A farmer is fencing off his field. A diagram is given and shows how the field has been divided into two regions. Find the perimeter of the entire field. Reaction 1 has length 530 feet and width 526 feet. Region 2 has length 974 feet and width 526 feet. a. 2556 ft c. 4052 ft b. 4060 ft d. 5112 ft

Answers

Answer 1

Answer:

the answer is B 4060 ft

Step-by-step explanation:

the answer is B have a nice day


Related Questions

WILL GET MARKED THE BRAINIEST
Which logic statement represents this argument?

If it’s a weekend, I exercise. It’s not a weekend. So, I won’t exercise.

Assume that p represents “It’s a weekend” and q represents “I exercise.”

A.
(p q) p
B.
[(p q) p] q
C.
[(p q) p] q
D.
[(p q) p] q

Answers

Hey the signs are not showing if you write the signs I’ll answer it in the comments :))

Given that one standard deviation below the mean is 24 and one standard deviation above the mean is 31, what is the mean l?

A)55
B)34
C)27.5
D)28

Answers

Answer:

C. 27.5

Step-by-step explanation:

since 24 and 31 are one standard deviation below or above the mean, we could subtract the two values and divide them by two to help find the mean.

we would first subtract the two values

31-24 = 7

we would then divide that number by 2 since we are finding the average between the two numbers

7/2 = 3.5

using the 3.5, you add it to the lower value (24) and subtract it from the higher value (31)

24+3.5 = 27.531-3.5 = 27.5

since both calculated numbers were equal, we know that we calculated the mean correctly.

Simplify (3x – 5) + (5x + 1).

Answers

Answer:

(-2x - 6)

Step-by-step explanation:

The given expression is ( 3x - 5 ) - ( 5x + 1 )

We have to simplify the given expression

First we will open the bracket having negative notation outside.

( 3x - 5 ) - 5x - 1

3x - 5 - 5x - 1

Now we will collect the similar terms together.

3x - 5x - 5 -1

-2x - 6

So the simplified form of the expression is (-2x - 6)

Answer:

8x - 4

Step-by-step explanation:

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These figures are similar. The perimeter and area of one are given. The perimeter of the other is also given. Find its area and round to the nearest tenth.
Perimeter= 20m
Area=19.6m^2
Perimeter=34m
What is the Area=

These figures are similar. The perimeter and area of one are given. The perimeter of the other is also

Answers

The area of the larger figure that is similar to the smaller one is: 28.2 m².

How to Find the Area of Similar Figures?

Where A and B represent the areas of two similar figures, and a and b are their corresponding side lengths, respectively, the formula that relates their areas and side lengths is:

Area of figure A / Area of figure B = a²/b².

Given that the two figures are similar as shown in the image above, find each of their respective side lengths if we are given the following:

Perimeter of smaller figure = 20 m

Area of smaller figure = 19.6 m²

Perimeter of larger figure = 34m

Area of larger figure = x

Therefore:

20/34 = a/b

Simplify:

10/17 = a/b.

Find the area (x) of the larger figure using the formula given above:

10²/12² = 19.6/x

100/144 = 19.6/x

100x = 2,822.4

x = 2,822.4/100

x ≈ 28.2 m²

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Greatest common multiple
of 12,27

Answers

Answer:

3

Step-by-step explanation:

3x4=12

3x9=27

4 cannot go into 27 without passing 9

Answer:

Factor of 12

= 2 × 2 × 3

Factor of 27

= 3 × 3 × 3

Now ,

CF = 3

HCF = 3

hence...the greatest common multiple of 12 and 27 is 3

\(...\)

Plot the point whose polar coordinates are given. Then find the Cartesian coordinates of the point.
(a) 8, 4/3
(x, y) =
(b) −4, 3/4
(x, y) =
(c) −9, − /3
(x, y) =

Answers

The Cartesian coordinates for point (c) are: (x, y) = (4.5, -7.794) which can be plotted on the graph using polar coordinates.

A system of describing points in a plane using a distance and an angle is known as polar coordinates. The angle is measured from a defined reference direction, typically the positive x-axis, and the distance is measured from a fixed reference point, known as the origin. In mathematics, physics, and engineering, polar coordinates are useful for defining circular and symmetric patterns.


(a) Polar coordinates (8, 4/3)
To convert to Cartesian coordinates, use the formulas:
x = r*\(cos(θ)\)
y = r*\(sin(θ)\)
For point (a):
x = 8 * \(cos(4/3)\)
y = 8 * \(sin(4/3)\)

Therefore, the Cartesian coordinates for point (a) are:
(x, y) = (-4, 6.928)

(b) Polar coordinates (-4, 3/4)
For point (b):
x = -4 * \(cos(3/4)\)
y = -4 * \(sin(3/4)\)

Therefore, the Cartesian coordinates for point (b) are:
(x, y) = (-2.828, -2.828)

(c) Polar coordinates (-9, \(-\pi /3\))
For point (c):
x = -9 * \(cos(-\pi /3)\)
y = -9 * \(sin(-\pi /3)\)

Therefore, the Cartesian coordinates for point (c) are:
(x, y) = (4.5, -7.794)

Now you have the Cartesian coordinates for each point, and you can plot them on a Cartesian coordinate plane.


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A baseball traveled 330 feet in 5 seconds. Which rate is equivalent to the rate at which the baseball traveled?

A.
55 feet per second


B.
66 feet per second


C.
55 seconds per foot


D.
66 seconds per foot

(just the answer pls)

Answers

Answer:

I think it's B.

Step-by-step explanation:

If m<1=105 and m<4=115, then m<6=

A.75 B.40 C.50 D.60​

Answers

the answer is 40 so B

Fill in the missing number. % of 98 = 49

Answers

50%

since 98/2 = 49

Thats it

Graphically determine the optimal solution, if it exists, and the optimal value of the objective function of the following linear programming problems. 1. 2. 3. maximize z = x₁ + 2x₂ subject to 2x1 +4x2 ≤6, x₁ + x₂ ≤ 3, x₁20, and x2 ≥ 0. maximize subject to z= X₁ + X₂ x₁-x2 ≤ 3, 2.x₁ -2.x₂ ≥-5, x₁ ≥0, and x₂ ≥ 0. maximize z = 3x₁ +4x₂ subject to x-2x2 ≤2, x₁20, and X2 ≥0.

Answers

The maximum value of the objective function z is 19, and it occurs at the point (5, 1).Hence, the optimal solution is (5, 1), and the optimal value of the objective function is 19.

1. Graphically determine the optimal solution, if it exists, and the optimal value of the objective function of the following linear programming problems.
maximize z = x₁ + 2x₂ subject to 2x1 +4x2 ≤6, x₁ + x₂ ≤ 3, x₁20, and x2 ≥ 0.

To solve the given linear programming problem, the constraints are plotted on the graph, and the feasible region is identified as shown below:

Now, To find the optimal solution and the optimal value of the objective function, evaluate the objective function at each corner of the feasible region:(0, 3/4), (0, 0), and (3, 0).

        z = x₁ + 2x₂ = (0) + 2(3/4)

                    = 1.5z = x₁ + 2x₂ = (0) + 2(0) = 0

                        z = x₁ + 2x₂ = (3) + 2(0) = 3

The maximum value of the objective function z is 3, and it occurs at the point (3, 0).

Hence, the optimal solution is (3, 0), and the optimal value of the objective function is 3.2.

maximize subject to z= X₁ + X₂ x₁-x2 ≤ 3, 2.x₁ -2.x₂ ≥-5, x₁ ≥0, and x₂ ≥ 0.

To solve the given linear programming problem, the constraints are plotted on the graph, and the feasible region is identified as shown below:

To find the optimal solution and the optimal value of the objective function,

        evaluate the objective function at each corner of the feasible region:

                                (0, 0), (3, 0), and (2, 5).

                          z = x₁ + x₂ = (0) + 0 = 0

                          z = x₁ + x₂ = (3) + 0 = 3

                           z = x₁ + x₂ = (2) + 5 = 7

The maximum value of the objective function z is 7, and it occurs at the point (2, 5).

Hence, the optimal solution is (2, 5), and the optimal value of the objective function is 7.3.

maximize z = 3x₁ +4x₂ subject to x-2x2 ≤2, x₁20, and X2 ≥0.

To solve the given linear programming problem, the constraints are plotted on the graph, and the feasible region is identified as shown below:

To find the optimal solution and the optimal value of the objective function, evaluate the objective function at each corner of the feasible region:(0, 1), (2, 0), and (5, 1).

                         z = 3x₁ + 4x₂ = 3(0) + 4(1) = 4

                      z = 3x₁ + 4x₂ = 3(2) + 4(0) = 6

                      z = 3x₁ + 4x₂ = 3(5) + 4(1) = 19

The maximum value of the objective function z is 19, and it occurs at the point (5, 1).Hence, the optimal solution is (5, 1), and the optimal value of the objective function is 19.

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Gianna invested $60,000 in an account paying an interest rate of 3.4% compounded
daily. Assuming no deposits or withdrawals are made, how much money, to the
nearest ten dollars, would be in the account after 11 years?

Answers

To the nearest ten dollars, there would be approximately $81,329 in the account after 11 years.

To calculate the future value of an investment with compound interest, we can use the formula:

FV = P(1 + r/n)^(nt)

Where:

FV = Future value

P = Principal amount (initial investment)

r = Annual interest rate (as a decimal)

n = Number of times interest is compounded per year

t = Number of years

In this case:

P = $60,000

r = 3.4% = 0.034 (as a decimal)

n = 365 (daily compounding)

t = 11 years

Plugging in these values, we can calculate the future value (FV):

FV = $60,000 * (1 + 0.034/365)^(365*11)

Calculating this expression, we find:

FV ≈ $60,000 * (1.000093835)^40015 ≈ $81,329.20

Therefore, to the nearest ten dollars, there would be approximately $81,329 in the account after 11 years.

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if the sun is directly over the beanstalk, how many days after the beanstalk was planted would the beanstalk reach the sun? (the sun is 92,960,000 miles from the earth, and there are 5,280 feet in 1 mile.)

Answers

How much does the beanstalk grow?

will mark as brainliest

...

will mark as brainliest...

Answers

Answer:

Third sequence (7, 2, 1, -4, -10)

In the first sequence, -4 has to be in front of -10 because it is larger.

In the second sequence, 7 goes in the beginning, with 2 then 1 following, with -4 behind and -10 behind -4.

In the third option, 7 must be in the front, with 2, 1, then -4, then -10 following.

The answer = third sequence.

Hope it helped!

Answer:

7, 2, 1, -4, -10

Step-by-step explanation:

-10 is the least number because in negative numbers are basically the opposite of positive number (if that makes sense). I don't really know what else to explain, but I hope this helps!!!

3. The system of equations for two liquid surge tanks in series is
A₁ dh'₁/dt = q'ᵢ - 1/R₁ h'₁, q'₁ = 1/R₁ h'₁
A₂ dh'₂/dt = 1/R₁ h'₁ - 1/R₂ h'₂ q'₂ = 1/R₂ h'₂
Using state-space notation, determine the matrices A,B,C, and D assuming that the level deviations are the state variables: h'₁ and h'₂. The input variable is q'ᵢ , and the output variable is the flow rate deviation, q'₂.

Answers

The surge tank is a vital component of a system in which the flow rate fluctuates significantly. The flow rate entering the tank varies significantly, causing the fluid level in the tank to fluctuate as a result of the compressibility of the liquid. The surge tank is utilized to reduce pressure variations generated by a rapidly fluctspace uating pump flow rate. To determine the matrices A,B,C, and D using state-space notation, here are the steps:State representation is given by:dx/dt = Ax + Bu; y = Cx + DuWhere: x represents the state variablesA represents the state matrixB represents the input matrixC represents the output matrixD represents the direct transmission matrixThe equation can be written asA = [ -1/R₁ 0; 1/R₁ -1/R₂]B = [1/A₁; 0]C = [0 1/R₂]D = 0Thus, the matrices A,B,C and D assuming that the level deviations are the state variables: h'₁ and h'₂. The input variable is q'ᵢ, and the output variable is the flow rate deviation, q'₂ are given by A = [ -1/R₁ 0; 1/R₁ -1/R₂]B = [1/A₁; 0]C = [0 1/R₂]D = 0.Hence, the required matrices are A = [ -1/R₁ 0; 1/R₁ -1/R₂], B = [1/A₁; 0], C = [0 1/R₂], and D = 0 using state-space notation for the given system of equations for two liquid surge tanks.

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suppose that an
and
bn
are series with positive terms and bn ia convergent prove that if lim an/bn =0 then an is also convergent
show that the series congerges lnn/n3 lnn/n^1/2 en

Answers

The series on the right-hand side is a convergent p-series with p = 2. Therefore, by the comparison test, the original series converges as well.

To prove that if lim an/bn = 0 and bn is convergent, then an is also convergent, we can use the limit comparison test. Since bn is convergent, we know that its terms approach 0. Therefore, we can choose a positive number ε such that 0 < ε < bn for all n. Then, we have:

lim (an/bn) = 0
=> for any ε > 0, there exists N such that for all n > N, |an/bn| < ε
=> for all n > N, an < εbn

Since ε is a positive constant and bn is convergent, we know that εbn is also convergent. Therefore, by the comparison test, an is convergent as well.

To show that the series ∑(ln n)/(n^3 ln n^1/2 e^n) converges, we can use the comparison test again. Note that:

ln n^1/2 = (1/2)ln n
ln n^3 = 3ln n

Therefore, we can rewrite the series as:

∑[(1/2)/(n^2 e^(ln n))] = (1/2)∑(1/(n^2 n^ln(e)))

Since n^ln(e) > 1 for all n, we have:

(1/2)∑(1/(n^2 n^ln(e))) < (1/2)∑(1/n^2)

The series on the right-hand side is a convergent p-series with p = 2. Therefore, by the comparison test, the original series converges as well.

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Amelia went to an amusement park with $45 to spend. She bought lunch for $10.25 and paid $5.00 for each ride. What is the greatest number of rides Amelia could ride?

Answers

Answer:

Your answer is $34.75

Step-by-step explanation:

plz mark me brainliest

Answer:

6

Step-by-step explanation:

It takes a word processor 24 minutes to word process and spell check 10 pages find how long it takes her to word process and spell check 55 pages It takes the word processor ? Minutes

It takes a word processor 24 minutes to word process and spell check 10 pages find how long it takes

Answers

Given,

It takes a word processor 24 minutes to word process and spell check 10 pages.

Consider,

Time taken by the word processor to word process and spell check 55 pages is x.

According to the question,

\(\begin{gathered} \frac{10}{24}=\frac{55}{x} \\ 10x=24\times55 \\ 10x=1320 \\ x=\frac{1320}{10} \\ x=132\text{ minutes} \end{gathered}\)

Time taken by the word processor to word process and spell check 55 pages is 132 minutes.

I have five apples and ten oranges. If a fruit basket must contain at least one piece of fruit, how many kinds of fruit baskets can I make

Answers

Answer:

answer is 15

please that is what I'm thinking

38. What is the solution to 2(x - 6) = 14?

40. Simplify: 8(2x - 2)
HELP! answer if you can there's two questions​

Answers

Answer:

x=13, 16(x-1)

Step-by-step explanation:

For 38, you have to first divide both sides by 2.

This becomes, x-6=7

Add 6 to both sides

x=13.

For 40. You can can distribute the 8.

This makes it 16x-16.

With this you can than, factor out the 16.

16(x-1).

Answer:

x =1316x-16

Step-by-step explanation:

38.

\(2(x - 6) = 14\\\\\mathrm{Divide\:both\:sides\:by\:}2\\\\\frac{2\left(x-6\right)}{2}=\frac{14}{2}\\\mathrm{Simplify}\\x-6=7\\\mathrm{Add\:}6\mathrm{\:to\:both\:sides}\\\\x-6+6=7+6\\\\x=13\)

40.

\(8(2x - 2)\\\mathrm{Apply\:the\:distributive\:law}:\\\quad \:a\left(b-c\right)=ab-ac\\\\a=8,\:b=2x,\:c=2\\\\=8\times \:2x-8\times \:2\\\\=16x-16\)

Need help please!!!!

Need help please!!!!

Answers

Answer:

b^(-4/5) ...............

What is the x- intercept of the line 2x-3x=-4

Answers

Answer:

(4,0)

Step-by-step explanation:

Solve for x so 2x - 3x = -4 then -x = -4 so x = 4

What are the roots of the quadratic equation 0 = 2x² + 12x-14?
1,6, -7
2,12,-14
-7,1
-1,7

Answers

The roots of the quadratic equation 0 = 2x² + 12x-14 is (C) x=-7 and x=1.

What is a quadratic equation?

Any equation in algebra that can be written in the standard form where x stands for an unknown value and a, b, and c stand for known values is said to be a quadratic equation.

In general, it is assumed that a > 0; equations with a = 0 are regarded as degenerate since they become linear or even simpler.

So, the roots of 0 = 2x² + 12x-14 are:

2x² + 12x-14  = 0

2x² + 14x - 2x -14

2x(x + 7) - 2(x + 7)

(2x - 2) (x + 7)

Now, use the zero product property as follows:

2x - 2 = 0

2x = 2

x = 2/2

x = 1

And

x + 7 = 0

x = -7

Therefore, the roots of the quadratic equation 0 = 2x² + 12x-14 is (C) x = -7 and x = 1.

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Correct question:

What are the roots of the quadratic equation 0 = 2x² + 12x-14?

a. 1,6, -7

b. 2,12,-14

c. -7,1

d. -1,7

Consider a sample with six observations of 16, 11, 13, 22, 15, and 19. Compute the z-score for each observation. (Leave no cells blank - be certain to enter "0" wherever required. Round your answers to 2 decimal places. Negative values should be indicated by a minus sign.) Sample observations z-score 16 11 13 22 15 19

Answers

To compute the z-score for each observation, we need to standardize the data using the formula z = (x - μ) / σ, where x is the individual observation, μ is the mean of the sample, and σ is the standard deviation of the sample.

Given the sample observations: 16, 11, 13, 22, 15, and 19, we can calculate the z-score for each observation as follows:

Calculate the mean (μ) of the sample:

μ = (16 + 11 + 13 + 22 + 15 + 19) / 6 = 16

Calculate the standard deviation (σ) of the sample:

Step 1: Calculate the squared deviations from the mean for each observation:

(16 - 16)², (11 - 16)², (13 - 16)², (22 - 16)², (15 - 16)², (19 - 16)²

0, 25, 9, 36, 1, 9

Step 2: Calculate the variance:

Variance = (0 + 25 + 9 + 36 + 1 + 9) / 6 = 80 / 6 ≈ 13.33

Step 3: Calculate the standard deviation:

σ = √(Variance) = √13.33 ≈ 3.65

Calculate the z-score for each observation:

z = (x - μ) / σ

For 16: z = (16 - 16) / 3.65 = 0 / 3.65 = 0

For 11: z = (11 - 16) / 3.65 = -5 / 3.65 ≈ -1.37

For 13: z = (13 - 16) / 3.65 = -3 / 3.65 ≈ -0.82

For 22: z = (22 - 16) / 3.65 = 6 / 3.65 ≈ 1.64

For 15: z = (15 - 16) / 3.65 = -1 / 3.65 ≈ -0.27

For 19: z = (19 - 16) / 3.65 = 3 / 3.65 ≈ 0.82

The z-scores for the given sample observations are: 0, -1.37, -0.82, 1.64, -0.27, and 0.82.

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Part A
Construct a circle of any radius, and draw a chord on it. Then construct the radius of the circle that bisects the chord. Measure the angle between the chord and the radius. What can you conclude about the intersection of a chord and the radius that bisects it? Take a screenshot of your construction, save it, and insert the image below your answer.

Part B
Write a paragraph proof of your conclusion in part A. To begin your proof, draw radii OA and OC.

Part C
In this part of the activity, you will investigate the converse of the theorem stated in part A. To get started, reopen GeoGebra.

Draw a circle of any radius, and draw a chord on it. Construct the radius of the circle that is perpendicular to the chord. Measure the line segments into which the radius divides the chords. How are the line segments related? What can you conclude about the intersection of a chord and a radius that is perpendicular to it? Take a screenshot of your construction, save it, and insert the image below your answer.

Part D
Write a paragraph proof of your conclusion in part C. To begin your proof, draw radii OA and OC.

Answers

Answer:

All answers are bold and links are real photos  

BTW THE PHOTOS ARE IN ORDER OF THE ANSWERS

Brainlyist??

Step-by-step explanation:

Task 1

Part A

Tangent Line

Part B

PHOTO WITH LARGE CIRCLE AND LINE OUT SIDE BUT CONNECTED

Part C

2034.7

PHOTO WITH EQUATION

We calculate the point from the center of the earth to the satellite and because we have the radius we can subtract it getting the distance from the satellite to the earth.

Task 2

Gears

Part A

Approximately 10.47 inches

Part B

300°

Part C

Approximately 125.66 inches

Part D

The distance traveled increases by approximately 62.83 inches

Task 3

Circle Theorems

Part A

PHOTO WITH LINE THROUGH CIRCLE AND ONE 90 DEGREE ANGLE

Part B

Prove OC is perpendicular to AB

We know that ΔAEC≅AED by SSS criteria (SSS criteria is when all three sides of a triangle is equal making them congruent)

To prove this that they apply to the SSS criteria: m∠ADO=m∠BDO m∠ADO=90°=m∠BDO

Part C

A radius is perpendicular to a chord when the chord is equally divided in half by the radius.

PHOTO OF LINE THROUGH CIRCLE AND LINE DISTANCES

Part D

Prove OC is perpendicular to AB

AO=BO because AO and BO are both radii

OD≅OD by reflexive theorem

ΔADO≅ΔBDO because they are both right triangle with the hypotenuse and a side

AB≅BC means that OC is perpendicular to AB

Part AConstruct a circle of any radius, and draw a chord on it. Then construct the radius of the circle
Part AConstruct a circle of any radius, and draw a chord on it. Then construct the radius of the circle
Part AConstruct a circle of any radius, and draw a chord on it. Then construct the radius of the circle
Part AConstruct a circle of any radius, and draw a chord on it. Then construct the radius of the circle

Disclaimer: The images to part A and part C is the same.

Two theorems we are proving are:

Line drawn from the center of the circle to bisect a chord is perpendicular to it.Perpendicular drawn from the center of the circle to a chord, bisects it.

How do we solve the given question?

Part A: The image is attached

Part B:

Let there be a circle with the center at O. Let AC be a chord. Let OE be a radius of the chord such that OE bisects AC at B, that is, AB = BC.

To prove: A line drawn from the center of the circle to bisect a chord is perpendicular to it.

Construction: We join OA and OB.

Proof:

In ΔOAB and ΔOCB,

OA = OC (Radius of the same circle)

AB = BC (Given, at B, the chord is bisected)

OB = OB (common side)

∴ ΔOAB ≅ ΔOCB [SSS axiom]

∴ ∠OBA = ∠OBC [Common parts of Congruent triangles]

Let ∠OBA = ∠OBC = x.

Since AC is a straight line,

∠OBA + ∠OBC = 180° [Linear pair]

or, x + x = 180°

or, 2x = 180°

or, x = 90°.

∴ ∠OBA = ∠OBC = 90°.

So, we can say that OB ⊥ AC, hence the theorem is proved.

Part C: The image is attached

Part D:

Let there be a circle with the center at O. Let AC be a chord. Let OE be a radius of the chord such that OE is perpendicular to AC at B, that is, AB ⊥ BC.

To prove: A line drawn from the center of the circle perpendicular to the chord bisects it.

Construction: We join OA and OB.

Proof:

In ΔOAB and ΔOCB,

OA = OC (Radius of the same circle)

∠OBA = ∠OBC = 90° (∵ OB ⊥ AC)

OB = OB (common side)

∴ ΔOAB ≅ ΔOCB [RHS axiom]

∴ AB = AC [Common parts of Congruent triangles]

So, we can say that OE perpendicular to the chord AC bisects it, hence the theorem is proved.

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Part AConstruct a circle of any radius, and draw a chord on it. Then construct the radius of the circle

a circle with radius of 5cm sits inside a 11cm×11cm rectangle

Answers

Answer:

The area of the shaded region is

Step-by-step explanation:

a circle with radius of 5cm sits inside a 11cm11cm rectangle

On a​ map, 1 inch equals 20 miles. Two cities are 6 inches apart on the map. What is the actual distance between the​ cities?

Answers

Answer:

idk

Step-by-step explanation:

idk just responding

for points

Answer:

120 miles

Step-by-step explanation:

If 1 inch = 20 miles, you can multiply both sides by 6 to figure out how many miles 6 inches represent.

Prove the theorem.

Reflexive Property of Congruence (Theorem 2.2)

Answers

The Reflexive Property of Congruence states that any geometric figure or object is congruent to itself.

The Reflexive Property of Congruence is a fundamental property in geometry that states that any geometric figure or object is congruent to itself. In other words, every geometric shape is congruent to itself. This property is based on the concept of congruence, which means that two figures have the same size and shape.

To prove the Reflexive Property of Congruence, we consider a generic geometric figure or object. Let's denote it as figure A. By definition, congruence means that two figures have the same size and shape. In this case, we are comparing figure A to itself. Since figure A is the same as itself, it is evident that the two figures have the same size and shape, and therefore, they are congruent.

The Reflexive Property of Congruence is an essential concept used in various geometric proofs and constructions. It serves as a foundation for establishing congruence relationships between different figures. By recognizing that any figure is congruent to itself, we can make deductions and draw conclusions in geometric reasoning.

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bonjour help me please je ny arrive pas ..merci​

bonjour help me please je ny arrive pas ..merci

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If my translation is correct and if I have understood the question correctly, then this answer should be correct.

Hope it helps!!

bonjour help me please je ny arrive pas ..merci

Determine the intercepts of the line,
2x + 5y = -6
y-intercept:
x-intercept:(

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Answer:

x=-3  , y= -6/5 or y= -1 1/5 or y= -1.2

Step-by-step explanation:

x-intercept:                 y-intercept:

2x+5y= -6                     2x+5y= -6

2x+5×0= -6                  2×0+5y= -6

2x+0= -6                      y= -6/5

2x= -6                          Alternative form of solution would be:

x=-3                                 y= -1 1/5 or y= -1.2

a bag contains 4 red marbles and 3 blue marbles. Another bag contains 7 green marbles and 6 yellow marbles. You randomly pick one marble from each bag. One marble is blue and second marble is yellow.

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Answer: 18/91 or ≈ 0.2

Step-by-step explanation:

Bag one: 4 red + 3 blue = 7 total

Bag two: 7 green + 6 yellow = 13 total

probability of picking blue from first bag: 3/7

probability of picking yellow from second bag: 6/13

3/7*6/13 = 18/91 or about 0.2 chance

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