This component will do work on the crate by exerting a force in the same direction as the crate's displacement.
We can first calculate the weight of the crate, which is given by
W = mg
where m is the mass of the crate and g is the acceleration due to gravity. We can assume that the crate is on a frictionless surface, so the force of friction is zero. Therefore, the weight of the crate is the only force acting on it parallel to the ramp. Using the angle of the ramp, we can calculate the component of the weight that is parallel to the ramp:
F_parallel = mg sin θ
where θ is the angle of the ramp, which is 20∘. We can also calculate th
m = W/g
where g is the acceleration due to gravity, which is 9.81 m/s^2.
Substituting the values, we get:
m = (F_parallel/sin θ)/g
m = (mg sin θ/sin θ)/g
m = g
Therefore, the mass of the crate is equal to g.
Next, we can calculate the force applied by Paige, which is given by:
F_applied = 69 N
Since Paige is pushing back on the crate, her force is in the opposite direction of the crate's motion, so we need to calculate the negative of F_parallel. Therefore, the net force acting on the crate is:
F_net = F_applied - F_parallel
F_net = 69 N - g sin θ
Finally, we can calculate the work done by Paige on the crate using the formula:
W = F_net d
where d is the distance traveled by the crate, which is 3.3 m. Substituting the values, we get:
W = (69 N - g sin θ) x 3.3 m
Using the value for g and θ, we get:
W = (69 N - 9.81\(m/s^2\)x sin 20∘) x 3.3 m
W = 182.9 J
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If a book has a weight of 23.3 N on earth, what is its mass
Answer:
2.38 kg
Explanation:
by definition, weight in physics is the force of gravity (Fg)
Fg = mass x gravity or mg
gravity is 9.8 m/s^2
N = kg m/s^2
Fg = mg
23.3 kg m/s^2 = 9.8 m/s^2 x m
23.3 kg m/s^2 / 9.8 m/s^2 = m >>> m/s^2 cancel out
23.3/9.8 = 2.37755 kg
m = 2.38 kg
Why does the Moon orbit Earth?
a
There is magnetic attraction between the Earth and
the Moon
b
There is gravitational attraction between the Earth
and the Moon
с
There is chemical attraction between the Earth and
the Moon
d
There is mechanical attraction between the Earth
and the Moon
Answer:
B
Explanation:
Gravity, the attractive force between all masses, is what keeps the planets in orbit. Newton’s universal law of gravitation relates the gravitational force to mass and distance
The force of gravity is what gives us our sense of weight. Unlike mass, which is constant, weight can vary depending on the force of gravity (or acceleration) you feel. When Kepler’s laws are reexamined in the light of Newton’s gravitational law, it becomes clear that the masses of both objects are important for the third law, which becomes a3 = (M1+ M2) × P2. Mutual gravitational effects permit us to calculate the masses of astronomical objects, from comets to galaxies.
The index of refraction of crown glass is 1.515 for red light and 1.523 for blue light. Find the angle separating rays of the two colors in a piece of crown glass if their angle of incidence is 42o .
Given:
The angle of incidence is,
\(i=42\degree\)The refractive index of the crown glass for red light is,
\(n_r=1.515\)The refractive index of the crown glass for blue light is,
\(n_b=1.523\)To find:
The angle separating rays of the two colours in a piece of crown glass
Explanation:
We know, Snell's law,
\(n_1sini=n_2sinr\)For, the red light,
\(\begin{gathered} 1\times sin42\degree=1.515sinr_r \\ sinr_r=\frac{sin42\degree}{1.515} \\ r_r=sin^{-1}(0.4417) \\ r_r=26.2\degree \end{gathered}\)For, the blue light,
\(\begin{gathered} 1\times sin42\degree=1.523sinr_b \\ r_b=sin^{-1}\frac{sin42\degree}{1.523} \\ r_b=26.1\degree \end{gathered}\)The separation between the refracted rays is,
\(\begin{gathered} r_r-r_b=26.2\degree-26.1\degree \\ =0.1\degree \end{gathered}\)Hence, the required separation is 0.1 degrees.
Calculate the PE of an object with a mass of 0.5 kg located on a table with a height of 1 meter. (Remember g= 9.8 m/s2)
We will have the following:
\(P=(0.5kg)(9.8m/s^2)(1m)\Rightarrow P=4.9J\)So, the potential energy is 4.9 Joules.
What is the kinetic energy of an object that has a mass of 50. 0 kg and a velocity of 18 m/s? 450 J 900 J 8,100 J 16,000 J.
The kinetic energy of an object that has a mass of 50.0 kg and a velocity of 18m/s is 8,100J.
KINETIC ENERGY:Kinetic energy refers to the energy of a body due to its motion. The kinetic energy can be calculated as follows:
K.E = ½ m × v²
Where;
K.E = kinetic energy (J)m = mass (kg)v = velocity (m/s)According to this question, an object that has a mass of 50.0 kg and a velocity of 18m/s. The kinetic energy can be calculated as follows:
K.E = ½ × 50 × 18²
K.E = ½ × 16,200
K.E = 8100J.
Therefore, the kinetic energy of an object that has a mass of 50.0 kg and a velocity of 18m/s is 8,100J.
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By how much does a 65.0-kg mountain climber stretch her 0.800-cm diameter nylon rope when she hangs 35.0 m below a rock outcropping? Young's modulus for the nylon rope is .
The nylon rope stretches by 0.637 meters, or 63.7 centimeters when the mountain climber hangs 35.0 meters below the rock outcropping.
F = m * g
F = 65.0 kg * 9.81 m/s²
F = 637.65 N
The cross-sectional area of the rope can be calculated as:
A = πr²
A = π(0.800 cm/2)²
A = 0.5027 cm² = 5.027 ×\(10^{-5\)m²
Now we can use Young's modulus to calculate the stretch of the rope:
Y = stress/strain
stress = F/A
strain = ΔL/L0
where ΔL is the change in the length of the rope, and L0 is the original length.
Assuming Young's modulus for nylon is 2.0 GPa or 2.0 ×\(10^{9}\) N/m², we can solve for the stretch:
ΔL/L0 = stress/Y = (F/A)/(Y)
ΔL/L0 = (637.65 N)/(5.027 × \(10^-5\)m² * 2.0 ×\(10^{9}\)N/m²)
ΔL/L0 = 0.637 m
Cross-sectional area refers to the area of a two-dimensional shape that is perpendicular to an axis or direction of interest. For example, if a cylinder is standing upright, its cross-sectional area would be the circle formed by the intersection of the cylinder and a plane perpendicular to its height.
The cross-sectional area is important in a variety of physical contexts, including fluid mechanics, electrical engineering, and materials science. In fluid mechanics, the cross-sectional area of a pipe or channel is used to calculate flow rate and velocity. In electrical engineering, the cross-sectional area is used to determine the current-carrying capacity of a wire or cable. In materials science, the cross-sectional area is used to calculate stress and strain in materials subjected to external forces.
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In the spectrum of a galaxy that is travelling away from Earth a hydrogen line is observed to be shifted from 394 nm to 450 nm. Calculate the velocity of recession of the galaxy.
The velocity of recession of the galaxy will be 37.3×10⁶ m/sec. The concept of Doppler effect is employed in the given problem.
What is the Doppler effect?A sudden change in the frequency due to the distance between the objects and source is explained by the Doppler effect.
As the source and observer travel toward each other, the frequency of sound, light, or other waves increases or decreases.
A passing siren's rapid change in pitch, as well as astronomers' redshift, are both caused by this phenomenon.
Applications of the Doppler effect;
The rest wavelength is,\(\rm \lambda_0 = 394 \ nm\)
The distant wavelength is,\(\rm \lambda = 450 \ nm\)
The velocity of recession is,V
The recession velocity is found as;
\(\rm V = (1-\frac{\lambda}{\lambda_0} )C \\\\ \rm V = (1-\frac{394}{450} )\times 3 \times 10^8 \\\\ V = (1- 0.875)\times 3 \times 10^8 \\\\ V = 37.3 \times 10^6 \ m/sec\)
Hence, the velocity of recession of the galaxy will be 37.3×10⁶ m/sec.
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WHAT IS THE VOLUME OF A 5.71 G PLASTIC CUBE THAT HAS A DENSITY OF 1.15 G/CM3
Answer:4.96\(cm^{3}\)
Explanation: Density is \(\frac{Mass}{Volume}\)
so you are now looking for volume.
Volume= Density x Mass so
Volume = (5.78g) x(1.15g/ \(cm^{3} \frac{x}{y}\)) =4.96\(cm^{3}\)
A kangaroo moves with a constant speed of 90 km/h for 20 m on a straight road. Calculate the distance traveled in this period of time
We first apply the data to the problem.
Data:
V = 90km/hT = 20minD = ?Now, we convert the minutes to hours.
Conversion:
T = 20 min • (1 hr / 60 min)T = 1/3 hrThen, we apply the formula that is.
Formula:
D = V • TFinally we develop the problem.
Developing:
D = (90km/h) • (1/3h)D = 30kmThe distance traveled by the kangaroo is 30 kilometers.
A sound wave traveling in air has a frequency f and wavelength lambda. A second sound wave traveling in air has wavelength lambda/2. What is the frequency of the second sound wave? 4f 2f f 1/2 f 1/4 f
The frequency of a sound wave is directly related to its wavelength and the speed of sound in the medium through which it is traveling. In this case, we are considering two sound waves traveling in air.
The speed of sound in air is approximately constant under normal conditions, so we can assume it remains the same for both waves.
We are given that the first sound wave has a wavelength of λ and a frequency of f. The relationship between frequency (f), wavelength (λ), and speed of sound (v) is given by the equation: v = fλ.
For the second sound wave, we are told that its wavelength is λ/2. Let's denote the frequency of the second wave as f'. We can apply the same equation to this wave as well: v = f' (λ/2).
Since the speed of sound (v) remains the same for both waves, we can equate the two equations:
fλ = f' (λ/2).
To find the frequency of the second wave (f'), we need to solve this equation for f'. We can start by canceling out the common factor of λ:
f = f' / 2.
Multiplying both sides of the equation by 2, we have:
2f = f'.
Therefore, the frequency of the second sound wave is 2f.
In summary, if the first sound wave has a frequency f and the second sound wave has a wavelength that is half the wavelength of the first wave, then the frequency of the second sound wave is 2f.
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Three forces act on an object at the same time. F1 = 100. N at 30.0degrees north of east, F2 = 200. N at 45.0degrees north of west, and F3 = 100. N at 30.0degrees east of south. What are the magnitudes and direction of both the resultant force and equilibrant force?
200N towards south are the magnitudes and direction of both the resultant force and equilibrant force.
Define force
A force is an effect that changes, or accelerates, the motion of a mass-containing object. It is a vector quantity since it can be a push or a pull and always has magnitude and direction.
The entire force operating on the item or body, combined with the body's direction, is referred to as the resultant force. When the object is stationary or moving at the same speed as the object, the resultant force is zero.
Between F1 and F2 , resultant force will be 100N towards 45.0degrees north of west,
The total resultant force will be 100+100 i.e. 200N towards south.
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what is the ratio of the rotational speed of earth's daily rotation to that of its annual revolution?
The earth turns a little more than one revolution in 24 hours. A sidereal day, in which the earth turns exactly 360 degrees is about 4 minutes shorter than 24 hours. In a year, the extra bits add up to exactly one extra rotation. We have 365.25 days in a year (counting leap years) so the earth rotates 366.25 full revolutions in that same time. So the ratio of rotational speeds is 366.25 to 1.