The velocity of an electron emitted by a metal whose threshold frequency is 2.25 x 10¹⁴ s⁻¹ when it is exposed to visible light of a wavelength of 6.86 x 10⁻⁷ m is approximately 708.5 m/s.
Steps
The photoelectric effect equation is:
hf = Φ + 1/2 mv²
Convert the given wavelength of the visible light to frequency using the speed of light (c = 3.00 x 10⁸ m/s) and the formula:
c = λf
where λ is the wavelength and f is the frequency.
f = c/λ = (3.00 x 10⁸ m/s) / (6.86 x 10⁻⁷ m) = 4.37 x 10^14 s^-1
Since the frequency of the incident light is greater than the threshold frequency of the metal, electrons will be emitted. Therefore, Φ is given as 0 eV since no extra energy is required to release electrons.
hf = Φ + 1/2 mv²
(6.626 x 10⁻³⁴ J s)(4.37 x 10¹⁴ s⁻¹) = 0 eV + (1/2)(9.11 x 10⁻³¹ kg)(v²)
v² = 2hf/m = 2(6.626 x 10⁻³⁴ J s)(4.37 x 10¹⁴ s⁻¹) / 9.11 x 10⁻³¹ kg
v²= 5.02 x 10⁵ m²/s²
v = sqrt(5.02 x 10⁵ m²/s²) = 708.5 m/s
The velocity of an electron emitted by a metal whose threshold frequency is 2.25 x 10^14 s^-1 when it is exposed to visible light of a wavelength of 6.86 x 10^-7 m is approximately 708.5 m/s.
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if a body is moving with constant linear positive acceleration
a) It moves with constant velocity
b) It remains at rest.
c) It decreases its velocity at constant rate.
d) It increases its velocity.
Answer:
D
Explanation:
It says constant positive linear acceleration, which means that the velocity increases at a constant rate.
what does acceleRation measure
Answer:
Speed and distance traveled
Explanation:
determine the magnitude of the force exerted by the back muscles on the backbone (a measure of the strain in the back muscles). b. determine the magnitude of the force exerted by the pelvis on the backbone (a measure of the compression of the fluid-filled discs between the vertebrae in the lower back). c. how do these results explain why lifting in this way is unsafe? hint: how do the forces exerted by the cable and joint compare to the force exerted by the hanging 50 lb. object?
The magnitude of the force exerted by the back muscles on the backbone, which measures the strain in the back muscles, cannot be determined without specific information about the lifting scenario. Factors such as the angle and distance between the center of mass and the backbone, as well as individual strength and lifting technique, influence this force.
The magnitude of the force exerted by the pelvis on the backbone, which indicates the compression of the fluid-filled discs between the vertebrae in the lower back, is influenced by the weight of the object being lifted, lifting technique, and posture. When lifting an object, the force transmitted through the spine increases, potentially causing compression of the discs.
In an unsafe lifting scenario, the forces exerted by the cable and joint may not sufficiently counterbalance the force exerted by the hanging 50 lb. object. If the forces exerted by the cable and joint are lower than the force exerted by the object, the back muscles and spine can experience excessive strain and compression. This can lead to injuries, back pain, and long-term problems. It is crucial to ensure proper lifting mechanics, seek assistance when needed, and avoid lifting weights that exceed one's capabilities to maintain safety during lifting activities.
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A projectile is fired from ground level over level ground with an initial velocity that has a vertical component of 20m/s and a horizontal component of 30m/s. Using g = 10m/s2, the distance from launching to landing points is:.
The range is 120 meters from the launch point to the landing position.
The angle of projection must first be determined using the formula below before we can determine the projectile's range.
Equation:∅= tan1(Vy/Vx)... Equation 1, where is the projection angle.
Given:
Vy is 20 m/s, while Vx is 30 m/s.
Add these values to equation 1 as replacements.
∅ = tan⁻¹(20/30)
∅ = tan⁻¹(0.667) (0.667)
∅ = 33.7°
Finally, we apply the following formula to determine the projectile's range.Equation 2: R = V2sin2g Where:
R = Range of the projectile.
V = Resultant velocity
∅ = Angle of projection
g = acceleration due to gravity.
Given:V = √[(20²)+(30²)] = √(400+900) = √1300 m/s
∅ = 33.7°
g =10 m/s²
Substitute these values into equation 2R = (√1300)²sin(2×33.7)/9.8
R = 1300(sin67.4)/10
R = 1200.17/10
R = 120.017 m.
Therefore, the range—the distance between the launch and landing points—is 120 m.
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the magnitude of the electric potintial and of the electrolstatic force depend on which two factors
answer:
Distance and amount of charge
also:
size, type
Electrostatic force F=k Q q / r^2
It depends on
1. Charge on which force is acting.
2. Charge due to which force is acting
3. Distance between the two charges.
4. Material medium in which the charges are placed (eg air, water, oil etc)
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maitri goel
what property of gases describes the amount of space taken up by the gas?
Answer:
High pressure
The amount of space a gas's molecules take up compared to the total space in the container—the molecules' relative volume—gets bigger.
Explanation:
A student holds a water balloon outside of an open window and lets go. The window is 10 meters above the ground, and the balloon is falling under the acceleration of gravity, which is 9.8 m/s2. There are two equations that can be used to describe its motion over time:
x=x0+v0t+12at2
v=v0+at
Would the balloon hit the ground before or after 1.0 s of falling? Which equation did you use to decide, and what comparison did you make to determine that it would or would not hit the ground by then?
explain in 3-5 sentences
A uniform accelerated linear motion happens, when a ball is dropped from a certain amount of height.
After solving, we come to know that the water balloon that is dropped by the student 10 meters above the ground, will hit the ground after 1.0s of falling (in 1.4 s).
Which equation is used to describe motion over time for a ball falling from a certain height?
To find the time we need to use the equation that is related the time with the height and the acceleration due to gravity, that is to say, the first equation from the two given, but in the vertical direction:
yf=y0+v0t+1/2at² (1)
Where:
yf : is the final height = 0
yo: is the initial height = 10 m
vo: is the initial velociy = 0 (it is dropped)
a: is the acceleration due to gravity = -9.8 m/s² (it is negative because its direction of motion is downward)
t: is the time =?
Solving equation (1) for t, we have:
0=10m-1/2gt²
t=√2×10m/9.8m/s =1.4s
Therefore, the balloon will hit the ground after 1.0s of falling.
Main answer is :
We used the first given equation but in the y-direction, because the equation x=x₀+v₀t+(1/2)at², considers a motion in the horizontal direction, and the ball is falling (y-direction).
We did not use the other equation (v = v₀ + at) because we do not know the final velocity of the ball before it hits the ground (v).
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Una caloría (cal) es la cantidad de transferencia de energía necesaria para elevar la temperatura de 1 g de agua de 14,5 °C a 15,5 °C.
Answer:
Verdadera.
Explanation:
La caloría se puede definir como una unidad estándar utilizada para medir la cantidad de energía presente en un organismo vivo.
Una caloría (cal) es la cantidad de transferencia de energía necesaria para elevar la temperatura de 1 g de agua de 14,5 °C a 15,5 °C.
Generalmente, es una unidad de medida de energía e igual a 4,1855 julios.
student is given a rock that is known to have a mass of 436.8 grams. She measures the mass of the rock three different times with the following results: 460.9 g, 461.4g, 459.0 g. Calculate the percent error of the student.
Given :
Actual mass , \(m_e=436.8\ g\) .
Three observations 460.9 g, 461.4 g, 459.0 g .
To Find :
The percent error of the student.
Solution :
Percent error is given by :
\(\%error=\sum \dfrac{|approx\ value -actual\ value |}{exact\ value}\times 100\\\\\%error=\dfrac{|460.9-436.8|+|461.4-436.8|+|459-436.8|}{436.8}\times 100\\\\\%error=\dfrac{70.9}{436.8}\times 100\\\\\%error=16.23\%\)
Therefore , the percent error of the student is 16.23 % .
Hence , this is the required solution .
The force of air particles over an area is ________
temperature.
pressure.
volume.
kelvins.
At the top of the loop, what is the direction of the force exerted on a 65 kg rider by the seatbelt? a. upwardb. downwardc. this force has no direction, it is (approximately) zero
a. upward. The rider is upside down at the top of the loop, and the seatbelt provides a centripetal force that pulls the rider upward toward the center of the circle, allowing them to follow a circular path.
Centripetal force is a type of force that acts on an object moving in a circular path. It is directed towards the center of the circle and is necessary to keep the thing moving in a circular direction. The centripetal force can be provided by a variety of sources, such as tension in a rope, gravity, or a magnetic field. The magnitude of the centripetal force required depends on the mass of the object, the speed of the thing, and the radius of the circle.
The formula for centripetal force is
F = mv²/r,
where F is the force, m is the mass of the object, v is the velocity of the object, and r is the radius of the circle. Centripetal force is an essential concept in many areas of physics, including mechanics, astrophysics, and engineering, and it plays a significant role in the functioning of many natural and man-made systems, such as planetary orbits, and centrifuges.
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What is the weight in newtons of an object that has a mass of (a) 8 kg, (b) 0.04 kg, and (c) 760 mg?
The weight of object with a mass of 8 kg is 78.4 N.
The weight of object with a mass of 0.04 kg is 0.392 N.
The weight of object with a mass of 760 mg is 7.45 N.
What is weight?The weight of an object is the force acting on the object due to gravity.
Weight, W = mg
where;
m is the mass of the objectg is acceleration due to gravity, 9.8 m/s²Weight of object with a mass of 8 kgW = mg
W = 8 kg x 9.8 m/s²
W = 78.4 N
Weight of object with a mass of 0.04 kgW = mg
W = 0.04 kg x 9.8 m/s²
W = 0.392 N
Weight of object with a mass of 760 mgW = mg
W = 0.76 kg x 9.8 m/s²
W = 7.45 N
Thus, the weight of object with a mass of 8 kg is 78.4 N.
The weight of object with a mass of 0.04 kg is 0.392 N.
The weight of object with a mass of 760 mg is 7.45 N.
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What are the closest frequencies to 450 Hz that an average person can clearly distinguish as being different in frequency from 450 Hz? The sounds are not present simultaneously.
The closest frequencies to 450 Hz that an average person can distinguish as being different from 450 Hz would be in the range of 445-455 Hz.
The closest frequencies to 450 Hz that an average person can clearly distinguish as being different in frequency from 450 Hz are typically within a range known as the "Just Noticeable Difference" (JND) or the "Difference Limen." The JND for frequency perception varies from person to person but is generally around 1-5 Hz for a pure tone in the mid-frequency range. This means that an average person can perceive a difference in frequency if it is within the range of approximately 1-5 Hz from the original frequency. Therefore, the closest frequencies to 450 Hz that an average person can clearly distinguish as being different from 450 Hz would be in the range of 445-455 Hz. Frequencies outside this range would be more easily distinguishable as different from the original 450 Hz tone.
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At a particular place on the surface of the Earth, the Earth's magnetic field has magnitude of 3.65 ✕ 10^−5 T, and there is also a 121 V/m electric field perpendicular to the Earth's surface.
(a) Compute the energy density of the electric field. (b) Compute the energy density of the magnetic field.
Answer:(a) The energy density of an electric field is given by:
u_E = ε_0 * E^2 / 2
where ε_0 is the permittivity of free space (ε_0 = 8.85 × 10^-12 N^-1 C^2 m^-2), and E is the magnitude of the electric field.
Substituting the given values, we get:
u_E = (8.85 × 10^-12 N^-1 C^2 m^-2) * (121 V/m)^2 / 2 ≈ 6.34 × 10^-8 J/m^3
Therefore, the energy density of the electric field is approximately 6.34 × 10^-8 J/m^3.
(b) The energy density of a magnetic field is given by:
u_B = B^2 / (2 * μ_0)
where B is the magnitude of the magnetic field, and μ_0 is the permeability of free space (μ_0 = 4π × 10^-7 N A^-2).
Substituting the given value of the magnetic field, we get:
u_B = (3.65 × 10^-5 T)^2 / (2 * 4π × 10^-7 N A^-2) ≈ 6.52 × 10^-12 J/m^3
Therefore, the energy density of the magnetic field is approximately 6.52 × 10^-12 J/m^3.
Explanation:
(a) The energy density of the electric field is approximately 6.48 × 10^-8 J/m^3.
(b) The energy density of the magnetic field is approximately 1.27 × 10^-11 J/m^3.
(a) To compute the energy density of the electric field, we use the formula:
u_E = ε_0 E^2 / 2
where u_E is the energy density of the electric field, ε_0 is the electric constant (also known as the permittivity of free space), and E is the magnitude of the electric field.
The electric constant is ε_0 = 8.85 × 10^-12 F/m, and the magnitude of the electric field is E = 121 V/m. Substituting these values into the formula, we get
u_E = (8.85 × 10^-12 F/m) × (121 V/m)^2 / 2 = 6.48 × 10^-8 J/m^3
Therefore, the energy density of the electric field is approximately 6.48 × 10^-8 J/m^3.
(b) To compute the energy density of the magnetic field, we use the formula:
u_B = B^2 / (2μ_0)
where u_B is the energy density of the magnetic field, μ_0 is the magnetic constant (also known as the permeability of free space), and B is the magnitude of the magnetic field.
The magnetic constant is μ_0 = 4π × 10^-7 T·m/A, and the magnitude of the magnetic field is B = 3.65 × 10^-5 T. Substituting these values into the formula, we get:
u_B = (3.65 × 10^-5 T)^2 / (2 × 4π × 10^-7 T·m/A) = 1.27 × 10^-11 J/m^3
Therefore, the energy density of the magnetic field is approximately 1.27 × 10^-11 J/m^3.
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What is the net force on charge placed at the center of square of length 1m? All charges have same magnitude of 2 micro coulomb.
Answer:
Electric Field intensity is zero.
The reason for that is:
All charges are placed at equal distances from the center of the square and have same magnitude and sign. This means they will exert equal and opposite forces on the test charge at the center. Net force will become Zero.
Two hockey players on ice skates push off of each other. One has a mass of 60 kg. The other has a mass of 80 kg.
A. If the 80 kg player moves back with a velocity of 3 m/s, what is his momentum.
B. What is the momentum of the 60 kg player?
C. What is the velocity of the 60 kg player?
Momentum of the 80 kg player is 240 kg⋅m/s (80 kg× 3 m/s).Momentum of the 60 kg player is 180 kg⋅m/s (60 kg×3 m/s).The velocity of the 60 kg player must be -3 m/s.
What is Momentum ?Momentum is an important concept in physics which describes the physical quantity of a moving body's inertia. It is a vector quantity, meaning it has both a magnitude and a direction. Momentum is equal to the product of mass and velocity, and is measured in kilograms-meters per second (kgm/s). Momentum is conserved in closed systems, meaning that the total momentum of a system will remain the same, regardless of any changes in mass or velocity. Momentum is a very useful tool for understanding the motion of objects, particularly in collisions and impacts.
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The energy flow to the earth from sunlight is about 1.4kW/m^2
(a) Find the maximum values of the electric and magnetic fields for a sinusoidal wave of this intensity.
(b) The distance from the earth to the sun is about
1.5×10^11 m. Find the total power radiated by the sun
The maximum values of the electric and magnetic fields for a sinusoidal wave of this intensity E_max ≈ 1026 V/m.
Ours is given;I = 1.4kW/m2 = 1400 W/m2 is the intensity.
The following is the formula for the maximum value of the electric field in respect to intensity:
E max = (I/2(o•c))
Where;
Electric constant _o is equal to 8.85 10(-12) C2/N.m2.
c is the speed of light, which is 3 10(8) m/s.
Thus;
E max = √(2 × 1400)/(8.85 × 10^(-12) × 3 × 10^(8)))
E max 1026 mV
The maximal magnetic field formula is;
E max/c = B max
B max = 1026/(3 × 10^(8))
B max = 3.46 × 10^(-6) (-6) T
The equation for total power is;
P = IA
Where;
A = area = 4 r2.
Ours is given;
Radius: 1.5 10(11) meters
A = 4π × (1.5 × 10^(11))
² = 2.82 × 10^(23) m²
P = 1400 × 2.82 × 10^(23)
P = 3.95 × 10^(26) W
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Select the correct answer from each drop-down menu.
We can change a gas to liquid by_______ the temperature and______ the pressure
We can change a gas to liquid by decreasing the temperature and increasing the pressure.
What is phase transition?Phase transition is the process by which a substance transforms from one state—solid, liquid, or gas—to another. Every element and substance has a precise range of temperatures and pressures at which it can change from one phase to another.
Each substance can transform into one of three phases: solid, liquid, or gas. At specific temperatures, every substance is in one of these three phases. The intermolecular forces acting on the material's molecules and atoms have a significant impact on the temperature and pressure at which the substance will change.
When we change a gas to liquid, we have to decrease in the temperature and increase in the pressure for this phase transition.
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3. an archer puts a .30 kg arrow to the bowstring. an average force of 201 n is exerted to draw the string back 1.3 m. a. assuming no frictional loss, with what speed does the arrow leave the bow? b. if the arrow is shot straight up, how high does it rise?
(a) The arrow will leave the bow with a velocity 29.51 m/s. (b) The distance covered by the arrow is 44.44 m.
(a)
Let us assume that, the initial velocity of the arrow is v m/s.
It is given that,
The mass of the arrow, m = 0.3 kg.
The average force exerted on the string, F = 201 N.
The distance that the string pulled back, x = 1.3 m.
Let us consider the spring constant is k N/m.
It is known that, the force on the spring, F = kx.
\(\Rightarrow k=\frac{F}{x}\)
\(\Rightarrow k=\frac{201}{1.3} N/m\)
\(\Rightarrow k=154.62 N/m\)
The kinetic energy of any system can be given by, 1/2 mv²
The kinetic energy of a spring system can be given by, \(\frac{1}{2}kx^2\).
Therefore, \(\frac{1}{2}mv^2=\frac{1}{2}kx^2\)
\(\Rightarrow mv^2=kx^2\\\Rightarrow v=\sqrt{\frac{kx^2}{m}}\\\Rightarrow v=\sqrt{\frac{(154.62)(1.3)^2}{0.3}} m/s\\\Rightarrow v=\sqrt{871.026} m/s\)
⇒ v = 29.51 m/s
Hence, the arrow will leave the bow with a velocity 29.51 m/s.
(b)
It is known that,
The initial velocity of the arrow, u = 29.51 m/s.
The final velocity of the arrow, v = 0.
The acceleration due to gravity is g = -9.8 m/s² (Negative sign signifies it is acting opposite to the initial force).
Let us assume that the distance covered by the arrow is s m.
It is known that,
v² = u² + 2as
⇒ (0)² = (29.51)² + 2 (-9.8) s
⇒ 0 = 871.026 - 19.6s
⇒ 19.6s = 871.026
⇒ s = 871.026 / 19.6 m
⇒ s = 44.44 m
Hence, the distance covered by the arrow is 44.44 m.
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Suppose a(t) = 2 measured in seconds. Vt + 4e -5, V(0) = - 4, and S(0) = 5, where act), v(t) and s(t) represent the acceleration, velocity and distance from the starting point of an object. Distance is measured in meters and time is a. Find v(t). b. Find s(t). c. Find the velocity when t = 9. a. v(t) = b. s(t) = C. The velocity is m/sec. (Type an integer or decimal rounded to two decimal places as needed.)
a) The value of the required velocity is v(t) = t²/2 - 4t + 4e⁻⁵
b) The value of the required distance is S(t) = t³/6 - 2t² + 4e⁻⁵t + 5
c) The value of the velocity when t = 9 is approximately -28.2 m/sec
(a)To find v(t), we need to integrate a(t) first
a(t) = 2∫
a(t) dt = ∫ 2
dt = 2t + C1
Here, C1 is the constant of integration
Next, we need to integrate v(t) by substituting the value of a(t) into it
v(t) = ∫ (2t + C1)
dt= t² + C1t + C2
Here, C2 is another constant of integration
v(0) = - 4⇒ C2 = - 4
Also, given: v(t) = Vt + 4e⁻⁵
Comparing the above two equations:
v(t) = Vt + 4e⁻⁵ = t² + C1t - 4
On differentiating with respect to t, we geta(t) = 2
Therefore, we get the differential equation as:
Vt + 4e⁻⁵ = t² + C1t - 4 - - - - - - (1)
To find v(t), we need to solve this differential equation
Substituting t = 0, in (1), we get
-4 + 4 = 0 + C1(0)⇒ C1 = 0
Therefore, the differential equation becomes:
Vt + 4e⁻⁵ = t² - 4
On differentiating the above equation w.r.t t, we get:
a(t) = 2
Therefore, we get
v(t) = t²/2 - 4t + 4e⁻⁵ - - - - - - (2)
Thus, the required velocity is given by:
v(t) = t²/2 - 4t + 4e⁻⁵
Part (b) To find s(t), we need to integrate v(t) first
v(t) = t²/2 - 4t + 4e⁻⁵∫ v(t)
dt = ∫ (t²/2 - 4t + 4e⁻⁵)
dt= t²/6 - 2t² + 4e⁻⁵t + C3
Here, C3 is the constant of integration
Also, given that S(0) = 5⇒ C3 = 5
Therefore, we get
S(t) = t³/6 - 2t² + 4e⁻⁵t + 5 - - - - - - (3)
Thus, the required distance is given by:
S(t) = t³/6 - 2t² + 4e⁻⁵t + 5
Part (c) To find the velocity when t = 9We can use the value of v(t) obtained in part (a)⇒ v(9) = (9)²/2 - 4(9) + 4e⁻⁵⇒ v(9) = - 28.2 (approx)
Thus, the velocity when t = 9 is -28.2 (approx)m/sec.
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need help on these questions
More potential energy can be stored by moving against the magnetic force closer to a magnet?
Answer:
if your saying can it? then yes or if you are asking what type of magnetic force then its fr its actual self magnetic force
Explanation:
Which of the following will occur if the average speed of the gas molecules in a closed rigid container is increased?
(a) The density of the gas will decrease.
(b) The density of the gas will increase.
(c) The pressure of the gas will increase.
(d) The pressure of the gas will decrease.
(e) The temperature of the gas will decrease.
The correct options are (a) and (c) .Increasing the average speed of gas molecules in a closed rigid container will result in an increase in the gas pressure and a decrease in its density. This is due to the increased frequency and force of molecular collisions.
What is the effect of Increased Gas Molecule Speed?If the average speed of the gas molecules in a closed rigid container is increased, it will have several effects on the gas properties. The gas will first become less dense.
This is because the increased speed of the molecules will cause them to spread out more, resulting in a decrease in the number of molecules per unit volume.
Second, the pressure of the gas will increase. The increased speed of the molecules will result in more frequent and forceful collisions with the walls of the container, leading to an increase in the overall pressure exerted by the gas.
Third, the temperature of the gas will increase. The increase in average speed of the molecules is directly related to an increase in kinetic energy, which is a measure of temperature.
Therefore, as the speed of the molecules increases, the temperature of the gas will also increase.
In conclusion, if the average speed of gas molecules in a closed, rigid container increases, the density of the gas decreases, the pressure of the gas rises, and the temperature of the gas rises.
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which of these three words applies to all types of sedimentary rock: weathering, compaction, or deposition
Weathering is words applies to all types of sedimentary rock.
What is Weathering?The breakdown or dissolution of rocks and minerals on the Earth's surface is referred to as weathering. Agents of weathering include water, ice, acids, salts, plants, animals, and variations in temperature.
The breakdown or dissolution of rocks and minerals on the Earth's surface is referred to as weathering. Agents of weathering include water, ice, acids, salts, plants, animals, and variations in temperature.
The effects of weathering and erosion cannot be resisted by any rock on Earth due to its softness. These processes combined to carve famous sites like Arizona's Grand Canyon.
Therefore, Weathering is words applies to all types of sedimentary rock.
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Calculate the ke of a puppy of mass 5 kg
running with a speed of 4 m/s.
The kinetic energy of the puppy would be 40 kg*m^2/s^2, or 40 Joules (J). The formula for kinetic energy (KE) is KE = (1/2)mv² where m is the mass of the object and v is its velocity.
To calculate the kinetic energy (KE) of a puppy with a mass of 5 kg running at a speed of 4 m/s, you can use the formula:
KE = 0.5 × mass × speed^2
Here, the mass is 5 kg and the speed is 4 m/s.
Step 1: Substitute the values into the formula.
KE = 0.5 × 5 kg × (4 m/s)^2
Step 2: Calculate the square of the speed.
(4 m/s)^2 = 16 m^2/s^2
Step 3: Multiply the mass, the speed squared, and 0.5.
KE = 0.5 × 5 kg × 16 m^2/s^2 = 40 kg*m^2/s^2
So, the kinetic energy of the puppy is 40 kg*m^2/s^2, or 40 Joules (J).
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Which characteristic does inertia describe
Answer:
Inertia is the resistance of any physical object to any change in its velocity. This includes changes to the object's speed, or direction of motion. An aspect of this property is the tendency of objects to keep moving in a straight line at a constant speed, when no forces act upon them.
Explanation:
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Answer:- how difficult it is to change an object's motion
Explanation:
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What do you use to write on a blackboard?
Answer:
Chalk, expo markers. Why?
Answer:
Chalk
Explanation:
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the maximum speed limit on interstate 10 is 75 miles per hour. how many meters per second is this
Answer:
33.53m/sExplanation:
Given the maximum speed limit on interstate 10 as 75 miles per hour, to get the speed in meter per seconds, we need to convert the given speed to meter per seconds.
Using the conversion 1 mile = 1609.34m and 1 hour = 3600 seconds
75 miles perhour = 75miles/1 hour
75miles/1 hour (in m/s) = 75miles*1609.34m* 1 hour/1mile * 1 hour * 3600s *
= 75 *1609.34m* 1 /1 * 1 * 3600s
= 120,700.5m/3600s
= 33.53m/s
Hence the maximum speed limit on interstate 10 in metre per seconds is 33.53m/s
The S.I. unit of E is NC^-1 and that of B is NA^-1 m^-1, then unit of E/B is
The S.I. unit of E is NC^-1 and that of B is NA^-1 m^-1, then unit of E/B is A m/C (ampere meter per coulomb). This unit represents the ratio between the electric field and the magnetic field, indicating the strength and direction of the electromagnetic field.
The SI unit of electric field (E) is NC^(-1) (newton per coulomb) and the SI unit of magnetic field (B) is NA^(-1) m^(-1) (tesla). To determine the unit of E/B, we need to divide the unit of E by the unit of B.
Dividing the unit of E (NC^(-1)) by the unit of B (NA^(-1) m^(-1)), we can simplify the expression:
E/B = (NC^(-1))/(NA^(-1) m^(-1))
To simplify this expression, we can cancel out the common units in the numerator and denominator:
E/B = (N/C)/(N/(A m))
Now, let's simplify further by dividing the numerator and denominator:
E/B = (N/C) * (A m/N)
Canceling out the common units:
E/B = (A m)/(C)
Therefore, the unit of E/B is A m/C (ampere meter per coulomb).
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