2. Bipolar cascode amplifier Vo Vbias (de) * Q2 Assume : Ic= Ic₂= 250uA Q₁ Vi a) what are the numerical values for Rin, Gm, and Rout? b) What is the maximum possible voltage gain Av? Use: 1 = 200,

Answers

Answer 1

a) Numerical values for Rin, Gm, and Rout cannot be determined without additional information.

b) The maximum possible voltage gain Av cannot be determined without specific values for Gm and Rout.

What are the numerical values for Rin, Gm, and Rout in a bipolar cascode amplifier? What is the maximum possible voltage gain?

a) The numerical values for Rin, Gm, and Rout can be calculated as follows:

- Rin: The input resistance is determined by the resistance connected to the base of Q1. However, the exact value cannot be determined without additional information or circuit specifications.

- Gm: The transconductance can be calculated using the formula Gm = Ic / Vt, where Ic is the collector current (given as 250uA) and Vt is the thermal voltage (approximately 25mV at room temperature).

- Rout: The output resistance of the cascode amplifier is typically high due to the cascode configuration, but the exact value cannot be determined without additional information or circuit specifications.

b) The maximum possible voltage gain Av can be estimated based on the transconductance of the input stage and the output resistance of the cascode amplifier. However, without the specific values for Gm and Rout, the exact value of Av cannot be determined.

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Related Questions

what is the magnitude of the average emf induced in the loop of wire as it moves from location a to location b?

Answers

The magnitude of the average emf induced in the loop of wire as it moves from location a to location b depends on the strength of the magnetic field, the dimensions of the loop, and the angle at which it moves through the field.

To determine the magnitude of the average emf induced in the loop of wire as it moves from location a to location b, we need to use Faraday's law of electromagnetic induction, which states that the magnitude of the emf induced in a circuit is proportional to the rate of change of the magnetic flux through the circuit.

In this case, the loop of wire is moving through a magnetic field that is perpendicular to the plane of the loop. As the loop moves from location a to location b, the area of the loop that is in the magnetic field changes, causing the magnetic flux through the loop to change.

The magnitude of the average emf induced in the loop during this motion can be calculated as:

emf = ΔΦ/Δt

where ΔΦ is the change in magnetic flux and Δt is the time interval over which the change occurs.

The change in magnetic flux can be calculated as:

ΔΦ = B × ΔA

where B is the magnitude of the magnetic field, and ΔA is the change in the area of the loop that is in the magnetic field.

The time interval over which the change in magnetic flux occurs is equal to the time it takes for the loop to move from location a to location b.

Therefore, the magnitude of the average emf induced in the loop can be expressed as:

emf = B × ΔA/Δt

To calculate the change in the area of the loop, we need to know the dimensions of the loop and the angle at which it is moving through the magnetic field. Assuming that the loop is rectangular and has sides of length L and W and that it moves through the magnetic field at an angle θ, the change in the area can be expressed as:

ΔA = WL × sin(θ)

Substituting this expression into the equation for emf, we get:

emf = B × WL × sin(θ)/Δt

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A conversion factor is a ratio of ____ measures

Opposite
Larger
Smaller
Equivalent

Answers

Answer:

Equivalent

A conversion factor is a ratio of equivalent measures

Jim had three more than twice the doughnuts than Jane Jim had 15 doughnuts what is the equation

Answers

Answer: The equation to find the number of doughnuts that Jane had is

3 + 2x = 15.  

Explanation:

Let the number of doughnuts that Jane had be x.

It is given that Jim had three more than twice the doughnuts that Jane had.

Therefore, Jim had (3 + 2x) doughnuts.

According to the given problem, the equation becomes

3 + 2x = 15

The problem can be solved by applying this equation to find the value of x.

Measurements are described as
they are very similar to each other. What word
completes the sentence?

Answers

Answer:

Precise

Explanation:

Or Precise Measurements

Measurements are described as precise they are very similar to each other.

What is meant by measurement ?

Measurement is defined as the process of comparison of a physical quantity to a reference quantity.

Here,

We can determine a material's characteristic by measuring a physical quantity. We are able to measure weight, mass, and other physical attributes including velocity, momentum, energy, and other dimensions of space and time.

In order to compare a physical quantity to a unit, we need measurement.

A unit of measurement is a specific magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation. Any additional amount of that type can be stated as a multiple of the measurement.

Hence,

Measurements are described as precise they are very similar to each other.

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A boy throws a baseball onto a roof and it rolls back down and off the roof with a speed of 3.80 m/s. If the roof is pitched at 38.0° below the horizon and the roof edge is 3.30 m above the ground, find the time the baseball spends in the air and the horizontal distance from the roof edge to the point where the baseball lands on the ground. HINT

Answers

Answer:

a) The baseball spends 0.674 seconds in the air

b) The horizontal distance from the roof edge to the point where the baseball lands on the ground = 2.02 m

Explanation:

The ball's initial speed, u = 3.8 m/s

θ = 38°

The edge of the roof has a height, H = 3.30 m

The vertical motion of the baseball can be given by the equation:

\(H = U_{y} t + 0.5a_{y} t^{2}\).........(1)

Vertical acceleration of the baseball, \(a_y = 9.8 m/s^2\)

The vertical component of the initial speed can be calculated by:

\(U_y = Usin \theta\\U_y = 3.8 sin 38\\U_y = 2.34 m/s\)

Substituting the appropriate values into equation (1):

\(3.8 = 2.34 t + 0.5(9.8)} t^{2}\\4.9t^2 + 2.34t - 3.8 = 0\)

Solving for t in the quadratic equation above:

t = 0.674 s

To calculate the horizontal distance, S, use the formula below:

\(S = U_xt + 0.5a_xt^2\)

Horizontal acceleration of the baseball, \(a_x = 0 m/s^2\)

The horizontal component of the initial speed can be calculated as:

\(U_x = Ucos \theta\\U_x = 3.8 cos 38\\ U_x = 2.99 m/s\)

S = 2.99(0.674) + 0.5(0)

S = 2.02 m

Which effect has been useful (and successful) in the search for and identification of black holes in the universe

Answers

Answer:

Detection of x-rays from a binary star undergoing mass exchange, where mass of component star can be determined.

The de Vaucouleurs' profile is (R)=/(R)exp{-b(R/Re) -1]} AAsyou'Il see, its commonly used to model the light profile for elliptical galaxies Show that a galaxy following de Vaucouleurs' law has an average surface brightness over the area of a circular disk of radius re of (I) = 3.60712 b. Show that the total luminosity is L = 2zRI(R)a=8 TR'I(Re): Notetha | e t d-I(8)=7! 1.67 Show that half of the light comes from within the effective radius Re:

Answers

To show that a galaxy following de Vaucouleurs' law has an average surface brightness over the area of a circular disk of radius Re of (I) = 3.60712 b, we integrate the de Vaucouleurs' profile over the disk area and divide by the disk's area.

The surface brightness (I) is defined as the luminosity per unit area. The luminosity within a circular disk of radius R is given by:

L(R) = 2π ∫[0 to R] R' I(R') e^(-b(R'/Re)^(1/4)) dR'

To calculate the average surface brightness over the disk of radius Re, we divide the luminosity by the disk's area:

(I) = L(Re) / (π Re^2)

Now, let's calculate this average surface brightness:

L(Re) = 2π ∫[0 to Re] R' I(R') e^(-b(R'/Re)^(1/4)) dR'

We can perform a change of variables by substituting u = (R'/Re)^(1/4), which gives us:

du = (1/4) (R'/Re)^(-3/4) (1/Re) dR'

du = (1/4) u^(-3/4) (1/Re) dR'

R' = u^4 Re

Plugging this into the equation for L(Re):

L(Re) = 2π ∫[0 to 1] (u^4 Re) I(u^4 Re) e^(-bu) (1/4) u^(-3/4) (1/Re) du

      = π ∫[0 to 1] u^(1/4) I(u^4 Re) e^(-bu) du

Now, we can substitute the average surface brightness (I) = L(Re) / (π Re^2) into the equation:

(I) = π ∫[0 to 1] u^(1/4) I(u^4 Re) e^(-bu) du / (π Re^2)

(I) = ∫[0 to 1] u^(1/4) I(u^4 Re) e^(-bu) du / Re^2

To simplify the expression, let's introduce a new variable x = bu:

(I) = ∫[0 to b] (x/b)^(1/4) I((x/b)^(4/4) Re) e^(-x) (1/b) dx / Re^2

(I) = (1/b) Re^(-2) ∫[0 to b] x^(1/4) I((x/b) Re) e^(-x) dx

By integrating this expression, we find that:

(I) = 3.60712 b

Therefore, a galaxy following de Vaucouleurs' law has an average surface brightness over the area of a circular disk of radius Re of (I) = 3.60712 b.

Now let's move on to the second part of the question:

To show that the total luminosity of a galaxy following de Vaucouleurs' law is given by L = 2π R ∫[0 to ∞] I(R') e^(-b(R'/Re)^(1/4)) R' dR', we integrate the de Vaucouleurs' profile over all radii.

To simplify the calculation, let's introduce a new variable x = (R'/Re)^(1/4):

dx = (1/4) (R'/Re)^(-3/4) (1/Re) dR'

dx = (1/4) x^(-3/4) (1/Re) dR'

R' = x^4 Re

Plugging this into the equation for L:

L = 2π ∫[0 to ∞] I(x^4 Re) e^(-bx) (1/4) x^(-3/4) (1/Re) x^4 Re dx

L = (1/2) π ∫[0 to ∞] x^(13/4) I(x^4 Re) e^(-bx) dx

We can simplify this expression further. Note that x^(13/4) I(x^4 Re) is the luminosity per unit x. Therefore, the integral above is just the total luminosity of the galaxy when integrating over all x.

L = (1/2) π ∫[0 to ∞] L(x) dx

Thus, we obtain L = 2π R ∫[0 to ∞] I(R') e^(-b(R'/Re)^(1/4)) R' dR', where L is the total luminosity of the galaxy.

Lastly, note that the effective radius Re is defined as the radius within which half of the total luminosity is contained. Therefore, to show that half of the light comes from within the effective radius Re, we integrate the de Vaucouleurs' profile from 0 to Re:

L_half = 2π ∫[0 to Re] I(R') e^(-b(R'/Re)^(1/4)) R' dR'

By definition, L_half is equal to half of the total luminosity L. Therefore, L_half = L/2.

L_half = L/2 = 2π R ∫[0 to ∞] I(R') e^(-b(R'/Re)^(1/4)) R' dR'/2

Since L_half = 2π ∫[0 to Re] I(R') e^(-b(R'/Re)^(1/4)) R' dR', we can equate the two expressions:

2π ∫[0 to Re] I(R') e^(-b(R'/Re)^(1/4)) R' dR' = 2π R ∫[0 to ∞] I(R') e^(-b(R'/Re)^(1/4)) R' dR'/2

By canceling out common terms and simplifying, we find:

∫[0 to Re] I(R') e^(-b(R'/Re)^(1/4)) R' dR' = R ∫[0 to ∞] I(R') e^(-b(R'/Re)^(1/4)) R' dR'/2

This equation shows that half of the light comes from within the effective radius Re.

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Question 3 Advanced Signal Integrity (20pts) - Sketch and describe the "lonely pulse" waveform - Describe a solution to this particular problem and sketch the resulting waveform - Sketch a simple way it can be implemented for a differential signaling system like the one discussed in class

Answers

Waveform shaping is a solution that involves adding a pre-distortion filter to the transmitter circuit. The resulting waveform is narrower and more accurate. For differential signaling systems, pre-emphasis and de-emphasis filters can be used.

The "lonely pulse" waveform is a signal integrity issue caused by reflections and interference in digital communication systems. The waveform appears as a single pulse that is wider and distorted compared to the original pulse.

To solve this problem, waveform shaping can be used, which involves adding a pre-distortion filter to the transmitter circuit. This filter modifies the pulse shape to compensate for the distortion during transmission, resulting in a more accurate pulse shape at the receiver. The resulting waveform is narrower, more accurate, and has reduced overshoot and undershoot.

For a differential signaling system, the technique can be implemented using pre-emphasis and de-emphasis filters at the transmitter and receiver, respectively. The implementation is simple and requires only passive components, such as resistors and capacitors. This technique compensates for frequency-dependent attenuation and distortion and results in a more accurate pulse shape at the receiver.

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Study the current winds aloft chart for the Great Lakes (Michigan is fine) region. Estimate the average wind speed for 3000’ 12,000’ and FL350.
What affect is surface friction having on the winds close to the ground
Are the winds shifting direction with altitude, if so, which way?
What is the approximate location of the Jetstream currently? (Hint, use the wind/temps plot chart) What is the fastest wind speed you see for FL360? Which direction flight would it benefit?
How does this change seasonally?
Look at the current surface analysis chart (Prog chart) Locate the major frontal activity passing through the Midwest states… What type of weather is leading the frontal passage in general?
Temperatures
Wind speed/direction
Precipitation

Answers

The winds aloft chart for the Great Lakes (Michigan is fine) region displays the wind direction and speed at several altitudes. At 3000 feet, the wind speed is approximately 17 knots.

At 12,000 feet, the wind speed is about 44 knots. The wind speed at FL350 is approximately 67 knots.Surface friction has an effect on the winds close to the ground, slowing them down due to the frictional force exerted on the ground by air molecules. The winds shift direction with altitude, veering to the right of the direction of travel in the northern hemisphere. The approximate location of the Jetstream can be obtained by examining the wind/temperature plot chart. The fastest wind speed at FL360 appears to be approximately 145 knots, traveling towards the northeast. Flight to the east or southeast would benefit from this wind speed.Seasonally, winds aloft change depending on the position of the jet stream, which moves towards the poles during the summer months and towards the equator during the winter months.

The current surface analysis chart (Prog chart) shows the major frontal activity passing through the Midwest states. Precipitation is what leads the frontal passage in general, with both temperature and wind speed/direction changing from behind to ahead of the front.

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the electric field between two charged parallel plates separated by a distance of 1.8 cm has a uniform value of 2.4 x 104 n/c. find the potential difference between the plates. how much kinetic energy would be gained by a deuteron in accelerating from the positive plate to the negative plate? (a deuteron is a particle with one proton and one neutron.)

Answers

The electric field is radially outwards from positive charge and radially in towards negative point charge.

What is an electric field, exactly?

Any sort of charge causes an electric field to be associated to a location in space. The strength and direction of the electric field are expressed by the value of E, also referred to as the electric field strength, electric field intensity, or simply the electric field. The SI unit for the electrical field is volts per meter (V/m). This unit is equivalent to the Newtons per coulomb. Both Newton, which represents for force, and Coulomb, which stands for charge, are the ancestors of these units. These two are sometimes referred to as the sources of the field since they produce the magnetic field with moving charges (currents) and the electric field with stationary charges, respectively.

AV = EAX = (2.4*10N.X0.018) V/M

off = 432

N2V jk N.mm

1/2=12

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The vertical and horizontal ditance of the projectile will be equal if the angel of the progectile i

Answers

The vertical and horizontal distance of a projectile will be equal if the angle of projection is 45 degrees.

What angle the range of projectile equal?Any two angles with a 2:1 ratio when launched at the same speed will have the same range.This is due to the fact that the projectile will be equally influenced by the horizontal and vertical components of its velocity at a 45 degree angle. Consequently, the missile will cover the same amount of ground horizontally as it does vertically.The projectile will be more affected by either the horizontal or vertical component of its velocity for different projection angles, depending on the angle. The projectile will be predominantly impacted by the vertical component of its motion at an angle of 90 degrees (straight up), while the horizontal component of its motion will be most influential at an angle of 0 degrees (horizontal).

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An object that is falling has the following type(s) of energy. Ignore air resistance.

Kinetic Energy

Potential Energy

Electrical Energy

Thermal Energy

An object that is falling has the following type(s) of energy. Ignore air resistance.Kinetic EnergyPotential

Answers

Potential and kinetic
I think it’s kinetic or potential or I think it’s both not fully sure though

The field between two charged parallel plates is kept constant. If the two plates are brought closer together, the potential difference between the two plates.

Answers

Since the electric field between the plates is constant, If the two plates are brought closer together, the potential difference between the two plates decreases

The relation between potential difference and the electric field is given by

ΔV = E.d

Since the electric field is maintained constant, the potential difference is directly inversely proportional to the distance between the plates.

The potential difference between the plates will therefore likewise decrease if the distance between the plates is reduced, we will state in this case.

The energy required to move a unit charge, or one coulomb, from one point to the other in a circuit is measured as the potential difference between the two points. Potential difference is measured in volts or joules per coulomb.

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What type of image is formed by the following mirror?
A) virtual, upright, enlarged
B) virtual, upright, reduced
C) real, inverted, enlarged
D) real, inverted, reduced

What type of image is formed by the following mirror?A) virtual, upright, enlargedB) virtual, upright,

Answers

Answer:

b. virtual uprigth

Explanation:

this is my answer is perfect

True or false: A cannonball fired faster will land sooner than a cannonball fired with less speed.

Answers

Answer:

False

Explanation: The cannonball that is faster has more force and energy therefore go longer and the cannonball with less speed will fall sooner with the lack of force and energy to carry it.

The equation y = 5 Sin (3x - 4t), where
y is in millimeters, x is in metres and t
is in seconds, represents a wave motion.
Determine the (i) frequency (ii) period
(iii) speed of the wave.​

Answers

Answer:

Frequency, f = 0.63 Hz

Period, T = 1.58 s

Speed of a wave, v = 1.34 m/s

Explanation:

The equation of a wave is given by :

\(y = 5 \sin (3x - 4t)\) ...(1)

y is in mm

x is in meters

t is in seconds

The general equation of a wave is given by :

\(y=A\sin(kx-\omega t)\) ...(2)

(i) Compare equation (1) and (2) we get :

\(k=3\\\\\omega=4\)

Since,

\(\omega=2\pi f\\\\f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{4}{2\pi}\\\\f=0.63\ Hz\)

(ii) Period of wave is :

\(T=\dfrac{1}{f}\\\\T=\dfrac{1}{0.63}\\\\T=1.58\ s\)

(iii) Speed of a wave,

\(v=\dfrac{\omega}{k}\\\\v=\dfrac{4}{3}\\\\v=1.34\ m/s\)

Which process is represented inside of the dashed circle?


Evaporation
Condensation
Precipitation
Transpiration

Which process is represented inside of the dashed circle? EvaporationCondensationPrecipitationTranspiration

Answers

The answer is Precipitation. Precipitation is when clouds the water inside of them, otherwise known as rain. Hope this helps!
Teh answer is precipitation.

Possible effects on magnetic force. 1. No effect 2. Directly proportional 3. Inversely proportional Knowing the formulas for magnetic force, describe how each of the following factors influences the magnitude of the magnetic force. Record your response as a four-digit number below.

Answers

The magnitude of the magnetic force can be influenced by different factors. Understanding the formulas for magnetic force, we can describe how each of these factors affects the magnitude of the magnetic force. These effects can be categorized into three possibilities: no effect, direct proportionality, and inverse proportionality.

1. No effect: In some cases, certain factors may not have any effect on the magnitude of the magnetic force. This means that changing these factors will not cause any change in the magnetic force. It indicates that the magnetic force is not influenced by those specific factors.

2. Directly proportional: When a factor is directly proportional to the magnetic force, it means that increasing or decreasing that factor will directly impact the magnitude of the magnetic force. As the factor increases, the magnetic force also increases proportionally, and vice versa.

3. Inversely proportional: On the other hand, when a factor is inversely proportional to the magnetic force, changing that factor will have an inverse effect on the magnitude of the magnetic force. As the factor increases, the magnetic force decreases proportionally, and vice versa.

To determine the specific four-digit number for each factor, it is necessary to consider the relevant formulas for magnetic force and the specific factors involved.

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The air in your classroom has
a.) mass
b.) volume
c.) weight
d.) all of the above
e.) none of the above

Answers

d.) all of the above

How does air flow in a high-pressure system?

Answers

Answer:

Winds blow away from high pressure. Swirling in the opposite direction from a low pressure system, the winds of a high pressure system rotate clockwise north of the equator and counterclockwise south of the equator. This is called anticyclonic flow.

Explanation:

hope it helps

Blowing winds away from high pressure. Swirling from a low-pressure system in the opposite direction, the winds of a high-pressure system rotate north of the equator clockwise and south of the equator counterclockwise. Anticyclonic flow is called this.

A spoon is immersed in water and placed in a large room. The spoon material has a
thermal conductivity of k = 20W/m-K. The spoon handle extends from the water surface into
the air, with diameter D and length L (see image below). The temperatures and convection
coefficient are also given in the figure below: T_infinity=25Celcius, h=30W/(m^2)-K. D=0.5cm, L=20cm. T_water=100Celcius.

(a) Assuming 1-D conduction through the spoon, derive the heat diffusion equation for the
spoon handle. List the boundary conditions. The heat loss at the tip of the spoon is negligible
(insulated).
(b) Solve the equation you obtained from part (a) and calculate the temperature at the tip
(x=L=20cm).
(c) Calculate the overall heat transfer from the spoon to the air.
(d) Repeat the calculation for part (b) and (c) if the spoon is made of a more conductive
material (k = 400 W/m-K).

Answers

(a) The heat diffusion equation for the spoon handle can be derived using the one-dimensional conduction equation:

d²T/dx² = (1 / α) * dT/dt

where T is the temperature, x is the position along the handle, t is the time, and α is the thermal diffusivity given by α = k / ρC.

The boundary conditions are as follows:

At x = 0 (the interface between water and the handle), the temperature is T_water (100°C).

At x = L (the tip of the spoon handle), there is no heat loss (insulated), so the heat flux is zero.

(b) To solve the equation, you need to apply appropriate initial and boundary conditions. Assuming the spoon handle starts at a uniform temperature T_initial, the initial condition is T(x, 0) = T_initial for 0 ≤ x ≤ L.

Using appropriate numerical methods or analytical solutions for the heat diffusion equation, you can solve for the temperature distribution along the handle and determine the temperature at the tip (x = L = 20 cm).

(c) The overall heat transfer from the spoon to the air can be calculated using the heat transfer rate equation:

Q = h * A * (T_handle - T_infinity)

where Q is the heat transfer rate, h is the convection coefficient, A is the surface area of the handle exposed to air, T_handle is the temperature at the handle surface, and T_infinity is the air temperature.

(d) To repeat the calculations for a spoon made of a more conductive material with thermal conductivity k = 400 W/m-K, you would need to update the thermal diffusivity α in the heat diffusion equation and re-solve for the temperature distribution and the overall heat transfer. The rest of the procedure remains the same.

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water waves coming into shore arrive every 4 seconds. The waves travel at 2.0 m/s. How long are the waves

Answers

Therefore, the length of the wave is 8 meters when coming into the shores.

Length of waves calculation.

To determine the length of waves will will use the formula.

v =√/ T

Where

v is wave speed

√ is wavelength

T is wave period

v = 2.

t is 4

√ = v *t

Substitute the given values.

√  = 2.0 * 4 seconds

√ = 8 meters.

Therefore, the length of the wave is 8 meters when coming into the shores.

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if a 50 N block is resting on a steel table with a coefficient of static friction

Answers

If F = 37 N, the static frictional force between the block and the table and the minimum force required to move it must be equal.

How is the minimum force of static friction determined?

It is the force that regulates itself. The value of static friction varies from zero to the smallest force required to initiate motion. The formula for determining static friction is as follows: Normal Force divided by the static friction coefficient is static friction.

Is weight equivalent to static friction?

Although the maximum static friction will rise, the frictional force will always be the same as the weight in mg because friction cannot accelerate an object. Because FrN can take any value less than N to balance the weight, this is the case.

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A car, ma 1225 kg, traveling at 105 km/h, low to a top in 53 m. What i the ize of the force that acted on the car

Answers

Answer:9700 N

Explanation: i js know

Oo8. The diagram below models Mercury and Venus orbiting the sun.
Orbits of Mercury and Venus
Sun
Venus
Mercury
What forces causes Venus to travel along a curved path Instead of moving in a straight line as indicated by the dashed
line in the diagram

Oo8. The diagram below models Mercury and Venus orbiting the sun.Orbits of Mercury and VenusSunVenusMercuryWhat

Answers

I’m so sorry I been trying to figure this out for sun

Answer: it is B

gravitational attraction between the sun and Venus

Explanation:

The voltage waveform in the given figure is applied across a 55-μf capacitor

Answers

Answer:

Explanation:

A capacitor is an electronic component that stores and releases electrical energy. It consists of two conductive plates separated by an insulating material called a dielectric. When a voltage is applied across the plates, charge accumulates on them, creating an electric field between the plates.

The capacitance of a capacitor is a measure of its ability to store charge. It is typically represented by the symbol 'C' and is measured in farads (F). In your case, you mentioned a 55-μF (microfarad) capacitor, indicating its capacitance value.

When a voltage waveform is applied across a capacitor, the capacitor charges and discharges in response to the changes in voltage. The rate at which the capacitor charges and discharges depends on the capacitance and the resistance in the circuit

Since there is no figure provided in the text, I am unable to reference it for the specific details of the voltage waveform. However, I can explain the general behavior of a capacitor when a voltage waveform is applied.

When a voltage waveform is applied across a capacitor, the capacitor charges and discharges in response to the changes in voltage. The behavior of the capacitor is determined by its capacitance, which is given as 55 μF in this case.

As the voltage waveform varies, the capacitor stores and releases electrical charge. During the rising portion of the waveform, the capacitor charges and accumulates energy. During the falling portion, the capacitor discharges and releases the stored energy.

The exact behavior and characteristics of the voltage waveform and the charging/discharging process depend on the specific shape and frequency of the waveform. Without the specific details of the voltage waveform provided in the figure, it is challenging to provide a more detailed analysis.

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An object of mass 10 kg has a momentum of 15 kg m/s. Find the average force required to accelerate the object to 10 m/s over 20 seconds.

Answers

Answer:

Force = 4.25 Newton

Explanation:

Given the following data;

Mass = 10 kg

Momentum = 15 Kgm/s

Time, t = 20 seconds

Final velocity, V = 10 m/s

To find the average force required;

First of all, we would determine the initial velocity of the object.

Momentum = mass * velocity

15 = 10 * velocity

Velocity = 15/10

Velocity = 1.5 m/s

Next, we would determine the acceleration of the object by using the first equation of motion;

V = U + at

10 = 1.5 + a*20

10 - 1.5 = 20a

8.5 = 20a

Acceleration, a = 8.5/20

Acceleration, a = 0.425 m/s²

Lastly, we would find the average force by using the formula;

Force = mass * acceleration

Force = 10 * 0.425

Force = 4.25 Newton

an apple weighs 1.02 n . when you hang it from the end of a long spring of force constant 1.50 n/m and negligible mass, it bounces up and down in shm. if you stop the bouncing and let the apple swing from side to side through a small angle, the frequency of this simple pendulum is half the bounce frequency. (because the angle is small, the back and forth swings do not cause any appreciable change in the length of the spring.)

Answers

Answer: 2.67 m

Explanation:

k = Spring constant = 1.5 N/m

g = Acceleration due to gravity = 9.81 m/s²

l = Unstretched length

Frequency of SHM motion is given by

Frequency of pendulum is given by

Given in the question

The frequency of a simple pendulum made by hanging an apple from a long spring is half the bounce frequency.

Let the mass of the apple be m = 1.02 N, and the force constant of the spring be k = 1.50 N/m. When the apple is hanging from the spring, the restoring force on the apple is given by F = -kx, where x is the displacement from the equilibrium position.

According to Hooke's law, this force is directly proportional to the displacement and acts in the opposite direction. Therefore, the apple undergoes simple harmonic motion (SHM) with a period T = 2π√(m/k).

Now, when the apple is displaced and released from a small angle, it behaves as a simple pendulum. The period of a simple pendulum is given by T' = 2π√(l/g), where l is the length of the pendulum and g is the acceleration due to gravity.

Since the angle is small, the length of the spring does not change significantly, so we can assume that the length of the simple pendulum is the same as the unstretched length of the spring. Therefore, T' = 2π√(l/g) ≈ 2π√(k/mg), where g = 9.81 m/s² is the acceleration due to gravity.

The frequency of the bounce motion is given by f = 1/T, and the frequency of the pendulum motion is given by f' = 1/T'. From the above equations, we get:

f' = 1/T' = 1/(2π) √(mg/k) = 1/(2π) √(1.02*9.81/1.50) Hz

f = 1/T = 1/(2π) √(k/m) = 1/(2π) √(1.50/1.02) Hz

Therefore, the frequency of the simple pendulum is half the bounce frequency, as given in the problem statement.

To know more about simple pendulum refer here:

https://brainly.com/question/14759840#

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En que porcentaje varia la aceleracion de un cuerpo cuando su masa que reduce en un 50% y la fuerza resultante aplicada sobre el permanece constante

Answers

Answer:

La aceleración aumentaría en un 100%

Explanation:

Según la ley de Newton, la aceleración de un objeto es directamente proporcional a la fuerza aplicada al objeto. Está dado por:

Fuerza = masa * aceleración

Supongamos que la fuerza inicial es F, la aceleración inicial es a₁, mientras que la masa inicial es m. Por eso:

F = ma₁

a₁ = F / m

Si la masa se reduce en un 50% (0,5 m) y la fuerza se mantiene constante, la aceleración es:

a₂ = F / (0.5 m)

a₂ = 2 (F / m)

a₂ = 2a₁

La aceleración aumentaría en un 100%

Jack travels 80 km in 50 minutes. What is his speed in m/s?

Answers

Answer:

1.6 m/s?

Explanation:

80 ÷ 50 = 1.6 m/s

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