From the point of view of a spectator, the two children tossing the ball from the float will appear to be moving at a slower speed than the float itself.
The speed of the float is usually around 10 meters per second, so the children will appear to be moving at about 7-8 meters per second. This is because the children are moving with the float, but their tossing the ball introduces an additional component of movement that the spectator will observe.
As the children toss the ball back and forth, their speed will appear to vary between 7-8 meters per second. Thus, the speed of the two children tossing the ball can be approximated to be 7, 8 meters per second.
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A car can accelerate from rest to a speed of 28 m/s in 20 s. What is the average acceleration of the car
Formula for acceleration:
\(a=\dfrac{V^f-V^I}{t}\)
acceleration(measured in m/s^2) = Final velocity(measured in m/s) - Initial velocity(measured in m/s) / time(measured in seconds)
__________________________________________________________
Given:
\(V^I=0m/s\) (rest)
\(V^f=28m/s\)
\(t=20s\)
\(a=?\)
__________________________________________________________
Finding acceleration:
\(a=\dfrac{V^f-V^I}{t}\)
\(a=\dfrac{28-0}{20}\)
__________________________________________________________
Answer:
\(\boxed{a=1.4m/s^2}\)
Savanna regions developed during the Triassic period.
Please select the best answer from the choices provided
T
F
Hurry i have until 4 to turn in
A man walks 7 m north in 15 seconds and then south for 2 m in 8 seconds. What is the
man's average speed?
Answer:
9miles average speed and 23 seconds
Anyone get this if you do please help me step by step
Answer:
$7.95
Explanation:
$5.75 cost per bag ÷ 47 apples = unit cost of $0.1223. thus, each apple cost $ .1223.
.1223 × 65 apples= $7.95
note_rounding apples to .12*65=$7.8
Can someone help me, it will get 5 stars
Answer:
A. Increased self-esteem
Explanation:
I hope this helps :)
Explain how a book can have energy even if it is not moving.
A skater with a mass of 50 kg is moving at a speed of 5 m/s. Away is their kinetic energy?
1. Determine the energy released per kilogram of fuel used.
Given MeV per reaction, calculate energy in joules per kilogram of reactants.
Consider 1 mole of uranium-235 to be a mole of “reactions” (molar mass = 235 grams).
2. Determine the energy released per kilogram of fuel used.
Given MeV per reaction, calculate energy in joules per kilogram of reactants.
Consider 1 mole of uranium-235 to be a mole of “reactions” (molar mass = 235 grams).
200 MeV of energy is the energy released per kilogram of fuel used.
E1/E2=7.61=8 (E1 , E2 are energies)
U is equal to 1 kilogram or 1000 g.
There are 6.02310 23 atoms in one mole, or 235 g, of uranium. Therefore, 6.02310 23 atoms are present in 1000 g of 92/235 U.
It is understood that one atom releases 200 MeV of energy during its fission.
As a result, the energy released from the fission of one kilogram of 92/235 is given by E 2 = 6.02310 23 1000200/235 =5.10610 26 MeV E1/E2=7.61=8
In light of this, the energy released during the fusion of one kilogram of hydrogen is roughly eight times greater than the energy generated during the fission of one kilogram of uranium.
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Answer:
200 MeV of energy is the energy released per kilogram of fuel used.
E1/E2=7.61=8 (E1 , E2 are energies)
U is equal to 1 kilogram or 1000 g.
There are 6.02310 23 atoms in one mole, or 235 g, of uranium. Therefore, 6.02310 23 atoms are present in 1000 g of 92/235 U.
It is understood that one atom releases 200 MeV of energy during its fission.
As a result, the energy released from the fission of one kilogram of 92/235 is given by E 2 = 6.02310 23 1000200/235 =5.10610 26 MeV E1/E2=7.61=8
In light of this, the energy released during the fusion of one kilogram of hydrogen is roughly eight times greater than the energy generated during the fission of one kilogram of uranium.
A mass attached to a 57.8 cm long string starts from rest andis rotated 44.8 times in 60.0 s before reaching a final angularspeed. (A) determine the acceleration of the mass, assuming that itis constant. (B) What is the final angular speed of the mass
(A) 0.125 rad/s2 X
(B) 9.0 rad/s2 X
(A) The acceleration of the mass, assuming it is constant, is 0.125 rad/s^2.
(B) The final angular speed of the mass is 9.0 rad/s.
(A) To determine the constant acceleration of the rotating mass, we can use the relationship between angular displacement, angular velocity, and acceleration. By dividing the total angular displacement (44.8 rotations or 89π radians) by the time taken (60.0 seconds), we find the average angular velocity. Then, by dividing the average angular velocity by the time taken, we obtain the constant acceleration of 0.125 rad/s^2.
(B) The final angular speed of the mass can be calculated by multiplying the constant acceleration by the time taken (60.0 seconds). Since the acceleration is constant, the angular speed increases linearly with time. Therefore, the final angular speed is determined to be 9.0 rad/s.
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An ideal gas is compressed isobarically to one-fourth of its initial volume. the resulting pressure will be:_________
less than three times as large as the initial value.
What is isobaric compression?
An isobaric process is shown on a P–V diagram as a straight horizontal line, connecting the initial and final thermostatic states.
If the process moves towards the right, then it is an expansion. If the process moves towards the left, then it is a compression.
What happens to pressure in isobaric compression?Isobaric process is a thermodynamic process that takes place under constant pressure.
Temperature, volume, and internal energy are not constant in this process, even though the pressure is constant.
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Tom has been hired to deliver 11 m3 of sand. If the truck that Tom is driving has a truck bed that is 2.5 m X 1.6 m, X 0.75 m how many trips will Tom need to complete the order?
PLS GO TO MY PROFILE TO SEE THE OTHER QUESTIONS I POSTED I GIVE BRAINLY THING FOR THOSE AS WELL THANK YOU
Answer:
About 3 trips
Explanation: if we do 2.5m*1.6m*0.75 it equals to 11000 then we divide that to 11m3 and it gives you 3.6 so it will be about 3 times
Thx
Conservation of Momentum
No one likes you little trolls please send an actual answer
Hello!
This is an example of an inelastic collision, where the two objects "stick" to each other after their collision. (The Goalkeeper CATCHES the puck).
We can write out the conservation of momentum formula:
m1vi + m2vi = m1vf + m2vf
Let:
m1 = mass of puck
m2 = mass of the goalkeeper
We know that the initial velocity of the goalkeeper is 0, so:
m1vi + m2(0) = m1vf + m2vf
m1vi = m1vf + m2vf
The final velocities will be the same, so:
m1vi = (m1 + m2)vf
Plug in the given values:
(0.16)(40)/ (0.16 + 120) = vf ≈ 0.0533 m/s
Using the equation for momentum:
p = mv
The object with the LARGER mass will have the greater momentum. Thus, the Goalkeeper has the largest momentum as p = mv; a greater mass correlates to a greater momentum since the velocity is the same between the two objects. The puck would have a momentum of p = (.16)(0.0533) = 0.008528 kgm/s, whereas the goalkeeper would have a momentum of
p = (120)(0.0533) = 6.396 kgm/s.
a vector has an x component of -22.5 units and a y component of 37.4 units. find the magnitude and direction of this vector.
The magnitude of the vector is 43.81 units and the direction of the vector is 120.89 degrees with a +x-axis counterclockwise.
What is the magnitude and direction of a vector?The length for a certain vector (let's say v) can be calculated by using the symbol |v|, which stands for the magnitude of a vector formula. In essence, this measurement represents the separation between the vector's starting and ending points. We apply the distance formula to get the vector's magnitude.
Its direction indicates where it points. Although vector direction can be expressed in a number of ways, degrees are the most frequent notation.
The magnitude of the given vector will be
\(\vec{r} &=x i+y j \\\vec{r}=-22.5 \hat{i}+37.6 \hat{j} \\{[\vec{r}] } &=\sqrt{(22.5)^2+(37.6)^2} \\&=43.81 units\)
The direction of the vector will be
tanα=\(\frac{y}{x}\\\)
\(=tan^{-1}(\frac{y}{x})\\=tan^{-1}(\frac{37.6}{22.5}\\=59.103 degree\)
Therefore, the direction of the vector is 120.89 degrees with the +x-axis counterclockwise.
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A 1400 kg car traveling at 17.0 m/s to the south collides with a 4700 kg truck that is at rest. The car and truck stick together and move together after collision. What is the final velocity of the two-vehicle mass? If Kinetic Energy = 0.5 * m * v^2, calculate the KE before the crash and the KE of the combined vehicles after the crash.
Answer:
Final velocity = 7.677 m/s
KE before crash = 202300 J
KE after crash = 182,702.62 J
Explanation:
We are given;
m1 = 1400 kg
m2 = 4700 kg
u1 = 17 m/s
u2 = 0 m/s
Using formula for inelastic collision, we have;
m1•u1 + m2•u2 = (m1 + m2)v
Where v is final velocity after collision.
Plugging in the relevant values;
(1400 × 17) + (4700 × 0) = (1400 + 1700)v
23800 = 3100v
v = 23800/3100
v = 7.677 m/s
Kinetic energy before crash = ½ × 1400 × 17² = 202300 J
Kinetic energy after crash = ½(1400 + 1700) × 7.677² = 182,702.62 J
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the table below shows the right ascensions of two stars at a location.
Name of star Right ascension
Star 1 2 hours
Star 2 4 hours 30 minutes
What is the interval between the times when the two stars rise at the location? (10 points)
Group of answer choices
2 hours
30 minutes
2 hours 30 minutes
4 hours 30 minutes
Answer:
Explanation:
It would actually be A. 30 , as each hour of ascension (i am not sure about the correct terminology) equals 15 .
Answer:
30
Explanation:
any two difference between negative and positive charge of class 7 please fast
Answer:
any two difference between negative and positive charge
➢The matter is positively charged if it contains more protons than electrons, and it is negatively charged if it contains more electrons than protons.
Explanation:
I hope it will help you.....
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The speed of all electromagnetic waves is 3. 00 × 108 meters per second. What is the wavelength of an X-ray with a frequency of 1. 18 × 1018 Hz? 2. 54 × 1026 meters 3. 93 × 109 meters 2. 54 × 10-10 meters 3. 93 × 10-11 meters.
PLEASE ITS PORTOFOLIO WORK
A car has a mass of 900 kg. he moves from rest with acceleration 1.2 m / s.
Calculate the force required to give the car that acceleration.
Answer:
I'm pretty sure its 1080
Explanation:
force is = to mass multiplied by acceleration.
So 900 kg multiplied by 1.2m/s is = to 1080
I'm no expert so please tell me if I'm wrong so that I can improve.
Have fun buddy .
Which diagram shows the most likely effect when a rock is weathered by water flowing over its entire surface
Answer:
the answer to this would be D.
Answer: Its D but it might swap to another letter so keep your eye out bud pass this test good luck
Explanation:
If a bicycle has an average acceleration of -0.44 m/s^2, and its initial forward velocity is 8.2 m/s, how long will it take the cyclist to bring the bicycle to a complete stop
Answer:
The value is \(t = 18.6 s\)
Explanation:
From the question we are told that
The average acceleration of the bicycle is \(v = -0.44 \ m/s^2\)
The initial forward velocity is \(u = 8.2 \ m/s\)
Generally from kinematic equations we have that
\(v = u + at\)
Here v is the final velocity of the bicycle and the value is v = 0 m/s
So
\(0 = 8.2 + (-0.44)t\)
=> t = 18.6 s
A mixture is made of two or more materials that
The ratio between the force of friction and the normal force is called:
A.the drag
B.rolling friction
C.the coefficient of friction
D.the starting friction
Answer:
C.the coefficient of friction
Explanation:
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Se lanza desde el piso una piedra con velocidad vertical de +42 m/s. El punto de referencia se encuentra en el piso. Calcular: a). Escribir la ecuación de posición y la ecuación de la velocidad. b). Calcular en que instante su velocidad es nula. c). Calcular la máxima altura que llego. (Considerar la aceleración de la gravedad: a=9.81m/s2).
Answer:
a) y = 42 t - 4,905 t² , v = 42 - 9.81 t, b) t = 4.281 s , c) y = 89.9 m
Explanation:
This problem is an example of vertical launch
a) the expression for the position is
y = v₀ t - ½ g t²
we substitute
y = 42 t - 4,905 t²
the expression for speed is
v = v₀ - gt
v = 42 - 9.81 t
b) the speed is null when v = 0
v₀ = gt
t = v₀ / g
t = 42 / 9.81
t = 4.281 s
c) for the maximum height we can use the expression
v² = v₀² - 2gy
at maximum height v = 0
y = v₀² / 2g
let's calculate
y = 42 2/2 9.81
y = 89.9 m
a net force of 219 N is exterted on a rock. the rock has an acceleration of 3m/s^2 due to this force. what is the mass of the rock
Answer:
73 kgExplanation:
The mass of the object can be found by using the formula
\(m = \frac{f}{a} \\ \)
f is the force
a is the acceleration
From the question we have
\(m = \frac{219}{3} \\ \)
We have the final answer as
73 kgHope this helps you
when are forces applied to pendulums to counteract friction
Forces may be applied to pendulums to counteract friction when the goal is to maintain the pendulum's motion over an extended period of time, or to reduce the effects of external disturbances that may interfere with the motion of the pendulum.
Friction is a force that acts to slow down the motion of a pendulum, leading to a decrease in amplitude over time. In addition, external forces such as air resistance, which acts in the opposite direction to the motion of the pendulum, can also cause a decrease in amplitude. To counteract these forces, additional forces can be applied to the pendulum.
One common method for reducing the effects of friction on a pendulum is to use a device called a "driving force" or "motor". This device applies a force to the pendulum at the right time and in the right direction to maintain or increase the amplitude of the pendulum's motion. This method is used in many types of clocks and other precision instruments that rely on the motion of a pendulum.
Another method is to use an electromagnet to attract and release the pendulum at precisely the right time to keep its motion going. This method is often used in high-precision pendulum clocks and scientific experiments.
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3. Over which of the following time intervals is
the acceleration of the object the greatest?
A. 0 s to 1 s
B. 1 s to 2 s
C. 2 s to 3 s
D. 4 s to 5 s
Answer:
A. 0s to 1s
Explanation:
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Air pollution caused by the reaction of nitrogen compounds and other pollutants in the presence of sunlight is
Nitrogen oxides play a critical role in photochemical smog. They give the smog its yellowish-brown hue. Indoor residential appliances like gas stoves and gas or wood heaters can be significant emitters of nitrogen oxides in poorly ventilated environments.
Nitrogen dioxide (NO₂), ozone (O₃), peroxyacetyl nitrate (PAN), and chemical compounds with the -CHO group are the main harmful elements of photochemical smog (aldehydes). If present in high enough amounts, PAN and aldehydes can harm plants and irritate the eyes.The greatest sources of emissions are power plants, heavy construction equipment driven by diesel, other moveable engines, and industrial boilers. Cars, trucks, and buses are next in line.Therefore , on conclusion i.e. two gases with molecules consisting of nitrogen and oxygen atoms are nitric oxide (NO) and nitrogen dioxide (NO₂). These nitrogen oxides play a part in the development of smog and acid rain, adding to the issue of air pollution.
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PLS HELP ASAP it's just 2 questions and they are multiple choice!
Consider the straight bar of a uniform elliptical cross-section. The semimajor and semiminor axes are a and b, respectively. Show that the stress function of the form + provides the solution for torsion of the bar. Find the expression of C and show that лазь3 a2 +b2 —2Ty Izx Тzy 2Tx лаbЗ» лазь and the warping displacement т(? — а?). -ху лазь3G
The stress function of the form Φ = C(x²- y²) provides the solution for torsion of the bar.
How can we determine the expression of C and derive the given equation?To determine the expression of C and derive the given equation, we consider the torsion of a straight bar with a uniform elliptical cross-section. The stress function Φ is assumed to have the form Φ = C(x²- y²), where C is a constant.
By substituting the stress function into the torsion equation and solving for the shear stress τxy, we find that τxy = 2GC(xsin(θ) - ycos(θ)), where G is the shear modulus and θ is the angular coordinate.
To find the expression of C, we compare this equation with the given equation and equate the terms. This leads us to C = Ty/(2G), where Ty is the applied torque.
By further substituting the expressions for x and y in terms of the semimajor and semiminor axes, we can rewrite the equation as τxy = Ty(a²+ b²- 2Jx/R²), where J is the torsional constant and R is the radius of the cross-section.
The warping displacement θ(Φ - Φ0) can be obtained by integrating the torsion equation, which involves the shear stress τxy and the differential area of the cross-section. This displacement can be expressed as θ(Φ - Φ0) = -G∫(τxy dA).
In summary, the stress function Φ = C(x²- y²) provides the solution for torsion of the bar, where C = Ty/(2G) and the derived equation is τxy = Ty(a²+ b² - 2Jx/R²). The warping displacement can be calculated through the integration of the torsion equation.
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To calculate the components of the initial velocity (vvivvi), you have to identify the correct motion equations.
A golfer hits a golf ball that travels 60 m across the field and takes 3.2 seconds to reach the ground.
What is the horizontal component of initial velocity?
Horizontal component of initial velocity = Vx = Cosθ x 18.75m/s
An object that is given an initial velocity and then affected by gravity is referred to as a projectile. These effects determine the course that the object takes. The object's trajectory is what we refer to as. A projectile's trajectory is determined by velocity in two dimensions. The projectile's x and y components each represent its horizontal and vertical motion, respectively. Meters are the units used to indicate both horizontal and vertical distances (m). Meters per second (m/s) is the unit used to express the horizontal and vertical velocities.
A projectile is in freefall once it has started moving. Gravity's downward acceleration is the sole acceleration that is having an effect on it. The magnitude of the acceleration caused by gravity (on Earth) is
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