Required wavelength is λ = 0.0119 nm
The Compton effect in physics is defined as the phenomenon that arises when a specific beam is dispersed on a specific particle with an increase in wavelength.
Equation :Given;
The campton scattering is k = 30 kev
The speed of light is c = 2.9979 X 10 ⁸ m/s
The planck's constant is h = 6.626 X 10⁻³⁴
The expression from Campton shift is given by,
λ' - λ = λc (1 - Cos∅)
Here, ∅ is the angle of scattering whose value is 180° for maximum energy transfer and λc is the campton wavelength whose value is
λc = h/mc
substitute the values in the above expression
λ' - λ = λc (1 - Cos 180°)
λ' - λ = 2 (h/mc)
Here, m is the mass of electron
On rearing the above expression
λ' = λ + 2 (h/mc)
The expression from conservation of energy is given by,
E - E' = k
(hc/λ) - (hc/λ') = k
hc((λ' - λ)/λλ') = k
hc ((λ' - λ)/k) = λλ'
Here E and E' are the initial and final energy of electron
substitute the values in the above equation
hc (2(h/mc)/k)) = λ (λ + 2 (h/mc))
λ² + (2h/mc)λ - 2h²/mk = 0
λ² + \(\frac{2(6.626X10^{-34}Js)}{(9.11X10^{-31}kg) (2.997X10^{8}m/s ) }\) λ - \(\frac{2(6.626X10^{-34}Js)}{(9.11X10^{-31}kg) (30X10^{3}evX\frac{1.6X10^{-19} }{1ev} J) }\) = 0
λ² + (4.85X10⁻¹²)λ - (2X10⁻²²) = 0
On solving the above expression
λ = 1.19 X 10⁻¹¹ m
λ = (1.19 X 10⁻¹¹ m X 10⁹ nm/1m)
λ = 0.0119 m
Thus, required wavelength is λ = 0.0119 nm
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5.How can we determine if an object is charged or not?
Answer:
through the use of a Gold leaf electroscope
Why does the output of a microphone increase as the frequency of the sound waves which it receives increases
Answer:
See Explanation
Explanation:
The frequency of sound waves received by the microphone influences the output or pitch of the sound obtained from the microphone.
The higher the frequency of the sound received by the microphone, the higher the output of the microphone and vice versa. This is because, the higher the frequency of sound, the higher the oscillations produced and the greater the output of the microphone.
The rise and fall in the pitch of sound waves as the frequency of sound waves varies is called inflection.
Answer:
b
Explanation:
cuz im smart
a carnot heat engine and an ordinary refrigerator with coefficient of performance 1.85 operate between reservoirs at 335 k and 265 k . the work done by the carnot heat engine drives the refrigerator. If the heat engine extracts 11.5 J of energy from the hot reservoir, how much energy does the refrigerator exhaust to the hot reservoir?
A Carnot heat engine operating between reservoirs at 335 K and 265 K extracts 11.5 J of energy from the hot reservoir, and the work done by the Carnot engine drives a refrigerator with a coefficient of performance of 1.85. The amount of energy that the refrigerator exhausts to the hot reservoir is 21.275 J.
We can solve this problem using the principles of thermodynamics and the equations that describe the behavior of a Carnot engine and a refrigerator.
To find the efficiency of the Carnot engine.
The efficiency of a Carnot engine is given by:
η = 1 - (Tc/Th)
where η is the efficiency,
Tc is the temperature of the cold reservoir, and
Th is the temperature of the hot reservoir.
Substituting in the values given in the problem, we get:
η = 1 - (265/335) = 0.208
Next, we can use the efficiency of the Carnot engine to find the amount of energy that it exhausts to the cold reservoir. The work done by the Carnot engine is given by:
W = Qh - Qc
where W is the work done,
Qh is the amount of heat absorbed from the hot reservoir, and
Qc is the amount of heat exhausted to the cold reservoir.
We know that W = 11.5 J, and we can use the efficiency of the Carnot engine to find Qc:
η = Qh/W
Qh = ηW = 0.208 x 11.5 J = 2.392 J
Therefore, the amount of energy that the Carnot engine exhausts to the cold reservoir is Qc = Qh - W = 2.392 J - 11.5 J = -9.108 J.
Note that this value is negative because the Carnot engine is doing work on the refrigerator, so energy is being transferred from the cold reservoir to the hot reservoir.
Finally, we can use the coefficient of performance of the refrigerator to find the amount of energy that it exhausts to the hot reservoir. The coefficient of performance is given by:
COP = Qc/W
where COP is the coefficient of performance and
Qc is the amount of heat exhausted to the hot reservoir.
Substituting in the values given in the problem, we get:
1.85 = Qc/11.5 J
Solving for Qc, we get:
Qc = 21.275 J
Therefore, the amount of energy that the refrigerator exhausts to the hot reservoir is Qc = 21.275 J.
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_______ assisted Anton Raphael Mengs with the iconography of his ceiling fresco, Parnasus, in the Villa Albani.
A) Johann Winckelmann
B) Cardinal Albani
C) Jacques Louis David
D) Joshua Reynolds
Answer:
Explanation:
The correct answer is A) Johann Winckelmann. Johann Winckelmann, a German art historian and archaeologist, assisted Anton Raphael Mengs with the iconography of his ceiling fresco, Parnassus, in the Villa Albani
An
egg with a mass of 0. 052 kg is thrown against a wall with a velocity of 30 m/s. The egg is smashed against the wall, stopping it. What is the
impulse the wall provided?
A tennis ball moves 22 meters southward, then 12 meters northward, then 16 meters southward, and finally 34 meters northward
The resultant displacement of the tennis ball is 8 m northward.
What is displacement?
The displacement of an object is the change in the position of the object. The displacement of an object describes the shortest point between the final and initial position of an object.
The displacement of the tennis ball is calculated as follows;
d = (12 m north + 34 m north) - (22 m south + 16 m south)
d = (46 m north) - (38 m south)
d = 8 m northward
Thus, the resultant displacement of the tennis ball for the given motion is 8 m northward.
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The compete question is below:
A tennis ball moves 22 meters southward, then 12 meters northward, then 16 meters southward, and finally 34 meters northward. find the resultant displacement of the tennis ball.
After every movement in north and south direction multiple times, the displacement of the tennis ball is 8 meters in north direction.
What is displacement?The definition of displacement is the modification of an object's position. It has a direction and magnitude and is a vector quantity. It is shown as an arrow that travels from the initial location to the conclusion.
According to the question, the tennis ball moves 22 meters in south direction then it moves towards north and travels for 12 meters again it turns to south and covers 16 meters and at last it covers 34 meters in the north direction.
d = (12 m + 34 m ) north direction - (22 m + 16 m ) south direction
d = 8 meters in north direction.
Hence, the total displacement done by the tennis ball is 8 meters in the north direction.
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list in order of imcreasing
Radio waves , microwaves , infrared radiation , visible light , ultraviolet waves , x-rays , gamma rays
PLEASE GIVE BRAINLIEST
A stuntman drives a car off of a parking garage. The car lands 68.38 meters away from the base of the garage. If the stuntman drove the car at 19 m/s, how tall is the parking garage?
Answer: 63.43 m
Explanation:
Given
Car lands 68.38 m away from the base of the garage
Stuntman drove the car with speed \(u=19\ m/s\)
Since there is no acceleration in the horizontal direction, so there is no change in velocity
\(\Rightarrow 68.38=19\times t\\\Rightarrow t=3.598\ s\)
time taken to cover 68.38 m is 3.598 s
In this time car travels a vertical distance of h
Such that we can write
\(\Rightarrow h=u_vt+\frac{1}{2}at^2\\\\\Rightarrow h=\frac{1}{2}gt^2\\\\\Rightarrow h=0.5\times 9.8\times (3.598)^2=63.43\ m\)
scientists currently use planetary rovers to collect data on mars. what type of samples have they collected so far?
Scientists currently use planetary rovers to collect data on mars rovers collect infrared spectra, drill cores, photographs.
Designed to move across the solid surface of a planet or other planetary mass celestial bodies, a rover (or occasionally planetary rover) is a planetary surface exploration tool. Others have been created as partially or entirely autonomous robots. Some rovers have been created as ground vehicles to transfer members of a human spaceflight crew. When a lander-style spacecraft is used to land on a planet (other than Earth), rovers are often built to collect data about the topography and sample the crust, including dust, dirt, rocks, and even liquids. They are vital resources for space exploration. Due to the slow speed of radio communications, rovers that land on celestial worlds other than the Earth, like the Mars Exploration Rovers, cannot be remotely operated in real-time.
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Is commonly weighed in carats. five carats are equivalent to one gram. how many grams of gold are contained in a 24-carat gold chain?
a. 120 g
b. 4.8 g
c. 5.0 g
d. 100 g
24 carats divided by 5 carats per gram equals 4.8 grams of gold.The correct answer is b. 4.8 g.
To find the number of grams of gold in a 24-carat gold chain, we use the conversion rate of 5 carats = 1 gram. Therefore, we divide 24 carats by 5 to get the answer in grams.
1. We are given that five carats are equivalent to one gram. This means that for every 5 carats of gold, we have 1 gram of gold.
2. To find the number of grams of gold in a 24-carat gold chain, we divide the number of carats (24) by the conversion rate of 5 carats per gram.
3. So, 24 carats divided by 5 carats per gram equals 4.8 grams of gold.
The correct answer is b. 4.8 g.
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The coldest clouds in the ISM are molecular clouds, so named because their temperatures are low enough and their densities high enough for atoms to join together into molecules. These clouds are capable of collapsing to form new stars, in a stellar nursery like the one in the left image. The Pleiades (right image) is an example of stars that formed recently within such a nursery.
Molecular clouds range in mass from a few times the mass of our Sun (solar masses) to 10 million solar masses. Individual stars range from 0.08 to about 150 solar masses.
What does all of this imply about how stars form from molecular clouds?
Stars form from molecular clouds through a process known as stellar formation.
These clouds, characterized by low temperatures and high densities, provide the ideal conditions for atoms to combine and form molecules. With a mass range spanning from a few solar masses to millions of solar masses, molecular clouds serve as the birthplaces of new stars. The Pleiades cluster serves as a notable example of stars that have recently formed within such a stellar nursery.
The formation of stars from molecular clouds involves several key steps. Firstly, gravitational forces acting on regions of higher density within the cloud cause them to collapse under their own gravity. As the cloud collapses, it begins to fragment into smaller, denser clumps called protostellar cores. These cores continue to collapse, and their central regions become increasingly dense and hot. At this stage, they are known as protostars.
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Pls help me with this question its due tomorrow and I can't find the answer: A person jumped 50cm, the hang time for the jump was 0.778 seconds, calculate a value for the acceleration due to gravity. What is the percent error in the value for acceleration you found? (Solve it without factoring in the air)
S = ut + 1/2gt²
where S = distance
50 cm = 0.5m
u is initial velocity = 0
S = 0*t + 1/2gt²
S = 1/2gt²
0.5 = 1/2 g (0.778²)
2*0.5 = g(0.778²)
1/(0.778²) = g
g = 1.65m/s²
The value of g is grossly errored due to the values obtained since the known value of g on earth is 9.8m/s² the obtained value rounds off to the value of g on moon.
What is the surface area of the shape?
Answer:
162 should be the answer because 18x3x3=162.
Imagine that you are hovering next to a space shuttle and your buddy of equal mass
who is moving a 4 km/h with respect to the ship bumps into you. If he holds onto
you, how fast do you both move with respect to the ship?
The total momentum vectors will not change prior to or following a collision. When two objects collide at an angle from one another, their momentum will not change. Thus, the momentum of objects colliding remains constant.
What fast you both move with respect to the ship?Because momentum is dependent on mass and velocity, objects in space can have momentum. Mass is a property that does not change depending on where an object is, unlike other properties like weight.
Simply said, mass is the continuous amount of matter that makes up an item. Thus, momentum is a property of objects in space.
Therefore, Both the ship and the individual are moving at a 2 km/h rate.
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Two forces act on a 39 kg mass to give it an acceleration of 40 m/s 2 in the positive x direction. If one of the forces acts in the negative y direction with a magnitude of 150 N, what is the magnitude of the second force? Answer in units of N.
The magnitude of the second force is 1710 N.
What is force?Force is the product of mass and acceleration.
To calculate the magnitude of the second force, we use the formula below
Formula:
F' = F+ma................... Equation 1Where:
F' = Magnitude of the second forceF = Magnitude of the first forcem = Mass a = AccelerationFrom the question,
Given:
F = 150 Nm = 39 kga = 40 m/s²Substitute these values into equation 1
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Students raced each other in the gym while the teacher recorded each student's speed. Jeremy ran 14 miles per hour, Isaiah ran 10 miles per hour, Jonah ran 13 miles per hour, and Alexis ran 16 miles per hour. Which of the bar graphs should the teacher use to compare the students' speeds? (pictures re the choices)
In a gym the students raced with each other and teacher is recording everyone's speed than the second graph is representing correctly.
What is a graph?A graph is a visual depiction of statistical data or a logical relationship between variables. Graphs serve a predictive purpose because they have the virtue of displaying broad trends in the mathematical behavior of data. However, as just approximations, they may be incorrect and occasionally deceptive.
Most graphs have two axes, with the axis denoting a set of independent variables and the vertical axis denoting a set of dependent variables. The most typical graph is indeed a broken-line chart, where the regression coefficient is typically a factor of duration.
In the second graph the speed of every student is represented accurately, therefore the second graph is correct.
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What is the atomic number the atom shown?
A. 3
B. 13
C. 14
D. 27
Answer:
13
Explanation:
Brainlest pls
Answer:
B-13
Explanation:
The protons listed in the atom are 13, and the protons are the same number as the atomic number.
The model shows how solar-powered electric cars indirectly use energy from the Sun. Describe the energy transformations that you see.
Answer:
Radiant energy from the Sun is converted into electrical energy. Electrical energy is then converted into chemical energy. Chemical energy is then converted into electric energy for the motor. The motor converts electrical energy into mechanical energy and makes the car move.
Sun makes radiant energy > converted to electrical energy through solar panels > converted to chemical energy which is then stored in a battery for the motor > converted into mechanical energy to make the car move
Extra:
Look at the image below for a better understanding of the question. I hope this helps! :)
Source:
Edmentum Guided Notes
The energy transformations that can be seen in solar-powered electric cars :
Solar energy > electrical energy > chemical energy > mechanical energy.
What is solar-powered electric cars?
A solar electric car is one that is primarily or entirely powered by solar energy. Solar panels typically feature photovoltaic (PV) cells that convert solar energy directly into electric energy. The phrase "solar vehicle" typically implies that all or some of a vehicle's propulsion is powered by solar energy. Communications, controls, and other auxiliary operations might all be powered by solar energy.
In solar electric car, solar energy converted into electrical energy by photovoltaic (PV) cells. This energy is stored in battery in the form of chemical energy. When the car moves, this chemical energy transforms into mechanical energy.
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A grinding wheel 0. 35 m in diameter rotates at 2200 rpm.
a. Calculate its angular velocity in rad/s.
b. What is the linear speed of a point on the edge of the grinding wheel?
c. What is the acceleration of a point on the edge of the grinding wheel?
In this problem , angular velocity is230.26 rad/sec,
linear speed of a point on the edge= 40.3 m per sec
and acceleration of a point on the edge=
\(
9.28 \times {10}^{3} m \: per \: sq \: sec
\)
Rotational motion is a special type of motion in which each and every point has its different linear velocity but same angular velocity.For example a a wheel rolling over a ground is performing rotational motion.
every part has different value of linear acceleration bit same angular acceleration.Also the net acceleration of its lower most point is zero.
In this problem it is given that:
diameter of the grinding wheel (d)=0.35m
so the radius will be half of it
so r=0.35/2 =0.175 m
next we are given angular velocity z = 2200 rpmwe need to find in terms of rad/s. so we can do so by:
\( (2200 \times 2\pi) \div 60\)z=230.26 radian per second
we have to find the linear speed of a point on the edge of the grinding wheel which is given by:\(v = r \times {z}\)
where z is the angular velocity
v = 0.175 x230.6
v = 40.3m per sec
c.To find the acceleration of a point on the edge of a grinding wheel we will use the formula:
\(a = r \times {z}^{2} \)
where z= angular velocity
\(a = 0.175 \times {230.6}^{2} \)
\(= 9.28 \times {10}^{3} m \: per \: sec \: sq\)
so the angular velocity, linear speed and acceleration are 230.6m per sec, 40.3 m per sec and 9280 m per sec sq respectively.
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While riding a chairlift, a 55-kilogram skier is raised a vertical distance of 370 meters. What is the total change in the skier's gravitational potential energy
The change in the skier's gravitational potential energy is 199430 J.
Gravitational potential energy:This is the energy of a body due to its position in a gravitational field. The S.I unit of gravitational potential energy is Joules (J)
The Change in the skier's gravitational potential energy can be calculated using the formula below.
Formula:
ΔP.E = mg(Δh)............... Equation 1Where:
ΔP.E = Change in the skier's potential energym = mass of the skierΔh = change in height to which it was raisedg = acceleration due to gravity.From the question,
Given:
m = 55 kgΔh = 370 mg = 9.8 m/s²Substitute these values into equation 1
ΔP.E = 55×370×9.8ΔP.E = 199430 J.Hence, The change in the skier's gravitational potential energy is 199430 J.
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A car weighs 2,000 kg. It moves along a road by applying a force on the road with a parallel component of 560 N. There are two passengers in the car, each weighing 55 kg. If the magnitude of the force of friction experienced by the car is 45 N, what is the acceleration of the car?
Answer:
The acceleration of the car is 4.10 m/s².
Explanation:
The acceleration of the car can be found using the following equation:
\( F = ma \) (1)
Where:
F is the force
m is the mass
a is the acceleration
The force is:
\(F = F_{p} - F_{f}\) (2)
Where:
F(p) is the parallel force = 560 N
F(f) is the force of friction = 45 N
By entering equation (2) into (1) we have:
\(F_{p} - F_{f} = (m_{c} + m_{p}*2)a\)
\( 560 N - 45 N = (2000 kg + 55*2 kg)a \)
\( a = \frac{2000 kg + 55*2 kg}{515 N} = 4.10 m/s^{2} \)
Therefore, the acceleration of the car is 4.10 m/s².
I hope it helps you!
a security guard walks at a steady pace, traveling 120 mm in one trip around the perimeter of a building. it takes him 250 ss to make this trip.
The security guard make the trip of 120 m of distance in a time of 250 s with a speed of: 0.48 m/s
The formula and procedure we will use to solve this exercise is:
v = x /t
Where:
x = distancet = timev = velocityInformation about the problem:
t = 250 sx= 120 mv = ?Applying the velocity formula we have that:
v = x /t
v = 120 m /250 s
v = 0.48 m/s
What is velocity?It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).
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which describes what a velocity/ time graph looks like with no acceleration?
Answer:
A straight line with no slope.
Answer:
C on edge 2021
Explanation:
Answer is 8 however I do not know how to get there
Answer:
C. 10 m·s⁻¹
Explanation:
The velocity is numerically equal to the area of the figure lying under the acceleration graph
V = 2·1.0 + (1.0 + 3.0)·(6 - 2) / 2 = 2.0 + 4.0·4 / 2 = 10 m·s⁻¹
Find the center of mass of the region bounded by y=9-x^2 y=5/2x , and the z-axis. Center of Mass = __?
Note: You can earn partial credit on this problem.
The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.
The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].
The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].
The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].
Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].
The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].
The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.
Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).
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Find the solution to the equation for simple harmonic motion x" + 4x = 0, with initial conditions x(0) = 5 and x'(0) = 6.
The solution to the equation for simple harmonic motion is x(t) = 5cos(2t) + 3sin(2t) with initial conditions .
Given: x'' + 4x = 0 , x (0)= 5, x'(0) = 6 .
corresponding auxiliary eq?
m² + 4 = 0
m = ± 21
x(x) = c₁ × cos(2t) + c₂ × sin(2t)
x' × (t) = - 2c₁ sin (2t) + 2c₂ × cos(2t)
x(0) = 5 = c₁ + 0c₂ ---------- c₁ = 5
x' (0) = 6 = 2c₂ ------------- c₂ = 3
x(t) = 5cos(2t) + 3sin(2t)
Simple harmonic motion :In physics, simple harmonic motion refers to the continuous movement back and forth through an equilibrium, or central, position in such a way that the maximum displacement on one side of this position is the same as the maximum displacement on the other. Each complete vibration has the same time interval.
A back-and-forth motion about a fixed axis or straight line is the definition of a simple harmonic motion. For a straightforward harmonic motion, a body's acceleration changes directly with its displacement in the opposite direction. A straightforward harmonic motion can be linear or angular.
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Blackie, a cat whose mass is 6-kg, is napping on top of the refrigerator when he rolls over and fall. Blackie has a KE of 90-J just before he lands on his feet on the floor.
How tall is the refrigerator?
To answer this question, you need to understand the law of conservation of energy. Essentially, the law states that energy cannot be created or destroyed; it is always conserved.
Knowing this law, how can we answer this question? Well, let's look at what the question tells us. We know that Blackie was initially at the top of a refrigerator before rolling over and falling to the ground. At ground level, he only has Kinetic energy when he lands. Since we know that he started at the top of the fridge, we know that Blackie started off with potential gravitational energy.
That would make sense, right? Written out as an equation, it'd be:
\(U_{g}\) = \(K_{E}\)
This follows the law of conservation of energy, as all the potential gravitational energy is converted into Kinetic energy.
Now, we know what energies are converted. What can we do with it? Recall the equation of potential gravitational energy:
\(U_{g}\) = \(F_{g}\)∆H
\(U_{g}\) = mg∆H
Do you see it now? ∆H is the distance that Blackie falls, and since Blackie jumps from the fridge to the ground, ∆H must be the height of the fridge!
Let's start solving for ∆H:
\(U_{g}\) = \(K_{E}\)
Substitute potential gravitational energy with our equation:
mg∆H = \(K_{E}\)
We were given the value of Kinetic Energy:
mg∆H = 90
Isolate ∆H by dividing both sides by mg:
∆H = \(\frac{90}{mg}\)
Input values for 'm' and 'g' (m is the mass of Blackie and g is Earth's acceleration)
∆H = \(\frac{90}{6*9.80}\)
∆H = \(\frac{90}{58.8}\)
∆H = 1.53
The refrigerator is 1.53 meters tall.
And that's it! Let me know if you need me to explain anything I did here.
- breezyツ
Which stars are the most common?
A) Stars with a larger mass and a larger radius than the Sun's are the most common.
B) Stars with a smaller mass and a smaller radius than the Sun's are the most common.
C) Stars with a larger mass and a smaller radius than the Sun's are the most common.
D) Stars with a smaller mass and a larger radius than the Sun's are the most common.
E) All of the above are equally common.
Stars are born within the clouds of dust and scattered throughout most galaxies. A familiar example of such as a dust cloud is the Orion Nebula. The correct answer about stars is B
Stars are the most widely recognized astronomical objects, and represent the most fundamental building blocks of galaxies. The age, distribution, and composition of the stars in a galaxy trace the history, dynamics, and evolution of that galaxy. Moreover, stars are responsible for the manufacture and distribution of heavy elements such as carbon, nitrogen, and oxygen, and their characteristics are intimately tied to the characteristics of the planetary systems that may coalesce about them. Consequently, the study of the birth, life, and death of stars is central to the field of astronomy. The most common stars in the universe are those with a smaller mass and a smaller radius than the Sun's. Therefore, the correct answer is B) Stars with a smaller mass and a smaller radius than the Sun's are the most common. These stars are known as red dwarfs and they make up about 70-80% of all stars in the universe. Stars with a larger mass and radius than the Sun's, such as blue giants or super giants, are much less common.
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A wave with frequency 440Hz moves through a string. If the string is under a tension of 41N and has a linear density of 0.75g/m, how far apart are the crests of the wave
The distance between the crests of a wave with frequency 440Hz that moves through a string under a tension of 41N and with a linear density of 0.75g/m is approximately 1.496 meters.
To find the distance between the crests of the wave, we need to use the wave speed formula:
v = √(T/μ)
where v is the wave speed, T is the tension in the string, and μ is the linear density of the string.
First, we need to convert the linear density from grams per meter to kilograms per meter, since the unit of tension is Newtons:
μ = 0.75 g/m = 0.00075 kg/m
Next, we can plug in the values given in the problem:
v = √(41 N / 0.00075 kg/m) = 658.3 m/s
Now, we can use the frequency of the wave to find its wavelength:
λ = v/f
where λ is the wavelength and f is the frequency.
Again, we can plug in the values given:
λ = 658.3 m/s / 440 Hz = 1.496 m
Therefore, the distance between the crests of the wave is approximately 1.496 meters.
In summary, the distance between the crests of a wave with frequency 440Hz that moves through a string under a tension of 41N and with a linear density of 0.75g/m is approximately 1.496 meters.
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An electron travels at speed v = 0.996c, where c = 3×10^8 m/s is the speed of light. The electron travels in the direction given by the unit vector v = ⟨0.655,−0.492,−0.573⟩. The mass of an electron is 9×10^−31 kg. What is the vector momentum of the electron? Remember that any vector can be "factored" into its magnitude times its unit vector, so that v = |v|v
The vector momentum of the electron is approximately ⟨2.47×10^-22, -1.86×10^-22, -2.16×10^-22⟩ kg m/s.
The relativistic momentum of an object is given by:
p = m × v / sqrt(1 - v^2/c^2)
where m is the mass of the object,
v is its velocity
c is the speed of light.
In this case, the velocity of the electron is v = 0.996c, so we have:
p = mv / sqrt(1 - v^2/c^2)
= (9×10^-31 kg)(0.996c) / sqrt(1 - (0.996c)^2/c^2)
≈ 3.77×10^-22 kg m/s
The unit vector is already given as:
v = ⟨0.655,−0.492,−0.573⟩
So the vector momentum is:
p_vec = p * v
= ⟨(3.77×10^-22 kg m/s)(0.655), (3.77×10^-22 kg m/s)(-0.492), (3.77×10^-22 kg m/s)*(-0.573)⟩
≈ ⟨2.47×10^-22, -1.86×10^-22, -2.16×10^-22⟩ kg m/s
Therefore, the vector momentum is ⟨2.47×10^-22, -1.86×10^-22, -2.16×10^-22⟩ kg m/s.
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